Millisecond Forums » Millisecond Forums » Inquisit 5 » Randomizing presentation of groups of blocks

RE: Randomizing presentation of groups of blocks

Dave — Fri, 12 Feb 2021 01:54:45 GMT

+x[quote]

[b]mindwanderingjeremy - 2/12/2021[/b]
Is it the same for the expt /blocks syntax? If I only want it to run through noreplace(block1, block2, block3, etc.) once I list it as 1 = noreplace(block1, block2, block3, etc.)?
[/quote]

This applies to sequence() only. A sequence is treated as a single unit.

When sampling randomly from some pool, it's 1-3 = noreplace(a,b,c) if you want each element in the pool run once, in random order.

2 -9 = noreplace(0backNT, 0backNT, 0backNT, 0backtarget);

will give you 6 0backNT trials and 2 0backtarget trials, in random order.

Randomizing presentation of groups of blocks

mindwanderingjeremy — Fri, 12 Feb 2021 01:52:27 GMT

Hi again!

I am having trouble with my n-back task code again. It is nearly complete but I am attempting to randomise the presentation of my survey pages which is proving difficult.
The way I have attempted to do this is I have created a <survey thoughtprobes> function which presents each of the survey pages in a random order. However, I need this survey page to be shown after every one of my experimental blocks. To do this I need to be able to randomly select groups of block1 + survey.thoughtprobes, block 2 + survey.thoughprobes, block3 + survey.thoughtprobes, etc in my <experiment> function. Is there an easy way to do this?

So far I have attempted to use a method I found on a 10 year old thread in this forum which uses lists to achieve this like so:
<list blockselector>
/items = (list.q0b1, list.q0b2, list.q0b3, list.m0b1, list.m0b2, list.m0b3, list.l0b1, list.l0b2, list.l0b3,
list.q1b1, list.q1b2, list.q1b3, list.m1b1, list.m1b2, list.m1b3, list.l1b1, list.l1b2, list.l1b3,)
/selectionmode = random
/replace = false
</list>
<list q0b1>
/items = (block.quick0back1, survey.thoughtprobe)
/selectionmode = sequence
</list>
*** multiple lists for each block type ***
<expt>
/ preinstructions = (intro)
/ postinstructions = (end)
/ blocks = [1-2 = list.blockselector; 3-4 = list.blockselector; 5-6 = list.blockselector; 7-8 = list.blockselector; 9-10 = list.blockselector;
11-12 = list.blockselector; 13-14 = list.blockselector; 15-16 = list.blockselector; 17-18 = list.blockselector; 19-20 = list.blockselector;
21-22 = list.blockselector; 23-24 = list.blockselector; 25-26 = list.blockselector; 27-28 = list.blockselector; 29-30 = list.blockselector;
31-32 = list.blockselector; 33-34 = list.blockselector; 35-36 = list.blockselector]
/onexptend = [values.completed = 1]
</expt>

However this does not work. Any ideas on how I can randomly present blocks with the survey at the end?
I have included my code and stimuli below if you would like to look at the whole thing.
Thank you!

RE: Randomizing presentation of groups of blocks

mindwanderingjeremy — Fri, 12 Feb 2021 01:44:50 GMT

Is it the same for the expt /blocks syntax? If I only want it to run through noreplace(block1, block2, block3, etc.) once I list it as 1 = noreplace(block1, block2, block3, etc.)?

RE: Randomizing presentation of groups of blocks

mindwanderingjeremy — Fri, 12 Feb 2021 01:41:34 GMT

+x[quote]

[b]Dave - 2/12/2021[/b]
+x[quote]

[b]mindwanderingjeremy - 2/11/2021[/b]
+x[quote]

[b]mindwanderingjeremy - 2/11/2021[/b]
+x[quote]

[b]Dave - 2/11/2021[/b]
+x[quote]

[b]mindwanderingjeremy - 2/11/2021[/b]
Hi again!

I am having trouble with my n-back task code again. It is nearly complete but I am attempting to randomise the presentation of my survey pages which is proving difficult.
The way I have attempted to do this is I have created a <survey thoughtprobes> function which presents each of the survey pages in a random order. However, I need this survey page to be shown after every one of my experimental blocks. To do this I need to be able to randomly select groups of block1 + survey.thoughtprobes, block 2 + survey.thoughprobes, block3 + survey.thoughtprobes, etc in my <experiment> function. Is there an easy way to do this?

So far I have attempted to use a method I found on a 10 year old thread in this forum which uses lists to achieve this like so:
<list blockselector>
/items = (list.q0b1, list.q0b2, list.q0b3, list.m0b1, list.m0b2, list.m0b3, list.l0b1, list.l0b2, list.l0b3,
list.q1b1, list.q1b2, list.q1b3, list.m1b1, list.m1b2, list.m1b3, list.l1b1, list.l1b2, list.l1b3,)
/selectionmode = random
/replace = false
</list>
<list q0b1>
/items = (block.quick0back1, survey.thoughtprobe)
/selectionmode = sequence
</list>
*** multiple lists for each block type ***
<expt>
/ preinstructions = (intro)
/ postinstructions = (end)
/ blocks = [1-2 = list.blockselector; 3-4 = list.blockselector; 5-6 = list.blockselector; 7-8 = list.blockselector; 9-10 = list.blockselector;
11-12 = list.blockselector; 13-14 = list.blockselector; 15-16 = list.blockselector; 17-18 = list.blockselector; 19-20 = list.blockselector;
21-22 = list.blockselector; 23-24 = list.blockselector; 25-26 = list.blockselector; 27-28 = list.blockselector; 29-30 = list.blockselector;
31-32 = list.blockselector; 33-34 = list.blockselector; 35-36 = list.blockselector]
/onexptend = [values.completed = 1]
</expt>

However this does not work. Any ideas on how I can randomly present blocks with the survey at the end?
I have included my code and stimuli below if you would like to look at the whole thing.
Thank you!
[/quote]

Why don't you just /branch to the survey block from each of the nback blocks? That is:

Sample your nback blocks randomly at the <expt> level per

<expt>
...
/ blocks = [1-18 = noreplace(quick0back1, ...)]
...
</expt>

and in each nback block have

<block quick0back1>
...
/ branch = [survey.thoughtprobe]
</block>
[/quote]

I tried doing this but it doesnt work for some reason. It just goes past skips the thought probes and goes to the next block.
[/quote]

Here is the scripted coded like you suggest. It doesnt branch to the survey for some reason.
[/quote]

It branches to the survey just fine. You're probably just confused, expecting the branch to occur whenever you see your "stop" trial, but that's because your blocks' /trials syntax is faulty (in all blocks).

/ trials = [1 = 0backready; 2 -9 = noreplace(0backNT, 0backNT, 0backNT, 0backtarget); 10-14 = 0backtarget, 0backNT, 0backNT, 0backNT, stop]

I'm not sure what you intend the bolded part above to do, but I can tell you what it does do: It runs the sequence of trials

0backtarget -> 0backNT -> 0backNT -> 0backNT -> stop

five times.

If you want that sequence of five trials to run only once, the proper specification is

/ trials = [1 = 0backready; 2 -9 = noreplace(0backNT, 0backNT, 0backNT, 0backtarget); 10 = sequence(0backtarget, 0backNT, 0backNT, 0backNT, stop)]
[/quote]

Ahh right I understand! yes thank you I did want it to only run once so I appreciate this clarification. I will change this syntax thank you

RE: Randomizing presentation of groups of blocks

Dave — Fri, 12 Feb 2021 01:03:18 GMT

+x[quote]

[b]mindwanderingjeremy - 2/11/2021[/b]
+x[quote]

[b]mindwanderingjeremy - 2/11/2021[/b]
+x[quote]

[b]Dave - 2/11/2021[/b]
+x[quote]

[b]mindwanderingjeremy - 2/11/2021[/b]
Hi again!

I am having trouble with my n-back task code again. It is nearly complete but I am attempting to randomise the presentation of my survey pages which is proving difficult.
The way I have attempted to do this is I have created a <survey thoughtprobes> function which presents each of the survey pages in a random order. However, I need this survey page to be shown after every one of my experimental blocks. To do this I need to be able to randomly select groups of block1 + survey.thoughtprobes, block 2 + survey.thoughprobes, block3 + survey.thoughtprobes, etc in my <experiment> function. Is there an easy way to do this?

So far I have attempted to use a method I found on a 10 year old thread in this forum which uses lists to achieve this like so:
<list blockselector>
/items = (list.q0b1, list.q0b2, list.q0b3, list.m0b1, list.m0b2, list.m0b3, list.l0b1, list.l0b2, list.l0b3,
list.q1b1, list.q1b2, list.q1b3, list.m1b1, list.m1b2, list.m1b3, list.l1b1, list.l1b2, list.l1b3,)
/selectionmode = random
/replace = false
</list>
<list q0b1>
/items = (block.quick0back1, survey.thoughtprobe)
/selectionmode = sequence
</list>
*** multiple lists for each block type ***
<expt>
/ preinstructions = (intro)
/ postinstructions = (end)
/ blocks = [1-2 = list.blockselector; 3-4 = list.blockselector; 5-6 = list.blockselector; 7-8 = list.blockselector; 9-10 = list.blockselector;
11-12 = list.blockselector; 13-14 = list.blockselector; 15-16 = list.blockselector; 17-18 = list.blockselector; 19-20 = list.blockselector;
21-22 = list.blockselector; 23-24 = list.blockselector; 25-26 = list.blockselector; 27-28 = list.blockselector; 29-30 = list.blockselector;
31-32 = list.blockselector; 33-34 = list.blockselector; 35-36 = list.blockselector]
/onexptend = [values.completed = 1]
</expt>

However this does not work. Any ideas on how I can randomly present blocks with the survey at the end?
I have included my code and stimuli below if you would like to look at the whole thing.
Thank you!
[/quote]

Why don't you just /branch to the survey block from each of the nback blocks? That is:

Sample your nback blocks randomly at the <expt> level per

<expt>
...
/ blocks = [1-18 = noreplace(quick0back1, ...)]
...
</expt>

and in each nback block have

<block quick0back1>
...
/ branch = [survey.thoughtprobe]
</block>
[/quote]

I tried doing this but it doesnt work for some reason. It just goes past skips the thought probes and goes to the next block.
[/quote]

Here is the scripted coded like you suggest. It doesnt branch to the survey for some reason.
[/quote]

It branches to the survey just fine. You're probably just confused, expecting the branch to occur whenever you see your "stop" trial, but that's because your blocks' /trials syntax is faulty (in all blocks).

/ trials = [1 = 0backready; 2 -9 = noreplace(0backNT, 0backNT, 0backNT, 0backtarget); 10-14 = 0backtarget, 0backNT, 0backNT, 0backNT, stop]

I'm not sure what you intend the bolded part above to do, but I can tell you what it does do: It runs the sequence of trials

0backtarget -> 0backNT -> 0backNT -> 0backNT -> stop

five times.

If you want that sequence of five trials to run only once, the proper specification is

/ trials = [1 = 0backready; 2 -9 = noreplace(0backNT, 0backNT, 0backNT, 0backtarget); 10 = sequence(0backtarget, 0backNT, 0backNT, 0backNT, stop)]

RE: Randomizing presentation of groups of blocks

mindwanderingjeremy — Thu, 11 Feb 2021 23:51:46 GMT

+x[quote]

[b]mindwanderingjeremy - 2/11/2021[/b]
+x[quote]

[b]Dave - 2/11/2021[/b]
+x[quote]

[b]mindwanderingjeremy - 2/11/2021[/b]
Hi again!

I am having trouble with my n-back task code again. It is nearly complete but I am attempting to randomise the presentation of my survey pages which is proving difficult.
The way I have attempted to do this is I have created a <survey thoughtprobes> function which presents each of the survey pages in a random order. However, I need this survey page to be shown after every one of my experimental blocks. To do this I need to be able to randomly select groups of block1 + survey.thoughtprobes, block 2 + survey.thoughprobes, block3 + survey.thoughtprobes, etc in my <experiment> function. Is there an easy way to do this?

So far I have attempted to use a method I found on a 10 year old thread in this forum which uses lists to achieve this like so:
<list blockselector>
/items = (list.q0b1, list.q0b2, list.q0b3, list.m0b1, list.m0b2, list.m0b3, list.l0b1, list.l0b2, list.l0b3,
list.q1b1, list.q1b2, list.q1b3, list.m1b1, list.m1b2, list.m1b3, list.l1b1, list.l1b2, list.l1b3,)
/selectionmode = random
/replace = false
</list>
<list q0b1>
/items = (block.quick0back1, survey.thoughtprobe)
/selectionmode = sequence
</list>
*** multiple lists for each block type ***
<expt>
/ preinstructions = (intro)
/ postinstructions = (end)
/ blocks = [1-2 = list.blockselector; 3-4 = list.blockselector; 5-6 = list.blockselector; 7-8 = list.blockselector; 9-10 = list.blockselector;
11-12 = list.blockselector; 13-14 = list.blockselector; 15-16 = list.blockselector; 17-18 = list.blockselector; 19-20 = list.blockselector;
21-22 = list.blockselector; 23-24 = list.blockselector; 25-26 = list.blockselector; 27-28 = list.blockselector; 29-30 = list.blockselector;
31-32 = list.blockselector; 33-34 = list.blockselector; 35-36 = list.blockselector]
/onexptend = [values.completed = 1]
</expt>

However this does not work. Any ideas on how I can randomly present blocks with the survey at the end?
I have included my code and stimuli below if you would like to look at the whole thing.
Thank you!
[/quote]

Why don't you just /branch to the survey block from each of the nback blocks? That is:

Sample your nback blocks randomly at the <expt> level per

<expt>
...
/ blocks = [1-18 = noreplace(quick0back1, ...)]
...
</expt>

and in each nback block have

<block quick0back1>
...
/ branch = [survey.thoughtprobe]
</block>
[/quote]

I tried doing this but it doesnt work for some reason. It just goes past skips the thought probes and goes to the next block.
[/quote]

Here is the scripted coded like you suggest. It doesnt branch to the survey for some reason.

RE: Randomizing presentation of groups of blocks

mindwanderingjeremy — Thu, 11 Feb 2021 23:48:37 GMT

+x[quote]

[b]Dave - 2/11/2021[/b]
+x[quote]

[b]mindwanderingjeremy - 2/11/2021[/b]
Hi again!

I am having trouble with my n-back task code again. It is nearly complete but I am attempting to randomise the presentation of my survey pages which is proving difficult.
The way I have attempted to do this is I have created a <survey thoughtprobes> function which presents each of the survey pages in a random order. However, I need this survey page to be shown after every one of my experimental blocks. To do this I need to be able to randomly select groups of block1 + survey.thoughtprobes, block 2 + survey.thoughprobes, block3 + survey.thoughtprobes, etc in my <experiment> function. Is there an easy way to do this?

So far I have attempted to use a method I found on a 10 year old thread in this forum which uses lists to achieve this like so:
<list blockselector>
/items = (list.q0b1, list.q0b2, list.q0b3, list.m0b1, list.m0b2, list.m0b3, list.l0b1, list.l0b2, list.l0b3,
list.q1b1, list.q1b2, list.q1b3, list.m1b1, list.m1b2, list.m1b3, list.l1b1, list.l1b2, list.l1b3,)
/selectionmode = random
/replace = false
</list>
<list q0b1>
/items = (block.quick0back1, survey.thoughtprobe)
/selectionmode = sequence
</list>
*** multiple lists for each block type ***
<expt>
/ preinstructions = (intro)
/ postinstructions = (end)
/ blocks = [1-2 = list.blockselector; 3-4 = list.blockselector; 5-6 = list.blockselector; 7-8 = list.blockselector; 9-10 = list.blockselector;
11-12 = list.blockselector; 13-14 = list.blockselector; 15-16 = list.blockselector; 17-18 = list.blockselector; 19-20 = list.blockselector;
21-22 = list.blockselector; 23-24 = list.blockselector; 25-26 = list.blockselector; 27-28 = list.blockselector; 29-30 = list.blockselector;
31-32 = list.blockselector; 33-34 = list.blockselector; 35-36 = list.blockselector]
/onexptend = [values.completed = 1]
</expt>

However this does not work. Any ideas on how I can randomly present blocks with the survey at the end?
I have included my code and stimuli below if you would like to look at the whole thing.
Thank you!
[/quote]

Why don't you just /branch to the survey block from each of the nback blocks? That is:

Sample your nback blocks randomly at the <expt> level per

<expt>
...
/ blocks = [1-18 = noreplace(quick0back1, ...)]
...
</expt>

and in each nback block have

<block quick0back1>
...
/ branch = [survey.thoughtprobe]
</block>
[/quote]

I tried doing this but it doesnt work for some reason. It just goes past skips the thought probes and goes to the next block.

RE: Randomizing presentation of groups of blocks

Dave — Thu, 11 Feb 2021 11:57:53 GMT

+x[quote]

[b]mindwanderingjeremy - 2/11/2021[/b]
Hi again!

I am having trouble with my n-back task code again. It is nearly complete but I am attempting to randomise the presentation of my survey pages which is proving difficult.
The way I have attempted to do this is I have created a <survey thoughtprobes> function which presents each of the survey pages in a random order. However, I need this survey page to be shown after every one of my experimental blocks. To do this I need to be able to randomly select groups of block1 + survey.thoughtprobes, block 2 + survey.thoughprobes, block3 + survey.thoughtprobes, etc in my <experiment> function. Is there an easy way to do this?

So far I have attempted to use a method I found on a 10 year old thread in this forum which uses lists to achieve this like so:
<list blockselector>
/items = (list.q0b1, list.q0b2, list.q0b3, list.m0b1, list.m0b2, list.m0b3, list.l0b1, list.l0b2, list.l0b3,
list.q1b1, list.q1b2, list.q1b3, list.m1b1, list.m1b2, list.m1b3, list.l1b1, list.l1b2, list.l1b3,)
/selectionmode = random
/replace = false
</list>
<list q0b1>
/items = (block.quick0back1, survey.thoughtprobe)
/selectionmode = sequence
</list>
*** multiple lists for each block type ***
<expt>
/ preinstructions = (intro)
/ postinstructions = (end)
/ blocks = [1-2 = list.blockselector; 3-4 = list.blockselector; 5-6 = list.blockselector; 7-8 = list.blockselector; 9-10 = list.blockselector;
11-12 = list.blockselector; 13-14 = list.blockselector; 15-16 = list.blockselector; 17-18 = list.blockselector; 19-20 = list.blockselector;
21-22 = list.blockselector; 23-24 = list.blockselector; 25-26 = list.blockselector; 27-28 = list.blockselector; 29-30 = list.blockselector;
31-32 = list.blockselector; 33-34 = list.blockselector; 35-36 = list.blockselector]
/onexptend = [values.completed = 1]
</expt>

However this does not work. Any ideas on how I can randomly present blocks with the survey at the end?
I have included my code and stimuli below if you would like to look at the whole thing.
Thank you!
[/quote]

Why don't you just /branch to the survey block from each of the nback blocks? That is:

Sample your nback blocks randomly at the <expt> level per

<expt>
...
/ blocks = [1-18 = noreplace(quick0back1, ...)]
...
</expt>

and in each nback block have

<block quick0back1>
...
/ branch = [survey.thoughtprobe]
</block>