Millisecond Forums

You set the the various <picture> elements to specific items based on response in <trial grid>:

<trial grid>
/ ontrialbegin = [values.cross_num += 1]
/ inputdevice = mouse
/ stimulusframes = [1=grid, 1.1,1.2,1.3,2.1,2.2,2.3,3.1,3.2,3.3]
/ validresponse = (1.1,1.2,1.3,2.1,2.2,2.3,3.1,3.2,3.3)
/ ontrialbegin =
     [if (trial.grid.response == "1.1") {picture.1.1.item.1 = picture.x.item.1}
else if (trial.grid.response == "1.2") {picture.1.2.item.1 = picture.x.item.1}
else if (trial.grid.response == "1.3") {picture.1.3.item.1 = picture.x.item.1}

else if (trial.grid.response == "2.1") {picture.2.1.item.1 = picture.x.item.1}
else if (trial.grid.response == "2.2") {picture.2.2.item.1 = picture.x.item.1}
else if (trial.grid.response == "2.3") {picture.2.3.item.1 = picture.x.item.1}

else if (trial.grid.response == "3.1") {picture.3.1.item.1 = picture.x.item.1}
else if (trial.grid.response == "3.2") {picture.3.2.item.1 = picture.x.item.1}
else if (trial.grid.response == "3.3") {picture.3.3.item.1 = picture.x.item.1}]
/ branch = [if (values.cross_num < 3) trial.grid]
</trial>

You need to reverse that at the start of each "round", i.e. /onblockbegin set the various picture elements *back* to their original items.

<block verbal_experiment>
/ onblockbegin = [
    picture.1.1.item.1 = picture.square.item.1;
    picture.1.2.item.1 = picture.square.item.1;
    picture.1.3.item.1 = picture.square.item.1;
    picture.2.1.item.1 = picture.square.item.1;
    picture.2.2.item.1 = picture.square.item.1;
    picture.2.3.item.1 = picture.square.item.1;
    picture.3.1.item.1 = picture.square.item.1;
    picture.3.2.item.1 = picture.square.item.1;
    picture.3.3.item.1 = picture.square.item.1;
]
/ trials = [1 = easy; 2 = verbal; 3= grid; 4= pause]
</block>

<picture square>
/ items = ("square.png")
</picture>

Hello,

Many thanks for your reply,

I have done that, but from the second block (in the part 3. when the participant should click on three squares, you can see the last cross that the participant clicked)...Is it possible to show just an empty grid at the beginning of each part 3. (so the participant can reproduce the pattern see in part1.)?

Thanks,

Elena

> (in the part 3. when the participant should click on three squares, you can see the last cross that the participant clicked).

The problem is that you perform the logic in <trial grid> /ontrialbegin. It will thus carry over from the last instance of the trial in the previous round.

<trial grid>
/ ontrialbegin = [values.cross_num += 1]
/ inputdevice = mouse
/ stimulusframes = [1=grid, 1.1,1.2,1.3,2.1,2.2,2.3,3.1,3.2,3.3]
/ validresponse = (1.1,1.2,1.3,2.1,2.2,2.3,3.1,3.2,3.3)
/ ontrialbegin =
     [if (trial.grid.response == "1.1") {text.1.1.item.1 = text.x.item.1}
else if (trial.grid.response == "1.2") {text.1.2.item.1 = text.x.item.1}
else if (trial.grid.response == "1.3") {text.1.3.item.1 = text.x.item.1}

else if (trial.grid.response == "2.1") {text.2.1.item.1 = text.x.item.1}
else if (trial.grid.response == "2.2") {text.2.2.item.1 = text.x.item.1}
else if (trial.grid.response == "2.3") {text.2.3.item.1 = text.x.item.1}

else if (trial.grid.response == "3.1") {text.3.1.item.1 = text.x.item.1}
else if (trial.grid.response == "3.2") {text.3.2.item.1 = text.x.item.1}
else if (trial.grid.response == "3.3") {text.3.3.item.1 = text.x.item.1}]
/ branch = [if (values.cross_num < 3) trial.grid]
</trial>

You'll want to perform the logic /ontrialend instead.

<trial grid>
/ ontrialbegin = [values.cross_num += 1]
/ inputdevice = mouse
/ stimulusframes = [1=grid, 1.1,1.2,1.3,2.1,2.2,2.3,3.1,3.2,3.3]
/ validresponse = (1.1,1.2,1.3,2.1,2.2,2.3,3.1,3.2,3.3)
/ ontrialend =
     [if (trial.grid.response == "1.1") {text.1.1.item.1 = text.x.item.1}
else if (trial.grid.response == "1.2") {text.1.2.item.1 = text.x.item.1}
else if (trial.grid.response == "1.3") {text.1.3.item.1 = text.x.item.1}

else if (trial.grid.response == "2.1") {text.2.1.item.1 = text.x.item.1}
else if (trial.grid.response == "2.2") {text.2.2.item.1 = text.x.item.1}
else if (trial.grid.response == "2.3") {text.2.3.item.1 = text.x.item.1}

else if (trial.grid.response == "3.1") {text.3.1.item.1 = text.x.item.1}
else if (trial.grid.response == "3.2") {text.3.2.item.1 = text.x.item.1}
else if (trial.grid.response == "3.3") {text.3.3.item.1 = text.x.item.1}]
/ branch = [if (values.cross_num < 3) trial.grid]
</trial>

That's perfect now, thanks supreme being! A last thing: Is it possible that after the third click the grid stay there for 1 sec, so the participant can see where he/she has put the third cross?

Thank you,

Elena

> 1 sec, so the participant can see where he/she has put the third cross?

Yes. Run another <trial grid> in your <block> that displays the same stimuli as <trial grid>, but is set to accept no response ( /validresponse = (0) ) and last one second ( /trialduration = 1000 ).

Thanks!!

Elena