Selene_MQ
|
|
Group: Forum Members
Posts: 17,
Visits: 42
|
Good morning,
I am very new to Inquisit and still not familiar with how it works. I have been trying to adapt the existing Emotional-n-back task that I got from the library, to create a simple 1-back task using 56 different images. The idea is for participants to implicitely learn these images by doing a 1-back task. So far, the script seems to be doing approximately what I want, except that when I calculated at the end the number of times each image was presented, it varied greatly (with 8 blocks, and 64 images per block, I would expect each of my 56 images to appear about 9 times, but in reality it varied between 2 and 23). I really don't know how to control this so that each image appears the same number of times across the experiment.
I have attached the script to this post, and would greatly appreciate any help you may provide,
Thank you so much in advance, Selene
|
|
|
Dave
|
|
Group: Administrators
Posts: 13K,
Visits: 104K
|
+xGood morning, I am very new to Inquisit and still not familiar with how it works. I have been trying to adapt the existing Emotional-n-back task that I got from the library, to create a simple 1-back task using 56 different images. The idea is for participants to implicitely learn these images by doing a 1-back task. So far, the script seems to be doing approximately what I want, except that when I calculated at the end the number of times each image was presented, it varied greatly (with 8 blocks, and 64 images per block, I would expect each of my 56 images to appear about 9 times, but in reality it varied between 2 and 23). I really don't know how to control this so that each image appears the same number of times across the experiment. I have attached the script to this post, and would greatly appreciate any help you may provide, Thank you so much in advance, Selene <list notargetvalue> / items = (1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56) / not = (values.currenttarget) / replace = true</list> You're sampling items randomly *with* replacement. If you want a more even distribution, sample without replacement.
|
|
|
Selene_MQ
|
|
Group: Forum Members
Posts: 17,
Visits: 42
|
+x+xGood morning, I am very new to Inquisit and still not familiar with how it works. I have been trying to adapt the existing Emotional-n-back task that I got from the library, to create a simple 1-back task using 56 different images. The idea is for participants to implicitely learn these images by doing a 1-back task. So far, the script seems to be doing approximately what I want, except that when I calculated at the end the number of times each image was presented, it varied greatly (with 8 blocks, and 64 images per block, I would expect each of my 56 images to appear about 9 times, but in reality it varied between 2 and 23). I really don't know how to control this so that each image appears the same number of times across the experiment. I have attached the script to this post, and would greatly appreciate any help you may provide, Thank you so much in advance, Selene <list notargetvalue> / items = (1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56) / not = (values.currenttarget) / replace = true</list> You're sampling items randomly *with* replacement. If you want a more even distribution, sample without replacement. Thanks a lot for that. It does make it slightly better, but there is still a large variation in the number of times each image is seen (from 7 to 18 times instead of having them all presented 9 times). Is there another way to make it more even, that doesn't require massive changes in the script? Thank you so much! Selene
|
|
|
Dave
|
|
Group: Administrators
Posts: 13K,
Visits: 104K
|
+x+x+xGood morning, I am very new to Inquisit and still not familiar with how it works. I have been trying to adapt the existing Emotional-n-back task that I got from the library, to create a simple 1-back task using 56 different images. The idea is for participants to implicitely learn these images by doing a 1-back task. So far, the script seems to be doing approximately what I want, except that when I calculated at the end the number of times each image was presented, it varied greatly (with 8 blocks, and 64 images per block, I would expect each of my 56 images to appear about 9 times, but in reality it varied between 2 and 23). I really don't know how to control this so that each image appears the same number of times across the experiment. I have attached the script to this post, and would greatly appreciate any help you may provide, Thank you so much in advance, Selene <list notargetvalue> / items = (1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56) / not = (values.currenttarget) / replace = true</list> You're sampling items randomly *with* replacement. If you want a more even distribution, sample without replacement. Thanks a lot for that. It does make it slightly better, but there is still a large variation in the number of times each image is seen (from 7 to 18 times instead of having them all presented 9 times). Is there another way to make it more even, that doesn't require massive changes in the script? Thank you so much! Selene Well, it's an n-back task. I.e. some images *have* to be repeated more than others, because they're target images, i.e. the same image as than n (here: 1) trials before. Other images aren't targets, so will ultimately be displayed less often, because -- among other things -- there are fewer target trials than there are non-target trials. In short, no, I don't think there's any easy way to force each image to be displayed exactly (or close to) 9 times over the course of the task. In fact, I don't know that there's any way at all.
|
|
|
Selene_MQ
|
|
Group: Forum Members
Posts: 17,
Visits: 42
|
+x+x+x+xGood morning, I am very new to Inquisit and still not familiar with how it works. I have been trying to adapt the existing Emotional-n-back task that I got from the library, to create a simple 1-back task using 56 different images. The idea is for participants to implicitely learn these images by doing a 1-back task. So far, the script seems to be doing approximately what I want, except that when I calculated at the end the number of times each image was presented, it varied greatly (with 8 blocks, and 64 images per block, I would expect each of my 56 images to appear about 9 times, but in reality it varied between 2 and 23). I really don't know how to control this so that each image appears the same number of times across the experiment. I have attached the script to this post, and would greatly appreciate any help you may provide, Thank you so much in advance, Selene <list notargetvalue> / items = (1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56) / not = (values.currenttarget) / replace = true</list> You're sampling items randomly *with* replacement. If you want a more even distribution, sample without replacement. Thanks a lot for that. It does make it slightly better, but there is still a large variation in the number of times each image is seen (from 7 to 18 times instead of having them all presented 9 times). Is there another way to make it more even, that doesn't require massive changes in the script? Thank you so much! Selene Well, it's an n-back task. I.e. some images *have* to be repeated more than others, because they're target images, i.e. the same image as than n (here: 1) trials before. Other images aren't targets, so will ultimately be displayed less often, because -- among other things -- there are fewer target trials than there are non-target trials. In short, no, I don't think there's any easy way to force each image to be displayed exactly (or close to) 9 times over the course of the task. In fact, I don't know that there's any way at all. Thanks for your answer. I do understand that the targets have to be repeated, but because each image in the pool can be a target (i.e. there isn't a separate pool of images that constitute the non-target images), I think it's possible to think of a solution that will present each image exactly as many times as possible. So my new question is: if I can figure out an order of presentation that works (for example: 4 6 8 8 5 9 1 12 13 13 etc... over the entire experiment), how easy is it to then hard-code the order in the script? Thanks a lot!
|
|
|
Dave
|
|
Group: Administrators
Posts: 13K,
Visits: 104K
|
+x+x+x+x+xGood morning, I am very new to Inquisit and still not familiar with how it works. I have been trying to adapt the existing Emotional-n-back task that I got from the library, to create a simple 1-back task using 56 different images. The idea is for participants to implicitely learn these images by doing a 1-back task. So far, the script seems to be doing approximately what I want, except that when I calculated at the end the number of times each image was presented, it varied greatly (with 8 blocks, and 64 images per block, I would expect each of my 56 images to appear about 9 times, but in reality it varied between 2 and 23). I really don't know how to control this so that each image appears the same number of times across the experiment. I have attached the script to this post, and would greatly appreciate any help you may provide, Thank you so much in advance, Selene <list notargetvalue> / items = (1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56) / not = (values.currenttarget) / replace = true</list> You're sampling items randomly *with* replacement. If you want a more even distribution, sample without replacement. Thanks a lot for that. It does make it slightly better, but there is still a large variation in the number of times each image is seen (from 7 to 18 times instead of having them all presented 9 times). Is there another way to make it more even, that doesn't require massive changes in the script? Thank you so much! Selene Well, it's an n-back task. I.e. some images *have* to be repeated more than others, because they're target images, i.e. the same image as than n (here: 1) trials before. Other images aren't targets, so will ultimately be displayed less often, because -- among other things -- there are fewer target trials than there are non-target trials. In short, no, I don't think there's any easy way to force each image to be displayed exactly (or close to) 9 times over the course of the task. In fact, I don't know that there's any way at all. Thanks for your answer. I do understand that the targets have to be repeated, but because each image in the pool can be a target (i.e. there isn't a separate pool of images that constitute the non-target images), I think it's possible to think of a solution that will present each image exactly as many times as possible. So my new question is: if I can figure out an order of presentation that works (for example: 4 6 8 8 5 9 1 12 13 13 etc... over the entire experiment), how easy is it to then hard-code the order in the script? Thanks a lot! You have to hardcode two things, then. - The full item order in the non-target list, and set it to /selectionmode = sequence - The order of target and non-target trials run by the blocks. That you'll then also have to switch to a list, and set it to sequence. That's not necessarily hard, but fiddly and error-prone given the amount of trials.
|
|
|
Selene_MQ
|
|
Group: Forum Members
Posts: 17,
Visits: 42
|
+x+x+x+x+x+xGood morning, I am very new to Inquisit and still not familiar with how it works. I have been trying to adapt the existing Emotional-n-back task that I got from the library, to create a simple 1-back task using 56 different images. The idea is for participants to implicitely learn these images by doing a 1-back task. So far, the script seems to be doing approximately what I want, except that when I calculated at the end the number of times each image was presented, it varied greatly (with 8 blocks, and 64 images per block, I would expect each of my 56 images to appear about 9 times, but in reality it varied between 2 and 23). I really don't know how to control this so that each image appears the same number of times across the experiment. I have attached the script to this post, and would greatly appreciate any help you may provide, Thank you so much in advance, Selene <list notargetvalue> / items = (1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56) / not = (values.currenttarget) / replace = true</list> You're sampling items randomly *with* replacement. If you want a more even distribution, sample without replacement. Thanks a lot for that. It does make it slightly better, but there is still a large variation in the number of times each image is seen (from 7 to 18 times instead of having them all presented 9 times). Is there another way to make it more even, that doesn't require massive changes in the script? Thank you so much! Selene Well, it's an n-back task. I.e. some images *have* to be repeated more than others, because they're target images, i.e. the same image as than n (here: 1) trials before. Other images aren't targets, so will ultimately be displayed less often, because -- among other things -- there are fewer target trials than there are non-target trials. In short, no, I don't think there's any easy way to force each image to be displayed exactly (or close to) 9 times over the course of the task. In fact, I don't know that there's any way at all. Thanks for your answer. I do understand that the targets have to be repeated, but because each image in the pool can be a target (i.e. there isn't a separate pool of images that constitute the non-target images), I think it's possible to think of a solution that will present each image exactly as many times as possible. So my new question is: if I can figure out an order of presentation that works (for example: 4 6 8 8 5 9 1 12 13 13 etc... over the entire experiment), how easy is it to then hard-code the order in the script? Thanks a lot! You have to hardcode two things, then. - The full item order in the non-target list, and set it to /selectionmode = sequence - The order of target and non-target trials run by the blocks. That you'll then also have to switch to a list, and set it to sequence. That's not necessarily hard, but fiddly and error-prone given the amount of trials. Thank you very much for your answer, Dave. I generated, for each of the 8 blocks, the sequence that I want, and have also generated for each block a vector with the order of Target/Non-target that matches my sequence. I am not sure how to implement it, because each of the 8 blocks will have a different sequence... Would you please be able to help with this? I have attached the script, and under the "LIST" tab, you can see the orders that I generated. Thank you so much for your help, Selene
|
|
|
Dave
|
|
Group: Administrators
Posts: 13K,
Visits: 104K
|
+x+x+x+x+x+x+xGood morning, I am very new to Inquisit and still not familiar with how it works. I have been trying to adapt the existing Emotional-n-back task that I got from the library, to create a simple 1-back task using 56 different images. The idea is for participants to implicitely learn these images by doing a 1-back task. So far, the script seems to be doing approximately what I want, except that when I calculated at the end the number of times each image was presented, it varied greatly (with 8 blocks, and 64 images per block, I would expect each of my 56 images to appear about 9 times, but in reality it varied between 2 and 23). I really don't know how to control this so that each image appears the same number of times across the experiment. I have attached the script to this post, and would greatly appreciate any help you may provide, Thank you so much in advance, Selene <list notargetvalue> / items = (1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56) / not = (values.currenttarget) / replace = true</list> You're sampling items randomly *with* replacement. If you want a more even distribution, sample without replacement. Thanks a lot for that. It does make it slightly better, but there is still a large variation in the number of times each image is seen (from 7 to 18 times instead of having them all presented 9 times). Is there another way to make it more even, that doesn't require massive changes in the script? Thank you so much! Selene Well, it's an n-back task. I.e. some images *have* to be repeated more than others, because they're target images, i.e. the same image as than n (here: 1) trials before. Other images aren't targets, so will ultimately be displayed less often, because -- among other things -- there are fewer target trials than there are non-target trials. In short, no, I don't think there's any easy way to force each image to be displayed exactly (or close to) 9 times over the course of the task. In fact, I don't know that there's any way at all. Thanks for your answer. I do understand that the targets have to be repeated, but because each image in the pool can be a target (i.e. there isn't a separate pool of images that constitute the non-target images), I think it's possible to think of a solution that will present each image exactly as many times as possible. So my new question is: if I can figure out an order of presentation that works (for example: 4 6 8 8 5 9 1 12 13 13 etc... over the entire experiment), how easy is it to then hard-code the order in the script? Thanks a lot! You have to hardcode two things, then. - The full item order in the non-target list, and set it to /selectionmode = sequence - The order of target and non-target trials run by the blocks. That you'll then also have to switch to a list, and set it to sequence. That's not necessarily hard, but fiddly and error-prone given the amount of trials. Thank you very much for your answer, Dave. I generated, for each of the 8 blocks, the sequence that I want, and have also generated for each block a vector with the order of Target/Non-target that matches my sequence. I am not sure how to implement it, because each of the 8 blocks will have a different sequence... Would you please be able to help with this? I have attached the script, and under the "LIST" tab, you can see the orders that I generated. Thank you so much for your help, Selene You can creat lists of lists and select the list you need /onblockbegin. See e.g. https://www.millisecond.com/forums/Topic16652.aspx#16717, https://www.millisecond.com/forums/FindPost20679.aspx
|
|
|
Selene_MQ
|
|
Group: Forum Members
Posts: 17,
Visits: 42
|
+x+x+x+x+x+x+x+xGood morning, I am very new to Inquisit and still not familiar with how it works. I have been trying to adapt the existing Emotional-n-back task that I got from the library, to create a simple 1-back task using 56 different images. The idea is for participants to implicitely learn these images by doing a 1-back task. So far, the script seems to be doing approximately what I want, except that when I calculated at the end the number of times each image was presented, it varied greatly (with 8 blocks, and 64 images per block, I would expect each of my 56 images to appear about 9 times, but in reality it varied between 2 and 23). I really don't know how to control this so that each image appears the same number of times across the experiment. I have attached the script to this post, and would greatly appreciate any help you may provide, Thank you so much in advance, Selene <list notargetvalue> / items = (1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56) / not = (values.currenttarget) / replace = true</list> You're sampling items randomly *with* replacement. If you want a more even distribution, sample without replacement. Thanks a lot for that. It does make it slightly better, but there is still a large variation in the number of times each image is seen (from 7 to 18 times instead of having them all presented 9 times). Is there another way to make it more even, that doesn't require massive changes in the script? Thank you so much! Selene Well, it's an n-back task. I.e. some images *have* to be repeated more than others, because they're target images, i.e. the same image as than n (here: 1) trials before. Other images aren't targets, so will ultimately be displayed less often, because -- among other things -- there are fewer target trials than there are non-target trials. In short, no, I don't think there's any easy way to force each image to be displayed exactly (or close to) 9 times over the course of the task. In fact, I don't know that there's any way at all. Thanks for your answer. I do understand that the targets have to be repeated, but because each image in the pool can be a target (i.e. there isn't a separate pool of images that constitute the non-target images), I think it's possible to think of a solution that will present each image exactly as many times as possible. So my new question is: if I can figure out an order of presentation that works (for example: 4 6 8 8 5 9 1 12 13 13 etc... over the entire experiment), how easy is it to then hard-code the order in the script? Thanks a lot! You have to hardcode two things, then. - The full item order in the non-target list, and set it to /selectionmode = sequence - The order of target and non-target trials run by the blocks. That you'll then also have to switch to a list, and set it to sequence. That's not necessarily hard, but fiddly and error-prone given the amount of trials. Thank you very much for your answer, Dave. I generated, for each of the 8 blocks, the sequence that I want, and have also generated for each block a vector with the order of Target/Non-target that matches my sequence. I am not sure how to implement it, because each of the 8 blocks will have a different sequence... Would you please be able to help with this? I have attached the script, and under the "LIST" tab, you can see the orders that I generated. Thank you so much for your help, Selene You can creat lists of lists and select the list you need /onblockbegin. See e.g. https://www.millisecond.com/forums/Topic16652.aspx#16717, https://www.millisecond.com/forums/FindPost20679.aspx Thanks for your answer Dace. I had a look at these posts and try to adapt it to my code. I think I'm not too far off, but it just won't start. Now it throws an error when it reaches the blocks : "Could not locate element ". " and "trial 2 is unassigned" for each of the blocks. Any idea where I sent wrong? Thanks so much!
|
|
|
Dave
|
|
Group: Administrators
Posts: 13K,
Visits: 104K
|
+x+x+x+x+x+x+x+x+xGood morning, I am very new to Inquisit and still not familiar with how it works. I have been trying to adapt the existing Emotional-n-back task that I got from the library, to create a simple 1-back task using 56 different images. The idea is for participants to implicitely learn these images by doing a 1-back task. So far, the script seems to be doing approximately what I want, except that when I calculated at the end the number of times each image was presented, it varied greatly (with 8 blocks, and 64 images per block, I would expect each of my 56 images to appear about 9 times, but in reality it varied between 2 and 23). I really don't know how to control this so that each image appears the same number of times across the experiment. I have attached the script to this post, and would greatly appreciate any help you may provide, Thank you so much in advance, Selene <list notargetvalue> / items = (1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56) / not = (values.currenttarget) / replace = true</list> You're sampling items randomly *with* replacement. If you want a more even distribution, sample without replacement. Thanks a lot for that. It does make it slightly better, but there is still a large variation in the number of times each image is seen (from 7 to 18 times instead of having them all presented 9 times). Is there another way to make it more even, that doesn't require massive changes in the script? Thank you so much! Selene Well, it's an n-back task. I.e. some images *have* to be repeated more than others, because they're target images, i.e. the same image as than n (here: 1) trials before. Other images aren't targets, so will ultimately be displayed less often, because -- among other things -- there are fewer target trials than there are non-target trials. In short, no, I don't think there's any easy way to force each image to be displayed exactly (or close to) 9 times over the course of the task. In fact, I don't know that there's any way at all. Thanks for your answer. I do understand that the targets have to be repeated, but because each image in the pool can be a target (i.e. there isn't a separate pool of images that constitute the non-target images), I think it's possible to think of a solution that will present each image exactly as many times as possible. So my new question is: if I can figure out an order of presentation that works (for example: 4 6 8 8 5 9 1 12 13 13 etc... over the entire experiment), how easy is it to then hard-code the order in the script? Thanks a lot! You have to hardcode two things, then. - The full item order in the non-target list, and set it to /selectionmode = sequence - The order of target and non-target trials run by the blocks. That you'll then also have to switch to a list, and set it to sequence. That's not necessarily hard, but fiddly and error-prone given the amount of trials. Thank you very much for your answer, Dave. I generated, for each of the 8 blocks, the sequence that I want, and have also generated for each block a vector with the order of Target/Non-target that matches my sequence. I am not sure how to implement it, because each of the 8 blocks will have a different sequence... Would you please be able to help with this? I have attached the script, and under the "LIST" tab, you can see the orders that I generated. Thank you so much for your help, Selene You can creat lists of lists and select the list you need /onblockbegin. See e.g. https://www.millisecond.com/forums/Topic16652.aspx#16717, https://www.millisecond.com/forums/FindPost20679.aspx Thanks for your answer Dace. I had a look at these posts and try to adapt it to my code. I think I'm not too far off, but it just won't start. Now it throws an error when it reaches the blocks : "Could not locate element ". " and "trial 2 is unassigned" for each of the blocks. Any idea where I sent wrong? Thanks so much! Your /trials attributs in the blocks are all misspecified. / trials = [1 = startfixation ; 2 - 66 = (nontarget, nontarget, nontarget, nontarget, ...)]
To run the sequence you specifed, it ought to be / trials = [1 = startfixation; 2 = sequence(nontarget, nontarget, nontarget, nontarget, ...)]
|
|
|