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Automatically linking vposition and hposition

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Brabagazaa	Brabagazaa posted 7 Years Ago HOT Topic Details Share Topic
Group: Forum Members Posts: 13, Visits: 79	Dear all, I ran into a slight problem and could not find a straightforward solution on the forum. I am drawing multiple items on the screen for each trial, the horizontal positions are in a list and picked at random, however all the shape also need a vertical position and I could not see how to make a list with tuple, something like: list = [(x1, y1), (x2, y2), etc] At the moment I wrote an expression that checks all the possible horizontal positions and matches the correct vertical position to it, so that each picture has the correct combination of vertical position + horizontal position, I was wondering if there might be an easier way to combine these values? Any suggestions would be great, Roelof PS: Attached a simplified example that shows the basic structure, the actual experiment uses set sizes 5,7,9, with all different coordinates, at which point writing the expressions becomes more arduous Attachments experiment_cropped_example_vpos_hpos_coordnates.iqx (673 views, 970 bytes)
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Dave	Dave posted 7 Years Ago ANSWER Post Details Share Post
Group: Administrators Posts: 13K, Visits: 104K	+x Brabagazaa - Tuesday, October 10, 2017 Dear all, I ran into a slight problem and could not find a straightforward solution on the forum. I am drawing multiple items on the screen for each trial, the horizontal positions are in a list and picked at random, however all the shape also need a vertical position and I could not see how to make a list with tuple, something like: list = [(x1, y1), (x2, y2), etc] At the moment I wrote an expression that checks all the possible horizontal positions and matches the correct vertical position to it, so that each picture has the correct combination of vertical position + horizontal position, I was wondering if there might be an easier way to combine these values? Any suggestions would be great, Roelof PS: Attached a simplified example that shows the basic structure, the actual experiment uses set sizes 5,7,9, with all different coordinates, at which point writing the expressions becomes more arduous The trick is to define your position x/y tuples in two linked <list>s instead of trying to use a single one: <list hposition_list_neutral_set7> /items = (20, 26, 50, 73, 79, 63, 36) /selectionmode = random </list> <list vposition_list_set7> /items = (43, 68, 80, 68, 43, 22, 22) / selectionmode = list.hposition_list_neutral_set7.currentindex </list> with <trial neutral> /ontrialbegin = [values.hpos1 = list.hposition_list_neutral_set7.nextvalue; values.vpos1=list.vposition_list_set7.nextvalue] /stimulusframes = [1=target_shape] /validresponse = ("z","m") /pretrialpause = floor(rand(values.jitter_low,values.jitter_high)) </trial> <picture target_shape> / items = c_g / hposition = values.hpos1 / vposition = values.vpos1 </picture> Edited 7 Years Ago by Dave
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Brabagazaa	Brabagazaa posted 7 Years Ago ANSWER Post Details Share Post
Group: Forum Members Posts: 13, Visits: 79	+x Dave - Tuesday, October 10, 2017 +x Brabagazaa - Tuesday, October 10, 2017 Dear all, I ran into a slight problem and could not find a straightforward solution on the forum. I am drawing multiple items on the screen for each trial, the horizontal positions are in a list and picked at random, however all the shape also need a vertical position and I could not see how to make a list with tuple, something like: list = [(x1, y1), (x2, y2), etc] At the moment I wrote an expression that checks all the possible horizontal positions and matches the correct vertical position to it, so that each picture has the correct combination of vertical position + horizontal position, I was wondering if there might be an easier way to combine these values? Any suggestions would be great, Roelof PS: Attached a simplified example that shows the basic structure, the actual experiment uses set sizes 5,7,9, with all different coordinates, at which point writing the expressions becomes more arduous The trick is to define your position x/y tuples in two linked <list>s instead of trying to use a single one: <list hposition_list_neutral_set7> /items = (20, 26, 50, 73, 79, 63, 36) /selectionmode = random </list> <list vposition_list_set7> /items = (43, 68, 80, 68, 43, 22, 22) / selectionmode = list.hposition_list_neutral_set7.currentindex </list> with <trial neutral> /ontrialbegin = [values.hpos1 = list.hposition_list_neutral_set7.nextvalue; values.vpos1=list.vposition_list_set7.nextvalue] /stimulusframes = [1=target_shape] /validresponse = ("z","m") /pretrialpause = floor(rand(values.jitter_low,values.jitter_high)) </trial> <picture target_shape> / items = c_g / hposition = values.hpos1 / vposition = values.vpos1 </picture> That was exaclty what I was looking for, thank you so much
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S F	S F posted 7 Years Ago ANSWER Post Details Share Post
Group: Forum Members Posts: 29, Visits: 175	+x Dave - Tuesday, October 10, 2017 +x Brabagazaa - Tuesday, October 10, 2017 Dear all, I ran into a slight problem and could not find a straightforward solution on the forum. I am drawing multiple items on the screen for each trial, the horizontal positions are in a list and picked at random, however all the shape also need a vertical position and I could not see how to make a list with tuple, something like: list = [(x1, y1), (x2, y2), etc] At the moment I wrote an expression that checks all the possible horizontal positions and matches the correct vertical position to it, so that each picture has the correct combination of vertical position + horizontal position, I was wondering if there might be an easier way to combine these values? Any suggestions would be great, Roelof PS: Attached a simplified example that shows the basic structure, the actual experiment uses set sizes 5,7,9, with all different coordinates, at which point writing the expressions becomes more arduous The trick is to define your position x/y tuples in two linked <list>s instead of trying to use a single one: <list hposition_list_neutral_set7> /items = (20, 26, 50, 73, 79, 63, 36) /selectionmode = random </list> <list vposition_list_set7> /items = (43, 68, 80, 68, 43, 22, 22) / selectionmode = list.hposition_list_neutral_set7.currentindex </list> with <trial neutral> /ontrialbegin = [values.hpos1 = list.hposition_list_neutral_set7.nextvalue; values.vpos1=list.vposition_list_set7.nextvalue] /stimulusframes = [1=target_shape] /validresponse = ("z","m") /pretrialpause = floor(rand(values.jitter_low,values.jitter_high)) </trial> <picture target_shape> / items = c_g / hposition = values.hpos1 / vposition = values.vpos1 </picture> Hi, I'm trying this approach but I can't get it to run- any tips? More generally, I wouldn't have to randomize positions if I could just evaluate whether the item randomly chosen from an element of items matched a string (for correctresponse) but since I couldn't figure that out, evaluating this from the picture name (fixing the picture) worked before, except that it's tricky to randomize position. That's what I'm trying to do in this code, attempting to match this example. Thanks! Attachments script2of5.iqx (572 views, 2.00 KB)
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S F	S F posted 7 Years Ago ANSWER Post Details Share Post
Group: Forum Members Posts: 29, Visits: 175	+x S F - Monday, October 16, 2017 +x Dave - Tuesday, October 10, 2017 +x Brabagazaa - Tuesday, October 10, 2017 Dear all, I ran into a slight problem and could not find a straightforward solution on the forum. I am drawing multiple items on the screen for each trial, the horizontal positions are in a list and picked at random, however all the shape also need a vertical position and I could not see how to make a list with tuple, something like: list = [(x1, y1), (x2, y2), etc] At the moment I wrote an expression that checks all the possible horizontal positions and matches the correct vertical position to it, so that each picture has the correct combination of vertical position + horizontal position, I was wondering if there might be an easier way to combine these values? Any suggestions would be great, Roelof PS: Attached a simplified example that shows the basic structure, the actual experiment uses set sizes 5,7,9, with all different coordinates, at which point writing the expressions becomes more arduous The trick is to define your position x/y tuples in two linked <list>s instead of trying to use a single one: <list hposition_list_neutral_set7> /items = (20, 26, 50, 73, 79, 63, 36) /selectionmode = random </list> <list vposition_list_set7> /items = (43, 68, 80, 68, 43, 22, 22) / selectionmode = list.hposition_list_neutral_set7.currentindex </list> with <trial neutral> /ontrialbegin = [values.hpos1 = list.hposition_list_neutral_set7.nextvalue; values.vpos1=list.vposition_list_set7.nextvalue] /stimulusframes = [1=target_shape] /validresponse = ("z","m") /pretrialpause = floor(rand(values.jitter_low,values.jitter_high)) </trial> <picture target_shape> / items = c_g / hposition = values.hpos1 / vposition = values.vpos1 </picture> Hi, I'm trying this approach but I can't get it to run- any tips? More generally, I wouldn't have to randomize positions if I could just evaluate whether the item randomly chosen from an element of items matched a string (for correctresponse) but since I couldn't figure that out, evaluating this from the picture name (fixing the picture) worked before, except that it's tricky to randomize position. That's what I'm trying to do in this code, attempting to match this example. Thanks! Whoops- I was missing declaring the <values> before. So it works now, but it displays 2 pictures in each spot, overlapping.... <values> / 1h = 0 / 1v = 0 / 2h = 0 / 2v = 0 / 3h = 0 / 3v = 0 / 4h = 0 / 4v = 0 </values> <trial test_pic_trial1> / ontrialbegin = [ values.1h = list.random_hposition1.nextvalue; values.1v = list.random_vposition1.nextvalue; values.2h = list.random_hposition1.nextvalue; values.2v = list.random_vposition1.nextvalue; values.3h = list.random_hposition1.nextvalue; values.3v = list.random_vposition1.nextvalue; values.4h = list.random_hposition1.nextvalue; values.4v = list.random_vposition1.nextvalue; ] / stimulusframes=[1=correct1, incorrect1_2, incorrect1_3, incorrect1_4] / inputdevice=mouse / validresponse=(correct1, incorrect1_2, incorrect1_3, incorrect1_4) / correctresponse= (correct1) </trial> <block test1> /trials = [1=test_pic_trial1] </block> <picture correct1> / items = ("cap1.jpg") / size = (213, 280) / position = (values.1h, values.1v) </picture> <picture incorrect1_2> / items = ("cappen.jpg") / size = (213, 280) / position = (values.2h, values.2v) </picture> <picture incorrect1_3> / items = ("bottlecap.jpg") / size = (213, 280) / position = (values.3h, values.3v) </picture> <picture incorrect1_4> / items = ("pear.jpg") / size = (213, 280) / position = (values.4h, values.4v) </picture> <list random_hposition1> / items = (25, 25, 75, 75) / selectionrate = always / selectionmode = random / replace = false </list> <list random_vposition1> / items = (25, 75, 75, 25) / selectionmode = list.random_hposition1.currentindex </list>
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Dave	Dave posted 7 Years Ago ANSWER Post Details Share Post
Group: Administrators Posts: 13K, Visits: 104K	+x S F - Monday, October 16, 2017 +x S F - Monday, October 16, 2017 +x Dave - Tuesday, October 10, 2017 +x Brabagazaa - Tuesday, October 10, 2017 Dear all, I ran into a slight problem and could not find a straightforward solution on the forum. I am drawing multiple items on the screen for each trial, the horizontal positions are in a list and picked at random, however all the shape also need a vertical position and I could not see how to make a list with tuple, something like: list = [(x1, y1), (x2, y2), etc] At the moment I wrote an expression that checks all the possible horizontal positions and matches the correct vertical position to it, so that each picture has the correct combination of vertical position + horizontal position, I was wondering if there might be an easier way to combine these values? Any suggestions would be great, Roelof PS: Attached a simplified example that shows the basic structure, the actual experiment uses set sizes 5,7,9, with all different coordinates, at which point writing the expressions becomes more arduous The trick is to define your position x/y tuples in two linked <list>s instead of trying to use a single one: <list hposition_list_neutral_set7> /items = (20, 26, 50, 73, 79, 63, 36) /selectionmode = random </list> <list vposition_list_set7> /items = (43, 68, 80, 68, 43, 22, 22) / selectionmode = list.hposition_list_neutral_set7.currentindex </list> with <trial neutral> /ontrialbegin = [values.hpos1 = list.hposition_list_neutral_set7.nextvalue; values.vpos1=list.vposition_list_set7.nextvalue] /stimulusframes = [1=target_shape] /validresponse = ("z","m") /pretrialpause = floor(rand(values.jitter_low,values.jitter_high)) </trial> <picture target_shape> / items = c_g / hposition = values.hpos1 / vposition = values.vpos1 </picture> Hi, I'm trying this approach but I can't get it to run- any tips? More generally, I wouldn't have to randomize positions if I could just evaluate whether the item randomly chosen from an element of items matched a string (for correctresponse) but since I couldn't figure that out, evaluating this from the picture name (fixing the picture) worked before, except that it's tricky to randomize position. That's what I'm trying to do in this code, attempting to match this example. Thanks! Whoops- I was missing declaring the <values> before. So it works now, but it displays 2 pictures in each spot, overlapping.... <values> / 1h = 0 / 1v = 0 / 2h = 0 / 2v = 0 / 3h = 0 / 3v = 0 / 4h = 0 / 4v = 0 </values> <trial test_pic_trial1> / ontrialbegin = [ values.1h = list.random_hposition1.nextvalue; values.1v = list.random_vposition1.nextvalue; values.2h = list.random_hposition1.nextvalue; values.2v = list.random_vposition1.nextvalue; values.3h = list.random_hposition1.nextvalue; values.3v = list.random_vposition1.nextvalue; values.4h = list.random_hposition1.nextvalue; values.4v = list.random_vposition1.nextvalue; ] / stimulusframes=[1=correct1, incorrect1_2, incorrect1_3, incorrect1_4] / inputdevice=mouse / validresponse=(correct1, incorrect1_2, incorrect1_3, incorrect1_4) / correctresponse= (correct1) </trial> <block test1> /trials = [1=test_pic_trial1] </block> <picture correct1> / items = ("cap1.jpg") / size = (213, 280) / position = (values.1h, values.1v) </picture> <picture incorrect1_2> / items = ("cappen.jpg") / size = (213, 280) / position = (values.2h, values.2v) </picture> <picture incorrect1_3> / items = ("bottlecap.jpg") / size = (213, 280) / position = (values.3h, values.3v) </picture> <picture incorrect1_4> / items = ("pear.jpg") / size = (213, 280) / position = (values.4h, values.4v) </picture> <list random_hposition1> / items = (25, 25, 75, 75) / selectionrate = always / selectionmode = random / replace = false </list> <list random_vposition1> / items = (25, 75, 75, 25) / selectionmode = list.random_hposition1.currentindex </list> <list random_vposition1> must also be set to /selectionrate = always for this to work properly. <list random_vposition1> / items = (25, 75, 75, 25) / selectionmode = list.random_hposition1.currentindex / selectionrate = always </list>
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S F	S F posted 7 Years Ago ANSWER Post Details Share Post
Group: Forum Members Posts: 29, Visits: 175	+x Dave - Monday, October 16, 2017 +x S F - Monday, October 16, 2017 +x S F - Monday, October 16, 2017 +x Dave - Tuesday, October 10, 2017 +x Brabagazaa - Tuesday, October 10, 2017 Dear all, I ran into a slight problem and could not find a straightforward solution on the forum. I am drawing multiple items on the screen for each trial, the horizontal positions are in a list and picked at random, however all the shape also need a vertical position and I could not see how to make a list with tuple, something like: list = [(x1, y1), (x2, y2), etc] At the moment I wrote an expression that checks all the possible horizontal positions and matches the correct vertical position to it, so that each picture has the correct combination of vertical position + horizontal position, I was wondering if there might be an easier way to combine these values? Any suggestions would be great, Roelof PS: Attached a simplified example that shows the basic structure, the actual experiment uses set sizes 5,7,9, with all different coordinates, at which point writing the expressions becomes more arduous The trick is to define your position x/y tuples in two linked <list>s instead of trying to use a single one: <list hposition_list_neutral_set7> /items = (20, 26, 50, 73, 79, 63, 36) /selectionmode = random </list> <list vposition_list_set7> /items = (43, 68, 80, 68, 43, 22, 22) / selectionmode = list.hposition_list_neutral_set7.currentindex </list> with <trial neutral> /ontrialbegin = [values.hpos1 = list.hposition_list_neutral_set7.nextvalue; values.vpos1=list.vposition_list_set7.nextvalue] /stimulusframes = [1=target_shape] /validresponse = ("z","m") /pretrialpause = floor(rand(values.jitter_low,values.jitter_high)) </trial> <picture target_shape> / items = c_g / hposition = values.hpos1 / vposition = values.vpos1 </picture> Hi, I'm trying this approach but I can't get it to run- any tips? More generally, I wouldn't have to randomize positions if I could just evaluate whether the item randomly chosen from an element of items matched a string (for correctresponse) but since I couldn't figure that out, evaluating this from the picture name (fixing the picture) worked before, except that it's tricky to randomize position. That's what I'm trying to do in this code, attempting to match this example. Thanks! Whoops- I was missing declaring the <values> before. So it works now, but it displays 2 pictures in each spot, overlapping.... <values> / 1h = 0 / 1v = 0 / 2h = 0 / 2v = 0 / 3h = 0 / 3v = 0 / 4h = 0 / 4v = 0 </values> <trial test_pic_trial1> / ontrialbegin = [ values.1h = list.random_hposition1.nextvalue; values.1v = list.random_vposition1.nextvalue; values.2h = list.random_hposition1.nextvalue; values.2v = list.random_vposition1.nextvalue; values.3h = list.random_hposition1.nextvalue; values.3v = list.random_vposition1.nextvalue; values.4h = list.random_hposition1.nextvalue; values.4v = list.random_vposition1.nextvalue; ] / stimulusframes=[1=correct1, incorrect1_2, incorrect1_3, incorrect1_4] / inputdevice=mouse / validresponse=(correct1, incorrect1_2, incorrect1_3, incorrect1_4) / correctresponse= (correct1) </trial> <block test1> /trials = [1=test_pic_trial1] </block> <picture correct1> / items = ("cap1.jpg") / size = (213, 280) / position = (values.1h, values.1v) </picture> <picture incorrect1_2> / items = ("cappen.jpg") / size = (213, 280) / position = (values.2h, values.2v) </picture> <picture incorrect1_3> / items = ("bottlecap.jpg") / size = (213, 280) / position = (values.3h, values.3v) </picture> <picture incorrect1_4> / items = ("pear.jpg") / size = (213, 280) / position = (values.4h, values.4v) </picture> <list random_hposition1> / items = (25, 25, 75, 75) / selectionrate = always / selectionmode = random / replace = false </list> <list random_vposition1> / items = (25, 75, 75, 25) / selectionmode = list.random_hposition1.currentindex </list> <list random_vposition1> must also be set to /selectionrate = always for this to work properly. <list random_vposition1> / items = (25, 75, 75, 25) / selectionmode = list.random_hposition1.currentindex / selectionrate = always </list> fantastic- works great. thanks so much Dave!
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