creating a back button for randomized trials, not surveypage

nc — Thu, 12 Aug 2021 19:58:09 GMT

Hi--
I'm trying to add a back button for an experiment (NOT a survey page) in order to go back to a previous trial. I generally know how to use conditional logic -- the only problem is that the trials are randomized, so it's not entirely clear which trial to display. The relevant part of the experiment is set up as follows:

3 randomized trials:
<block similar>
/trials = [1-3 = noreplace(6_by_2, 10_by_2, 12_by_2)]
</block>

I'd like to add conditional branching to each of these trials (6_by_2, 10_by_2, 12_by_2) if the back button is pressed, but I don't know how to do this given that *which* trial is the previous trial will depend on how randomization works. Thanks in advance for any help!

RE: creating a back button for randomized trials, not surveypage

Dave — Thu, 12 Aug 2021 19:58:09 GMT

+x[quote]

[b]Dave - 8/12/2021[/b]
+x[quote]

[b]nc - 8/12/2021[/b]
Hi--
I'm trying to add a back button for an experiment (NOT a survey page) in order to go back to a previous trial. I generally know how to use conditional logic -- the only problem is that the trials are randomized, so it's not entirely clear which trial to display. The relevant part of the experiment is set up as follows:

3 randomized trials:
<block similar>
/trials = [1-3 = noreplace(6_by_2, 10_by_2, 12_by_2)]
</block>

I'd like to add conditional branching to each of these trials (6_by_2, 10_by_2, 12_by_2) if the back button is pressed, but I don't know how to do this given that *which* trial is the previous trial will depend on how randomization works. Thanks in advance for any help!

[/quote]

Before anyone can propose any answer, you need to spell out what's supposed to happen after someone went back to the previous trial. Suppose the random order is

10_by_2 -> 6_by_2 -> 12_by_2 and then you go back from 12_by_2 to 6_by_2. What happens after that second instance of 6_by_2 then? Another instance of 12_by_2? Nothing? Another random trial?
[/quote]

Meanwhile here's an example based on guesswork. Even if that's not how you want things to work, you may be able to adapt it.

[code]<values>
/ currenttrialnumber = 0
/ nexttrialnumber = 0
/ loopcount = 0
</values>

<block example>
/ stop = [
    // stop once we've finished all trials
    values.nexttrialnumber > list.trialsequence.itemcount;
]
/ onblockbegin = [
    // generate a random trial sequence
    while (values.loopcount < list.trials.itemcount) {
        list.trialsequence.appenditem(list.trials.nextvalue);
        values.loopcount += 1;
    };
    values.nexttrialnumber = 1;
]
/ trials = [1=list.trialsequence]
</block>

<list trials>
/ items = (trial.6_by_2, trial.10_by_2, trial.12_by_2)
/ selectionmode = random
/ selectionrate = always
</list>

<list trialsequence>
/ select = values.nexttrialnumber
</list>

<trial 6_by_2>
/ ontrialbegin = [
    values.currenttrialnumber = values.nexttrialnumber;
    trial.6_by_2.resetstimulusframes();
    // no back button in the 1st trial
    if (values.currenttrialnumber > 1){
        trial.6_by_2.insertstimulusframe(button.backbutton, 1);
    };
]
/ ontrialend = [
    if (trial.6_by_2.response == "backbutton") {
        values.nexttrialnumber -= 1;
    } else {
        values.nexttrialnumber += 1;
    };
    // can't go below trial number 1
    values.nexttrialnumber = max(1, values.nexttrialnumber);
]
/ stimulusframes = [1=mytext, nextbutton]
/ inputdevice = mouse
/ validresponse = (nextbutton, backbutton)
/ branch = [
    list.trialsequence.nextvalue;
]
</trial>

<trial 10_by_2>
/ ontrialbegin = [
    values.currenttrialnumber = values.nexttrialnumber;
    trial.10_by_2.resetstimulusframes();
    // no back button in the 1st trial
    if (values.currenttrialnumber > 1){
        trial.10_by_2.insertstimulusframe(button.backbutton, 1);
    };
]
/ ontrialend = [
    if (trial.10_by_2.response == "backbutton") {
        values.nexttrialnumber -= 1;
    } else {
        values.nexttrialnumber += 1;
    };
    // can't go below trial number 1
    values.nexttrialnumber = max(1, values.nexttrialnumber);
]
/ stimulusframes = [1=mytext, nextbutton]
/ inputdevice = mouse
/ validresponse = (nextbutton, backbutton)
/ branch = [
    list.trialsequence.nextvalue;
]
</trial>

<trial 12_by_2>
/ ontrialbegin = [
    values.currenttrialnumber = values.nexttrialnumber;
    trial.12_by_2.resetstimulusframes();
    // no back button in the 1st trial
    if (values.currenttrialnumber > 1){
        trial.12_by_2.insertstimulusframe(button.backbutton, 1);
    };
]
/ ontrialend = [
    if (trial.12_by_2.response == "backbutton") {
        values.nexttrialnumber -= 1;
    } else {
        values.nexttrialnumber += 1;
    };
    // can't go below trial number 1
    values.nexttrialnumber = max(1, values.nexttrialnumber);
]
/ stimulusframes = [1=mytext, nextbutton]
/ inputdevice = mouse
/ validresponse = (nextbutton, backbutton)
/ branch = [
    list.trialsequence.nextvalue;
]
</trial>

<text mytext>
/ items = ("<%script.currenttrial%>")
</text>

<button nextbutton>
/ caption = "Next >>"
/ size = (10%, 5%)
/ position = (90%, 90%)
</button>

<button backbutton>
/ caption = "<< Back"
/ size = (10%, 5%)
/ position = (10%, 90%)
</button>
[/code]

RE: creating a back button for randomized trials, not surveypage

Dave — Thu, 12 Aug 2021 17:13:46 GMT

+x[quote]

[b]nc - 8/12/2021[/b]
Hi--
I'm trying to add a back button for an experiment (NOT a survey page) in order to go back to a previous trial. I generally know how to use conditional logic -- the only problem is that the trials are randomized, so it's not entirely clear which trial to display. The relevant part of the experiment is set up as follows:

3 randomized trials:
<block similar>
/trials = [1-3 = noreplace(6_by_2, 10_by_2, 12_by_2)]
</block>

I'd like to add conditional branching to each of these trials (6_by_2, 10_by_2, 12_by_2) if the back button is pressed, but I don't know how to do this given that *which* trial is the previous trial will depend on how randomization works. Thanks in advance for any help!

[/quote]

Before anyone can propose any answer, you need to spell out what's supposed to happen after someone went back to the previous trial. Suppose the random order is

10_by_2 -> 6_by_2 -> 12_by_2 and then you go back from 12_by_2 to 6_by_2. What happens after that second instance of 6_by_2 then? Another instance of 12_by_2? Nothing? Another random trial?

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creating a back button for randomized trials, not surveypage

RE: creating a back button for randomized trials, not surveypage

RE: creating a back button for randomized trials, not surveypage