Terminate Experiment After Elapsed Time X

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Terminate Experiment After Elapsed Time X

Terminate Experiment After Elapsed Time X

Author	Message
DCole9	DCole9 posted 9 Years Ago ANSWER Post Details Share Post
Group: Forum Members Posts: 42, Visits: 220	Thanks for the response Dave. /stop seems suitable for me.
	Reply Like 55
Dave	Dave posted 9 Years Ago ANSWER Post Details Share Post
Group: Administrators Posts: 13K, Visits: 104K	<trial> ... /branch = [if (expt.myexpt.elapsedtime < 810000) block.theblock)] </trial> You cannot branch from a trial to a block. Branches must be at the same level, i.e. a trial can branch to another trial, a block can branch to another block. The /stop attribute will not interrupt the currently running trial. It will only kick in once the trial terminates. If you want a hard interrupt, use the /timeout attribute.
	Reply Like 47
DCole9	DCole9 posted 9 Years Ago ANSWER Post Details Share Post
Group: Forum Members Posts: 42, Visits: 220	I discovered the stop command--- seems to work well. I was testing it in my experiment section and set it to stop the experiment after just 1 second. However I noticed that the experiment continues well beyond one second. Does it always finish the current block/trial/etc. before it terminates?
	Reply Like 52
DCole9	DCole9 posted 9 Years Ago Topic Details Share Topic
Group: Forum Members Posts: 42, Visits: 220	Hey Inquisiters, I'm trying to have my experiment terminate itself after expt.name.elapsedtime becomes > a certain duration. I tried doing the following. <trial> ... /branch = [if (expt.myexpt.elapsedtime < 810000) block.theblock)] </trial> <exp myexptt> /blocks [1 = theblock] </expt> This is giving me the error that block.theblock is the wrong element type. I suspect that is because I am trying to branch to a block from a trial? I have to code my experiment this way b/c my trials refresh on each button press (fills a bar). So I have blocks as my "trials". Is there a way to 'break' the experiment with a certain command or to branch to a block from a trial? Maybe there is something I am missing. Thanks for your time, Dan
	Reply Like 51