By plush - 7/21/2015
Dear friends, I'm sure my question has been answered before somewhere, however I did not manage to find the answer.
What I would like to do, is use the response latencies provided in a first block, as the presentation times for a stimuli in a second block.
Is there an efficient way to do this? Thx for the help!
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By Dave - 7/21/2015
Yes, you can do that. You need to store the latency / latencies (or mean latency?) from the 1st block somewhere. You can then set the stimulus duration in the 2nd block via the <trial> element's setstimulustime() function. Simple example:
<expt>
/ blocks = [1=block1; 2=block2]
</expt>
<values>
/ alatency= 0
</values>
<block block1>
/ trials = [1=atrial]
</block>
<block block2>
/ trials = [1=btrial]
</block>
<trial atrial>
/ ontrialend = [values.alatency=trial.atrial.latency]
/ stimulusframes = [1=atext]
/ validresponse = (57)
</trial>
<trial btrial>
/ ontrialbegin = [trial.btrial.setstimulustime(shape.eraser, values.alatency); ]
/ stimulusframes = [1=btext]
/ validresponse = (57)
</trial>
<text atext>
/ items = ("Press the spacebar")
</text>
<text btext>
/ items = ("This stimulus will disappear after <%values.alatency%> milliseconds.")
</text>
<shape eraser>
/ shape = rectangle
/ color = white
/ size = (100%, 25%)
</shape>
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By plush - 7/22/2015
Thx for the response as always! I was hoping for something along the following lines to work:
<values>
/ one_trialslatency=0
</values>
<expt >
/blocks = [1=one;2=two]
</expt>
<block one>
/trials = [1-5=one_trials]
</block>
<block two>
/trials = [1-5=two_trials]
</block>
<trial one_trials>
/stimulustimes = [1=press]
/validresponse = (" ")
/ ontrialend = [values.one_trialslatency=trial.one_trials.latency]
</trial>
<trial two_trials>
/stimulustimes = [1=fixationcross]
/ timeout = values.one_trialslatency
</trial>
<text fixationcross>
/items = (" + ")
</text>
<text press>
/items = (" press the spacebar ")
</text>
The big question is whether I can save somehow 5 latencies, as timeouts for 5 trials in the second block. As it is currently designed it only uses the latency of the last trial.
Thx!
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By Dave - 7/22/2015
You can absolutely store several latencies and use them later on. You can use a <list> for that:
<expt >
/blocks = [1=one;2=two]
</expt>
<block one>
/trials = [1-5=one_trials]
</block>
<block two>
/trials = [1-5=two_trials]
</block>
<trial one_trials>
/stimulustimes = [1=press]
/validresponse = (" ")
/ ontrialend = [list.latencylist.appenditem(trial.one_trials.latency)]
</trial>
<list latencylist>
/ selectionmode = sequence
</list>
<trial two_trials>
/stimulustimes = [1=fixationcross]
/ timeout = list.latencylist.nextvalue
</trial>
<text fixationcross>
/items = (" + ")
</text>
<text press>
/items = (" press the spacebar ")
</text>
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By plush - 7/22/2015
Works great! Thx for the quick replies!
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