By Nathalia Melo - 2/10/2019
I'm trying to create an IAT with a specific number of times each word appears in the blocks. There are 8 words per category and 4 categories. I need each word to appear once in compatibletest1, totalizing 32 trials, and twice in compatibletest2, totalizing 64 trials. I need incompatible blocks with the same patern. Words should be selected randomly, but there must be a rule that indicates how many times they will appear. Does anyone know how to program this?
Thanks, Nathalia
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By Dave - 2/10/2019
+xI'm trying to create an IAT with a specific number of times each word appears in the blocks. There are 8 words per category and 4 categories. I need each word to appear once in compatibletest1, totalizing 32 trials, and twice in compatibletest2, totalizing 64 trials. I need incompatible blocks with the same patern. Words should be selected randomly, but there must be a rule that indicates how many times they will appear. Does anyone know how to program this?
Thanks, Nathalia
You need to adjust the amount of trials in the respective <block> elements accordingly. Do so via the <block> elements' /trials attributes.
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By Nathalia Melo - 2/10/2019
+x+x[quote]I'm trying to create an IAT with a specific number of times each word appears in the blocks. There are 8 words per category and 4 categories. I need each word to appear once in compatibletest1, totalizing 32 trials, and twice in compatibletest2, totalizing 64 trials. I need incompatible blocks with the same patern. Words should be selected randomly, but there must be a rule that indicates how many times they will appear. Does anyone know how to program this?
Thanks, Nathalia
You need to adjust the amount of trials in the respective <block> elements accordingly. Do so via the <block> elements' /trials attributes. I've already done that, but I don't know how to program the number of times I want each word to appear (one in the first block and twice in the second). Would it be through selection mode? I've already tried all of them.
That's my syntax:
<block compatibletest1> / bgstim = (targetAleft, orleft, attributeAleftmixed, targetBright, orright, attributeBrightmixed) / trials = [1=instructions; 3,5,7,9,11,13,15,17,19,21,23,25,27,29,31= noreplacenorepeat(targetAleft, targetBright); 2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32 = noreplacenorepeat(attributeA, attributeB)]
block compatibletest2> / bgstim = (targetAleft, orleft, attributeAleftmixed, targetBright, orright, attributeBrightmixed) / trials = [ 2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40,42,44,46,48,50,52,54,56,58,60,62,64 = noreplacenorepeat(targetAleft, targetAleft, targetBright, targetBright); 1,3,5,7,9,11,13,15,17,19,21,23,25,27,29,31,33,35,37,39,41,43,45,47,49,51,53,55,57,59,61,63 = noreplacenorepeat(attributeA, attributeA, attributeB, attributeB)]
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By Dave - 2/11/2019
+x+x+x[quote]I'm trying to create an IAT with a specific number of times each word appears in the blocks. There are 8 words per category and 4 categories. I need each word to appear once in compatibletest1, totalizing 32 trials, and twice in compatibletest2, totalizing 64 trials. I need incompatible blocks with the same patern. Words should be selected randomly, but there must be a rule that indicates how many times they will appear. Does anyone know how to program this?
Thanks, Nathalia
You need to adjust the amount of trials in the respective <block> elements accordingly. Do so via the <block> elements' /trials attributes. I've already done that, but I don't know how to program the number of times I want each word to appear (one in the first block and twice in the second). Would it be through selection mode? I've already tried all of them. That's my syntax: <block compatibletest1> / bgstim = (targetAleft, orleft, attributeAleftmixed, targetBright, orright, attributeBrightmixed) / trials = [1=instructions; 3,5,7,9,11,13,15,17,19,21,23,25,27,29,31= noreplacenorepeat(targetAleft, targetBright); 2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32 = noreplacenorepeat(attributeA, attributeB)] block compatibletest2> / bgstim = (targetAleft, orleft, attributeAleftmixed, targetBright, orright, attributeBrightmixed) / trials = [ 2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40,42,44,46,48,50,52,54,56,58,60,62,64 = noreplacenorepeat(targetAleft, targetAleft, targetBright, targetBright); 1,3,5,7,9,11,13,15,17,19,21,23,25,27,29,31,33,35,37,39,41,43,45,47,49,51,53,55,57,59,61,63 = noreplacenorepeat(attributeA, attributeA, attributeB, attributeB)] Let's take <block compatibletest1>. The items in your targetA, targetB, attributeA, and attributeB stimuli are sampled randomly without replacement. I.e., with 8 items per category, if you want each item to be sampled exactly once during the block, you need to run 8 targetAleft trials, 8 targetBright trials, 8 attributeA trials, and 8 attributeB trials. Your code doesn't do that, it runs too few targetAleft / targetBright trials. The code ought to read:
<block compatibletest1> / bgstim = (targetAleft, orleft, attributeAleftmixed, targetBright, orright, attributeBrightmixed) / trials = [1=instructions; 3,5,7,9,11,13,15,17,19,21,23,25,27,29,31,33= noreplacenorepeat(targetAleft, targetBright); 2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32 = noreplacenorepeat(attributeA, attributeB)] ... </block>
i.e. you want 16 target trials, with targetAleft and targetBright sampled in equal proportions, resulting in 8 trials each.
3,5,7,9,11,13,15,17,19,21,23,25,27,29,31,33= noreplacenorepeat(targetAleft, targetBright);
The same reasoning applies to <block compatibletest2>.
In addition, you can reset the various stimulus elements' selection pools at the start of the block.
<block compatibletest1> / onblockbegin = [text.attributea.resetselection(); text.attributeb.resetselection(); text.targeta.resetselection(); text.targetb.resetselection(); ] / bgstim = (targetAleft, orleft, attributeAleftmixed, targetBright, orright, attributeBrightmixed) / trials = [1=instructions; 3,5,7,9,11,13,15,17,19,21,23,25,27,29,31,33= noreplacenorepeat(targetAleft, targetBright); 2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32 = noreplacenorepeat(attributeA, attributeB)] ... </block>
That way you can guarantee that all 8 items are available and free to be sampled at the start of the block.
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By Nathalia Melo - 2/11/2019
+x+x+x+x[quote]I'm trying to create an IAT with a specific number of times each word appears in the blocks. There are 8 words per category and 4 categories. I need each word to appear once in compatibletest1, totalizing 32 trials, and twice in compatibletest2, totalizing 64 trials. I need incompatible blocks with the same patern. Words should be selected randomly, but there must be a rule that indicates how many times they will appear. Does anyone know how to program this?
Thanks, Nathalia
You need to adjust the amount of trials in the respective <block> elements accordingly. Do so via the <block> elements' /trials attributes. I've already done that, but I don't know how to program the number of times I want each word to appear (one in the first block and twice in the second). Would it be through selection mode? I've already tried all of them. That's my syntax: <block compatibletest1> / bgstim = (targetAleft, orleft, attributeAleftmixed, targetBright, orright, attributeBrightmixed) / trials = [1=instructions; 3,5,7,9,11,13,15,17,19,21,23,25,27,29,31= noreplacenorepeat(targetAleft, targetBright); 2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32 = noreplacenorepeat(attributeA, attributeB)] block compatibletest2> / bgstim = (targetAleft, orleft, attributeAleftmixed, targetBright, orright, attributeBrightmixed) / trials = [ 2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40,42,44,46,48,50,52,54,56,58,60,62,64 = noreplacenorepeat(targetAleft, targetAleft, targetBright, targetBright); 1,3,5,7,9,11,13,15,17,19,21,23,25,27,29,31,33,35,37,39,41,43,45,47,49,51,53,55,57,59,61,63 = noreplacenorepeat(attributeA, attributeA, attributeB, attributeB)] Let's take <block compatibletest1>. The items in your targetA, targetB, attributeA, and attributeB stimuli are sampled randomly without replacement. I.e., with 8 items per category, if you want each item to be sampled exactly once during the block, you need to run 8 targetAleft trials, 8 targetBright trials, 8 attributeA trials, and 8 attributeB trials. Your code doesn't do that, it runs too few targetAleft / targetBright trials. The code ought to read: <block compatibletest1> / bgstim = (targetAleft, orleft, attributeAleftmixed, targetBright, orright, attributeBrightmixed) / trials = [1=instructions; 3,5,7,9,11,13,15,17,19,21,23,25,27,29,31, 33= noreplacenorepeat(targetAleft, targetBright); 2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32 = noreplacenorepeat(attributeA, attributeB)] ... </block> i.e. you want 16 target trials, with targetAleft and targetBright sampled in equal proportions, resulting in 8 trials each. 3,5,7,9,11,13,15,17,19,21,23,25,27,29,31, 33= noreplacenorepeat(targetAleft, targetBright); The same reasoning applies to <block compatibletest2>. In addition, you can reset the various stimulus elements' selection pools at the start of the block. <block compatibletest1> / onblockbegin = [text.attributea.resetselection(); text.attributeb.resetselection(); text.targeta.resetselection(); text.targetb.resetselection(); ] / bgstim = (targetAleft, orleft, attributeAleftmixed, targetBright, orright, attributeBrightmixed) / trials = [1=instructions; 3,5,7,9,11,13,15,17,19,21,23,25,27,29,31, 33= noreplacenorepeat(targetAleft, targetBright); 2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32 = noreplacenorepeat(attributeA, attributeB)] ... </block> That way you can guarantee that all 8 items are available and free to be sampled at the start of the block. It worked. Thanks a lot!
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