Millisecond Forums » Millisecond Forums » Inquisit 5 » Presenting multiple image at once

Presenting multiple image at once

otago — Sun, 06 Jan 2019 14:02:18 GMT

Hi,

I am trying to create a trial that will show 7 images and 3 random images at all once on different location, then a fixation, and a red dot. My script so far only works when I only isted 3 random images but I need add more random images (I am new to programming). Is there a way always to select 7 images from the pool A and 3 random images from pool B?

Thank you.

RE: Presenting multiple image at once

otago — Sun, 06 Jan 2019 14:02:18 GMT

[quote]

[b]Dave - Wednesday, January 2, 2019[/b]

[quote]

[b]Dave - Wednesday, January 2, 2019[/b]

[quote]

[b]otago - Wednesday, January 2, 2019[/b]

[/quote]

You'll want to set up 7 <picture> elements that draw from pool A, and 3 that draw from pool B. This can be done using <list> elements for selection. You then (perhaps) want to randomize the location of those 10 <picture> elements on a trial by trial basis. (I say "perhaps" because that's not entirely clear from your description), This, too, can be achieved using <list> elements. Here's an example using <text> elements, it works the same way with <picture> elements:

<values>
/ a1 = 1
/ a1x = 0%
/ a1y = 0%
/ a2 = 1
/ a2x = 0%
/ a2y = 0%
/ a3 = 1
/ a3x = 0%
/ a3y = 0%
/ a4 = 1
/ a4x = 0%
/ a4y = 0%
/ a5 = 1
/ a5x = 0%
/ a5y = 0%
/ a6 = 1
/ a6x = 0%
/ a6y = 0%
/ a7 = 1
/ a7x = 0%
/ a7y = 0%

/ b1 = 1
/ b1x = 0%
/ b1y = 0%
/ b2 = 1
/ b2x = 0%
/ b2y = 0%
/ b3 = 1
/ b3x = 0%
/ b3y = 0%
</values>

<block myblock>
/ trials = [1-3 = mytrial]
</block>

<trial mytrial>
/ ontrialbegin = [
values.a1 = list.aitemnumbers.nextindex;
values.a1x = list.xpos.nextvalue;
values.a1y = list.ypos.nextvalue;
values.a2 = list.aitemnumbers.nextindex;
values.a2x = list.xpos.nextvalue;
values.a2y = list.ypos.nextvalue;
values.a3 = list.aitemnumbers.nextindex;
values.a3x = list.xpos.nextvalue;
values.a3y = list.ypos.nextvalue;
values.a4 = list.aitemnumbers.nextindex;
values.a4x = list.xpos.nextvalue;
values.a4y = list.ypos.nextvalue;
values.a5 = list.aitemnumbers.nextindex;
values.a5x = list.xpos.nextvalue;
values.a5y = list.ypos.nextvalue;
values.a6 = list.aitemnumbers.nextindex;
values.a6x = list.xpos.nextvalue;
values.a6y = list.ypos.nextvalue;
values.a7 = list.aitemnumbers.nextindex;
values.a7x = list.xpos.nextvalue;
values.a7y = list.ypos.nextvalue;

values.b1 = list.bitemnumbers.nextindex;
values.b1x = list.xpos.nextvalue;
values.b1y = list.ypos.nextvalue;
values.b2 = list.bitemnumbers.nextindex;
values.b2x = list.xpos.nextvalue;
values.b2y = list.ypos.nextvalue;
values.b3 = list.bitemnumbers.nextindex;
values.b3x = list.xpos.nextvalue;
values.b3y = list.ypos.nextvalue;
]
/ stimulustimes = [0=a1,a2,a3,a4,a5,a6,a7,b1,b2,b3]
/ validresponse = (57)
</trial>

<text a1>
/ items = poolaitems
/ select = values.a1
/ hposition = values.a1x
/ vposition = values.a1y
</text>

<text a2>
/ items = poolaitems
/ select = values.a2
/ hposition = values.a2x
/ vposition = values.a2y
</text>

<text a3>
/ items = poolaitems
/ select = values.a3
/ hposition = values.a3x
/ vposition = values.a3y
</text>

<text a4>
/ items = poolaitems
/ select = values.a4
/ hposition = values.a4x
/ vposition = values.a4y
</text>

<text a5>
/ items = poolaitems
/ select = values.a5
/ hposition = values.a5x
/ vposition = values.a5y
</text>

<text a6>
/ items = poolaitems
/ select = values.a6
/ hposition = values.a6x
/ vposition = values.a6y
</text>

<text a7>
/ items = poolaitems
/ select = values.a7
/ hposition = values.a7x
/ vposition = values.a7y
</text>

<text b1>
/ items = poolbitems
/ select = values.b1
/ hposition = values.b1x
/ vposition = values.b1y
</text>

<text b2>
/ items = poolbitems
/ select = values.b2
/ hposition = values.b2x
/ vposition = values.b2y
</text>

<text b3>
/ items = poolbitems
/ select = values.b3
/ hposition = values.b3x
/ vposition = values.b3y
</text>

<item poolaitems>
/ 1 = "A01"
/ 2 = "A02"
/ 3 = "A03"
/ 4 = "A04"
/ 5 = "A05"
/ 6 = "A06"
/ 7 = "A07"
/ 8 = "A08"
/ 9 = "A09"
/ 10 = "A10"
/ 11 = "A11"
/ 12 = "A12"
/ 13 = "A13"
/ 14 = "A14"
/ 15 = "A15"
/ 16 = "A16"
/ 17 = "A17"
/ 18 = "A18"
/ 19 = "A19"
/ 20 = "A20"
/ 21 = "A21"
</item>

<item poolbitems>
/ 1 = "B01"
/ 2 = "B02"
/ 3 = "B03"
/ 4 = "B04"
/ 5 = "B05"
/ 6 = "B06"
/ 7 = "B07"
/ 8 = "B08"
/ 9 = "B09"
</item>

//21 items in pool A in this example
<list aitemnumbers>
/ poolsize = 21
/ selectionrate = always
</list>

//9 items in pool B in this example
<list bitemnumbers>
/ poolsize = 9
/ selectionrate = always
</list>

//10 screen positions expressed as pairs of X and Y coordinates
<list xpos>
/ items = (10%, 30%, 50%, 70%, 90%, 10%, 30%, 50%, 70%, 90%)
/ selectionmode = random
/ selectionrate = always
</list>

<list ypos>
/ items = (25%, 25%, 25%, 25%, 25%, 75%, 75%, 75%, 75%, 75%)
/ selectionmode = list.xpos.currentindex
/ selectionrate = always
</list>

[/quote]

And if your items in pool A are composed of different sets (i.e. 7 specific items belong together and should be shown together in a given trial), that's possible as well along the same lines.

<values>
/ aset = 1

/ a1 = 1
/ a1x = 0%
/ a1y = 0%
/ a2 = 1
/ a2x = 0%
/ a2y = 0%
/ a3 = 1
/ a3x = 0%
/ a3y = 0%
/ a4 = 1
/ a4x = 0%
/ a4y = 0%
/ a5 = 1
/ a5x = 0%
/ a5y = 0%
/ a6 = 1
/ a6x = 0%
/ a6y = 0%
/ a7 = 1
/ a7x = 0%
/ a7y = 0%

/ b1 = 1
/ b1x = 0%
/ b1y = 0%
/ b2 = 1
/ b2x = 0%
/ b2y = 0%
/ b3 = 1
/ b3x = 0%
/ b3y = 0%
</values>

<block myblock>
/ trials = [1-3 = mytrial]
</block>

<trial mytrial>
/ ontrialbegin = [
values.aset = list.asetnumbers.nextindex;
values.a1 = list.aitemnumbers.nextvalue;
values.a1x = list.xpos.nextvalue;
values.a1y = list.ypos.nextvalue;
values.a2 = list.aitemnumbers.nextvalue;
values.a2x = list.xpos.nextvalue;
values.a2y = list.ypos.nextvalue;
values.a3 = list.aitemnumbers.nextvalue;
values.a3x = list.xpos.nextvalue;
values.a3y = list.ypos.nextvalue;
values.a4 = list.aitemnumbers.nextvalue;
values.a4x = list.xpos.nextvalue;
values.a4y = list.ypos.nextvalue;
values.a5 = list.aitemnumbers.nextvalue;
values.a5x = list.xpos.nextvalue;
values.a5y = list.ypos.nextvalue;
values.a6 = list.aitemnumbers.nextvalue;
values.a6x = list.xpos.nextvalue;
values.a6y = list.ypos.nextvalue;
values.a7 = list.aitemnumbers.nextvalue;
values.a7x = list.xpos.nextvalue;
values.a7y = list.ypos.nextvalue;

values.b1 = list.bitemnumbers.nextindex;
values.b1x = list.xpos.nextvalue;
values.b1y = list.ypos.nextvalue;
values.b2 = list.bitemnumbers.nextindex;
values.b2x = list.xpos.nextvalue;
values.b2y = list.ypos.nextvalue;
values.b3 = list.bitemnumbers.nextindex;
values.b3x = list.xpos.nextvalue;
values.b3y = list.ypos.nextvalue;
]
/ stimulustimes = [0=a1,a2,a3,a4,a5,a6,a7,b1,b2,b3]
/ validresponse = (57)
</trial>

<text a1>
/ items = poolaitems
/ select = values.a1
/ hposition = values.a1x
/ vposition = values.a1y
</text>

<text a2>
/ items = poolaitems
/ select = values.a2
/ hposition = values.a2x
/ vposition = values.a2y
</text>

<text a3>
/ items = poolaitems
/ select = values.a3
/ hposition = values.a3x
/ vposition = values.a3y
</text>

<text a4>
/ items = poolaitems
/ select = values.a4
/ hposition = values.a4x
/ vposition = values.a4y
</text>

<text a5>
/ items = poolaitems
/ select = values.a5
/ hposition = values.a5x
/ vposition = values.a5y
</text>

<text a6>
/ items = poolaitems
/ select = values.a6
/ hposition = values.a6x
/ vposition = values.a6y
</text>

<text a7>
/ items = poolaitems
/ select = values.a7
/ hposition = values.a7x
/ vposition = values.a7y
</text>

<text b1>
/ items = poolbitems
/ select = values.b1
/ hposition = values.b1x
/ vposition = values.b1y
</text>

<text b2>
/ items = poolbitems
/ select = values.b2
/ hposition = values.b2x
/ vposition = values.b2y
</text>

<text b3>
/ items = poolbitems
/ select = values.b3
/ hposition = values.b3x
/ vposition = values.b3y
</text>

<item poolaitems>
/ 1 = "A1_01"
/ 2 = "A1_02"
/ 3 = "A1_03"
/ 4 = "A1_04"
/ 5 = "A1_05"
/ 6 = "A1_06"
/ 7 = "A1_07"

/ 8 = "A2_01"
/ 9 = "A2_02"
/ 10 = "A2_03"
/ 11 = "A2_04"
/ 12 = "A2_05"
/ 13 = "A2_06"
/ 14 = "A2_07"

/ 15 = "A3_01"
/ 16 = "A3_02"
/ 17 = "A3_03"
/ 18 = "A3_04"
/ 19 = "A3_05"
/ 20 = "A3_06"
/ 21 = "A3_07"
</item>

<item poolbitems>
/ 1 = "B01"
/ 2 = "B02"
/ 3 = "B03"
/ 4 = "B04"
/ 5 = "B05"
/ 6 = "B06"
/ 7 = "B07"
/ 8 = "B08"
/ 9 = "B09"
</item>

<list aitemnumbers>
/ items = (list.a_set1.nextvalue, list.a_set2.nextvalue, list.a_set3.nextvalue)
/ selectionmode = values.aset
/ selectionrate = always
</list>

<list asetnumbers>
/ poolsize = 3
</list>

//set #1 is composed of items 1 to 7
<list a_set1>
/ items = (1,2,3,4,5,6,7)
/ selectionrate = always
</list>

//set #2 is composed of items 8 to 14
<list a_set2>
/ items = (8,9,10,11,12,13,14)
/ selectionrate = always
</list>

//set #3 is composed of items 15 to 21
<list a_set3>
/ items = (15,16,17,18,19,20,21)
/ selectionrate = always
</list>

//9 items in pool B in this example
<list bitemnumbers>
/ poolsize = 9
/ selectionrate = always
</list>

//10 screen positions expressed as pairs of X and Y coordinates
<list xpos>
/ items = (10%, 30%, 50%, 70%, 90%, 10%, 30%, 50%, 70%, 90%)
/ selectionmode = random
/ selectionrate = always
</list>

<list ypos>
/ items = (25%, 25%, 25%, 25%, 25%, 75%, 75%, 75%, 75%, 75%)
/ selectionmode = list.xpos.currentindex
/ selectionrate = always
</list>

[/quote]

Hi Dave,

This is exactly what I want to do.

Thank you very much.

RE: Presenting multiple image at once

Dave — Wed, 02 Jan 2019 21:06:51 GMT

[quote]

[b]Dave - Wednesday, January 2, 2019[/b]

[quote]

[b]otago - Wednesday, January 2, 2019[/b]

[/quote]

RE: Presenting multiple image at once

Dave — Wed, 02 Jan 2019 20:50:46 GMT

[quote]

[b]otago - Wednesday, January 2, 2019[/b]

[/quote]