+xHej!
Actiually I have no idea, how this can work...:
I got 2 Diff_Scores:
Cat1: medianlatency_AAT_1 - medianlatency_AAT_2
Cat 2: medianlatency_AAT_3 - medianlatency_AAT_4
and
4 categories: medianRT_AAT_1, medianRT_AAT_2, medianRT_AAT_3, medianRT_AAT_4,
BUT: If I put medianRT in Excel for calculating a Diff_Score myself, it's not the same value I got in my summary file... I also tried this without the error vaules.
I tried to got a medianlatency for each of the 4 categories, but it didn't work.
Is there a difference in latency and RT?
How could I calculate myself a Diff-Score which is simular to the summary file?
Sorry because of my english, its not my mothertongue...
Thank you very much for help!!
Anni
The latencies those scores are calculated on are the latencies from the <trial> elements AAT_1 to AAT_8
<trial AAT_1>
...
/ ontrialend = [
...;
if (
trial.AAT_1.correct) {
list.AAT1correctlatencies.insertitem(
trial.AAT_1.latency, 1);
...;};
]
...
</trial>
Only correct trials are considered.
> Is there a difference in latency and RT?
No. values.RT captures the same thing:
<trial AAT_1>
...
/ ontrialend = [
...
values.RT = trial.AAT_1.latency; values.correct = trial.AAT_1.correct;
...
]
...
</trial>
So, in summary, calculating the median of RTs for all _correct_ instances of <trial AAT_1>, <trial AAT_2>, etc. and then calculating the difference should give you the same result. Note, though, that the order of terms in the difference calculation varies according to the experimental condition (values.expcondition):
<expressions>
...
/ AAT_Diffscore_Cat1 = if (
values.expcondition == 1) list.
AAT1correctlatencies.median - list.
AAT2correctlatencies.median else
list.
AAT2correctlatencies.median - list.
AAT1correctlatencies.median
...
</expressions>
median latency of AAT_1 - median latency of AAT_2 in the 1st condition, and
median latency of AAT_2 - median latency of AAT_1 in the 2nd condition.
(Analogously for the other categories / difference scores.)
Hope this helps.