Millisecond Forums » Millisecond Forums » Inquisit 5 » Uneven number of trials for different conditions in the experiment

Uneven number of trials for different conditions in the experiment

mingwu — Thu, 23 Feb 2017 07:14:56 GMT

Here is the expt:

<expt>

/postinstructions = (end)

/ blocks = [1=Instructions0;2-31=noreplace(block.part1in,block.part1out);32=Instructions0;33-62=noreplace(block.part2in,block.part2out);]]

</expt>

As you see, I run two sets of blocks(30 times each):

2-31=noreplace(block.part1in,block.part1out);

33-62=noreplace(block.part2in,block.part2out);

Each of these blocks basically has same logic:

/ onblockbegin = [

list.latencies.reset();

list.latencies_congruent.reset();

list.latencies_control.reset();

list.latencies_incongruent.reset();

list.responses.reset();

list.responses_congruent.reset();

list.responses_control.reset();

list.responses_incongruent.reset();

]

/ trials = [1=noreplace(redcongruent2,redincongruent2,redcontrol2, greencongruent2,greenincongruent2,greencontrol2, bluecongruent2,blueincongruent2,bluecontrol2,

purplecongruent2,purpleincongruent2,purplecontrol2);2=noreplace(trial.intrialpart1)]

</block>

/ onblockbegin = [

list.latencies.reset();

list.latencies_congruent.reset();

list.latencies_control.reset();

list.latencies_incongruent.reset();

list.responses.reset();

list.responses_congruent.reset();

list.responses_control.reset();

list.responses_incongruent.reset();

]

/ trials = [1=noreplace(redcongruent2,redincongruent2,redcontrol2,

greencongruent2, greenincongruent2,greencontrol2,

bluecongruent2, blueincongruent2,bluecontrol2,

purplecongruent2, purpleincongruent2,purplecontrol2);2=noreplace(trial.outtrialpart1)]

</block>

/ onblockbegin = [

list.latencies.reset();

list.latencies_congruent.reset();

list.latencies_control.reset();

list.latencies_incongruent.reset();

list.responses.reset();

list.responses_congruent.reset();

list.responses_control.reset();

list.responses_incongruent.reset();

]

/ trials = [1=noreplace(redcongruent2,redincongruent2,redcontrol2,

greencongruent2,greenincongruent2,greencontrol2,

bluecongruent2,blueincongruent2,bluecontrol2,

purplecongruent2,purpleincongruent2,purplecontrol2);2=noreplace(trial.intrialpart2)]

</block>

/ onblockbegin = [

list.latencies.reset();

list.latencies_congruent.reset();

list.latencies_control.reset();

list.latencies_incongruent.reset();

list.responses.reset();

list.responses_congruent.reset();

list.responses_control.reset();

list.responses_incongruent.reset();

]

/ trials = [1=noreplace(redcongruent2,redincongruent2,redcontrol2,

greencongruent2, greenincongruent2,greencontrol2,

bluecongruent2, blueincongruent2,bluecontrol2,

purplecongruent2, purpleincongruent2,purplecontrol2);2=noreplace(trial.outtrialpart2)]

</block>

I have no problems with second set of trials(2=noreplace(trial.outtrialpart2/intrialpart2)), it works as I expect. However, I would like 1 set of trials to behave differently.

1=noreplace(redcongruent2,redincongruent2,redcontrol2,greencongruent2, greenincongruent2,greencontrol2, bluecongruent2, blueincongruent2,bluecontrol2, purplecongruent2, purpleincongruent2,purplecontrol2);

Basically I call these 4 blocks (part1in/part1out/part2out/part2in) 60 times in total (15 times each). And i would like that after running it 60 times, I had equal number of executed 1 trials:

[1=noreplace(redcongruent2,redincongruent2,redcontrol2,greencongruent2, greenincongruent2,greencontrol2,bluecongruent2, blueincongruent2,bluecontrol2, purplecongruent2, purpleincongruent2,purplecontrol2);

As you see there 12 of them , and I would really like to show each of them 5 times (60/12) in random order. Right now i can get 12 redcontrol, 3 redcongruent, etc. But I would like to have 5 times of each.

How can I achieve this? I have read and it seems like i can reset interval, but I am not sure whether I am right or not, same as I do not understand how to implement it.

I would be really appreciate your help.

Thank you very much!!

RE: Uneven number of trials for different conditions in the experiment

mingwu — Thu, 23 Feb 2017 07:14:56 GMT

[quote]

[b]Dave - Wednesday, February 22, 2017[/b]

[quote]

[b]mingwu - Wednesday, February 22, 2017[/b]

Here is the expt:

<expt>

/postinstructions = (end)

/ blocks = [1=Instructions0;2-31=noreplace(block.part1in,block.part1out);32=Instructions0;33-62=noreplace(block.part2in,block.part2out);]]

</expt>

As you see, I run two sets of blocks(30 times each):

2-31=noreplace(block.part1in,block.part1out);

33-62=noreplace(block.part2in,block.part2out);

Each of these blocks basically has same logic:

/ onblockbegin = [

list.latencies.reset();

list.latencies_congruent.reset();

list.latencies_control.reset();

list.latencies_incongruent.reset();

list.responses.reset();

list.responses_congruent.reset();

list.responses_control.reset();

list.responses_incongruent.reset();

]

/ trials = [1=noreplace(redcongruent2,redincongruent2,redcontrol2, greencongruent2,greenincongruent2,greencontrol2, bluecongruent2,blueincongruent2,bluecontrol2,

purplecongruent2,purpleincongruent2,purplecontrol2);2=noreplace(trial.intrialpart1)]

</block>

/ onblockbegin = [

list.latencies.reset();

list.latencies_congruent.reset();

list.latencies_control.reset();

list.latencies_incongruent.reset();

list.responses.reset();

list.responses_congruent.reset();

list.responses_control.reset();

list.responses_incongruent.reset();

]

/ trials = [1=noreplace(redcongruent2,redincongruent2,redcontrol2,

greencongruent2, greenincongruent2,greencontrol2,

bluecongruent2, blueincongruent2,bluecontrol2,

purplecongruent2, purpleincongruent2,purplecontrol2);2=noreplace(trial.outtrialpart1)]

</block>

/ onblockbegin = [

list.latencies.reset();

list.latencies_congruent.reset();

list.latencies_control.reset();

list.latencies_incongruent.reset();

list.responses.reset();

list.responses_congruent.reset();

list.responses_control.reset();

list.responses_incongruent.reset();

]

/ trials = [1=noreplace(redcongruent2,redincongruent2,redcontrol2,

greencongruent2,greenincongruent2,greencontrol2,

bluecongruent2,blueincongruent2,bluecontrol2,

purplecongruent2,purpleincongruent2,purplecontrol2);2=noreplace(trial.intrialpart2)]

</block>

/ onblockbegin = [

list.latencies.reset();

list.latencies_congruent.reset();

list.latencies_control.reset();

list.latencies_incongruent.reset();

list.responses.reset();

list.responses_congruent.reset();

list.responses_control.reset();

list.responses_incongruent.reset();

]

/ trials = [1=noreplace(redcongruent2,redincongruent2,redcontrol2,

greencongruent2, greenincongruent2,greencontrol2,

bluecongruent2, blueincongruent2,bluecontrol2,

purplecongruent2, purpleincongruent2,purplecontrol2);2=noreplace(trial.outtrialpart2)]

</block>

I have no problems with second set of trials(2=noreplace(trial.outtrialpart2/intrialpart2)), it works as I expect. However, I would like 1 set of trials to behave differently.

Basically I call these 4 blocks (part1in/part1out/part2out/part2in) 60 times in total (15 times each). And i would like that after running it 60 times, I had equal number of executed 1 trials:

How can I achieve this? I have read and it seems like i can reset interval, but I am not sure whether I am right or not, same as I do not understand how to implement it.

I would be really appreciate your help.

Thank you very much!!

[/quote]

You need to use a <list> for trial-selection if you want to keep the selection pool intact across those blocks.

<list triallist>
/ items = (trial.redcongruent2,trial.redincongruent2,trial.redcontrol2,trial.greencongruent2, trial.greenincongruent2,trial.greencontrol2,trial.bluecongruent2, trial.blueincongruent2,trial.bluecontrol2, trial.purplecongruent2,trial.purpleincongruent2,trial.purplecontrol2)
/ poolsize = 60
</list>

with

<block part1in>
...
/ trials = [1=list.triallist]
</block>

<block part1out>
...
/ trials = [1=list.triallist]
</block>

and so forth.

[/quote]

Problem solved! Thank you so much!

RE: Uneven number of trials for different conditions in the experiment

Dave — Wed, 22 Feb 2017 21:00:37 GMT

[quote]

[b]mingwu - Wednesday, February 22, 2017[/b]

Here is the expt:

<expt>

/postinstructions = (end)

/ blocks = [1=Instructions0;2-31=noreplace(block.part1in,block.part1out);32=Instructions0;33-62=noreplace(block.part2in,block.part2out);]]

</expt>

As you see, I run two sets of blocks(30 times each):

2-31=noreplace(block.part1in,block.part1out);

33-62=noreplace(block.part2in,block.part2out);

Each of these blocks basically has same logic:

/ onblockbegin = [

list.latencies.reset();

list.latencies_congruent.reset();

list.latencies_control.reset();

list.latencies_incongruent.reset();

list.responses.reset();

list.responses_congruent.reset();

list.responses_control.reset();

list.responses_incongruent.reset();

]

/ trials = [1=noreplace(redcongruent2,redincongruent2,redcontrol2, greencongruent2,greenincongruent2,greencontrol2, bluecongruent2,blueincongruent2,bluecontrol2,

purplecongruent2,purpleincongruent2,purplecontrol2);2=noreplace(trial.intrialpart1)]

</block>

/ onblockbegin = [

list.latencies.reset();

list.latencies_congruent.reset();

list.latencies_control.reset();

list.latencies_incongruent.reset();

list.responses.reset();

list.responses_congruent.reset();

list.responses_control.reset();

list.responses_incongruent.reset();

]

/ trials = [1=noreplace(redcongruent2,redincongruent2,redcontrol2,

greencongruent2, greenincongruent2,greencontrol2,

bluecongruent2, blueincongruent2,bluecontrol2,

purplecongruent2, purpleincongruent2,purplecontrol2);2=noreplace(trial.outtrialpart1)]

</block>

/ onblockbegin = [

list.latencies.reset();

list.latencies_congruent.reset();

list.latencies_control.reset();

list.latencies_incongruent.reset();

list.responses.reset();

list.responses_congruent.reset();

list.responses_control.reset();

list.responses_incongruent.reset();

]

/ trials = [1=noreplace(redcongruent2,redincongruent2,redcontrol2,

greencongruent2,greenincongruent2,greencontrol2,

bluecongruent2,blueincongruent2,bluecontrol2,

purplecongruent2,purpleincongruent2,purplecontrol2);2=noreplace(trial.intrialpart2)]

</block>

/ onblockbegin = [

list.latencies.reset();

list.latencies_congruent.reset();

list.latencies_control.reset();

list.latencies_incongruent.reset();

list.responses.reset();

list.responses_congruent.reset();

list.responses_control.reset();

list.responses_incongruent.reset();

]

/ trials = [1=noreplace(redcongruent2,redincongruent2,redcontrol2,

greencongruent2, greenincongruent2,greencontrol2,

bluecongruent2, blueincongruent2,bluecontrol2,

purplecongruent2, purpleincongruent2,purplecontrol2);2=noreplace(trial.outtrialpart2)]

</block>

I have no problems with second set of trials(2=noreplace(trial.outtrialpart2/intrialpart2)), it works as I expect. However, I would like 1 set of trials to behave differently.

Basically I call these 4 blocks (part1in/part1out/part2out/part2in) 60 times in total (15 times each). And i would like that after running it 60 times, I had equal number of executed 1 trials:

How can I achieve this? I have read and it seems like i can reset interval, but I am not sure whether I am right or not, same as I do not understand how to implement it.

I would be really appreciate your help.

Thank you very much!!

[/quote]