By raven - 2/6/2024
Hi Dave,
How would I go about presenting certain trials randomly for a given amount of times?
For example, if I want to run TrialA 3 times, TrialB 4 times, and TrialC 5 times, but each trial must be run in random order without being repeated for a total trial count of 12.
I looked at the Inquisit Language Reference for the block and trial elements, to see if this is possible, but the block element only seems to be able to run a certain number of trials sequentially, not randomly, as per the code example:
<block Block1>
/ trials=[1-12=noreplace(1-3=TrialA; 4-7=TrialB; 8-12=TrialC)]
</Block1>
Thank you!
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By Dave - 2/6/2024
+xHi Dave, How would I go about presenting certain trials randomly for a given amount of times? For example, if I want to run TrialA 3 times, TrialB 4 times, and TrialC 5 times, but each trial must be run in random order without being repeated for a total trial count of 12. I looked at the Inquisit Language Reference for the block and trial elements, to see if this is possible, but the block element only seems to be able to run a certain number of trials sequentially, not randomly, as per the code example: <block Block1> / trials=[1-12=noreplace(1-3=TrialA; 4-7=TrialB; 8-12=TrialC)] </Block1> Thank you!
You set up your noreplace() pool with the desired proportions.
/ trials = [1-12 = noreplace(TrialA, TrialA, TrialA, TrialB, TrialB, TrialB, TrialB, TrialC, TrialC, TrialC, TrialC, TrialC)]
This is covered in the documentation, see the examples at https://www.millisecond.com/support/docs/current/html/language/attributes/trials.htm
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By raven - 2/6/2024
+x+xHi Dave, How would I go about presenting certain trials randomly for a given amount of times? For example, if I want to run TrialA 3 times, TrialB 4 times, and TrialC 5 times, but each trial must be run in random order without being repeated for a total trial count of 12. I looked at the Inquisit Language Reference for the block and trial elements, to see if this is possible, but the block element only seems to be able to run a certain number of trials sequentially, not randomly, as per the code example: <block Block1> / trials=[1-12=noreplace(1-3=TrialA; 4-7=TrialB; 8-12=TrialC)] </Block1> Thank you! You set up your noreplace() pool with the desired proportions. / trials = [1-12 = noreplace(TrialA, TrialA, TrialA, TrialB, TrialB, TrialB, TrialB, TrialC, TrialC, TrialC, TrialC, TrialC)] This is covered in the documentation, see the examples at https://www.millisecond.com/support/docs/current/html/language/attributes/trials.htm
Thanks Dave,
That makes sense!
:)
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By raven - 2/7/2024
+x+xHi Dave, How would I go about presenting certain trials randomly for a given amount of times? For example, if I want to run TrialA 3 times, TrialB 4 times, and TrialC 5 times, but each trial must be run in random order without being repeated for a total trial count of 12. I looked at the Inquisit Language Reference for the block and trial elements, to see if this is possible, but the block element only seems to be able to run a certain number of trials sequentially, not randomly, as per the code example: <block Block1> / trials=[1-12=noreplace(1-3=TrialA; 4-7=TrialB; 8-12=TrialC)] </Block1> Thank you! You set up your noreplace() pool with the desired proportions. / trials = [1-12 = noreplace(TrialA, TrialA, TrialA, TrialB, TrialB, TrialB, TrialB, TrialC, TrialC, TrialC, TrialC, TrialC)] This is covered in the documentation, see the examples at https://www.millisecond.com/support/docs/current/html/language/attributes/trials.htm
Hi Dave,
I've been testing the above that you recommended, but not getting the desired result.
For example, with the following code, I would like TrialA's to be presented 12 times (e.g., TrialA1 and TrialA2 in the 3/4 ratio, so that TrialA1 is shown 9 times and TrialA2 is shown 3 times), Trial B's 12 times (with the respective 3/4 ratio), TrialC's 12 times (with the respective 1/2 ratio), and Trial D's 12 times (with the respective 1/2 ratio).
/ trials = [1-48 = noreplace(TrialA1, TrialA1, TrialA1, TrailA2, TrialB1, TrialB1, TrialB1, TrialB2, TrialC1, TrialC2, TrialD1, TrialD2)]
How is this possible?
Thanks!
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By Dave - 2/7/2024
+x+x+xHi Dave, How would I go about presenting certain trials randomly for a given amount of times? For example, if I want to run TrialA 3 times, TrialB 4 times, and TrialC 5 times, but each trial must be run in random order without being repeated for a total trial count of 12. I looked at the Inquisit Language Reference for the block and trial elements, to see if this is possible, but the block element only seems to be able to run a certain number of trials sequentially, not randomly, as per the code example: <block Block1> / trials=[1-12=noreplace(1-3=TrialA; 4-7=TrialB; 8-12=TrialC)] </Block1> Thank you! You set up your noreplace() pool with the desired proportions. / trials = [1-12 = noreplace(TrialA, TrialA, TrialA, TrialB, TrialB, TrialB, TrialB, TrialC, TrialC, TrialC, TrialC, TrialC)] This is covered in the documentation, see the examples at https://www.millisecond.com/support/docs/current/html/language/attributes/trials.htm Hi Dave, I've been testing the above that you recommended, but not getting the desired result. For example, with the following code, I would like TrialA's to be presented 12 times (e.g., TrialA1 and TrialA2 in the 3/4 ratio, so that TrialA1 is shown 9 times and TrialA2 is shown 3 times), Trial B's 12 times (with the respective 3/4 ratio), TrialC's 12 times (with the respective 1/2 ratio), and Trial D's 12 times (with the respective 1/2 ratio). / trials = [1-48 = noreplace(TrialA1, TrialA1, TrialA1, TrailA2, TrialB1, TrialB1, TrialB1, TrialB2, TrialC1, TrialC2, TrialD1, TrialD2)] How is this possible? Thanks!
You have 12 entries in the pool. 48/12 = 4, .i.e. each entry stands for 4 trials. You'll get 3 x 4 = 12 TrialA1, 1 x 4 = 4 = TrialA2, 3 x 4 = 12 TrialB1, 1 x 4 = TrialB2, 4 x TrialC1, 4 x TrialC2, 4 x TrialD1, and 4 x TrialD2.
If you want something else, adjust accordingly.
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By raven - 2/7/2024
+x+x+x+xHi Dave, How would I go about presenting certain trials randomly for a given amount of times? For example, if I want to run TrialA 3 times, TrialB 4 times, and TrialC 5 times, but each trial must be run in random order without being repeated for a total trial count of 12. I looked at the Inquisit Language Reference for the block and trial elements, to see if this is possible, but the block element only seems to be able to run a certain number of trials sequentially, not randomly, as per the code example: <block Block1> / trials=[1-12=noreplace(1-3=TrialA; 4-7=TrialB; 8-12=TrialC)] </Block1> Thank you! You set up your noreplace() pool with the desired proportions. / trials = [1-12 = noreplace(TrialA, TrialA, TrialA, TrialB, TrialB, TrialB, TrialB, TrialC, TrialC, TrialC, TrialC, TrialC)] This is covered in the documentation, see the examples at https://www.millisecond.com/support/docs/current/html/language/attributes/trials.htm Hi Dave, I've been testing the above that you recommended, but not getting the desired result. For example, with the following code, I would like TrialA's to be presented 12 times (e.g., TrialA1 and TrialA2 in the 3/4 ratio, so that TrialA1 is shown 9 times and TrialA2 is shown 3 times), Trial B's 12 times (with the respective 3/4 ratio), TrialC's 12 times (with the respective 1/2 ratio), and Trial D's 12 times (with the respective 1/2 ratio). / trials = [1-48 = noreplace(TrialA1, TrialA1, TrialA1, TrailA2, TrialB1, TrialB1, TrialB1, TrialB2, TrialC1, TrialC2, TrialD1, TrialD2)] How is this possible? Thanks! You have 12 entries in the pool. 48/12 = 4, .i.e. each entry stands for 4 trials. You'll get 3 x 4 = 12 TrialA1, 1 x 4 = 4 = TrialA2, 3 x 4 = 12 TrialB1, 1 x 4 = TrialB2, 4 x TrialC1, 4 x TrialC2, 4 x TrialD1, and 4 x TrialD2. If you want something else, adjust accordingly.
Thanks Dave
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