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RE: The mod() function returns the integer remainder of a division

Blackadder — Wed, 24 Mar 2010 09:42:26 GMT

Oh, and by the way, this is not at all a complaint, I applaude this discrepancy to the manual. The fraction part of a division can easily be computed by

fpart(a/b)

while mirroring the "normal" mod() behavior with a mod function as described in the manual is a tad more irky.

Bye, Malte.

RE: The mod() function returns the integer remainder of a division

Dave — Wed, 24 Mar 2010 09:38:16 GMT

[quote]Inquisit's mod() function computes the integer remainder of a division[/quote]

... as any well-behaved mod function should do. But indeed, you are correct in that the documentation is wrong.

~Dave

The mod() function returns the integer remainder of a division

Blackadder — Wed, 24 Mar 2010 09:28:47 GMT

Just a quick note: other than stated in the help, Inquisit's mod() function computes the integer remainder of a division.

Examples

mod(1,2) = 1
mod(2,9) = 2
mod(11,4) = 3

I haven't tested what mod(3.14,2) would yield but I assume it to be 1.14.

Bye, Malte