Variable Trial Number


Author
Message
mrg4
mrg4
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Posts: 19, Visits: 218
Hi,
I am currently working on creating templates for some standard procedures which only vary in their stimulus material and a few parameters.
One of those parameters is the number of trials within a specific block.
Is there any chance of using values within a block's trial-attribute?
Here is a example of how I imagine the ideal sultion:

<block Test>
/trials = [1-values.NumTrials = noreplace(trialA, trialB)
/...
</block>

Is this possible somehow?
Thanks in advance!

Dominik

Dave
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Posts: 12K, Visits: 99K
mrg4 - Tuesday, November 7, 2017
Hi,
I am currently working on creating templates for some standard procedures which only vary in their stimulus material and a few parameters.
One of those parameters is the number of trials within a specific block.
Is there any chance of using values within a block's trial-attribute?
Here is a example of how I imagine the ideal sultion:

<block Test>
/trials = [1-values.NumTrials = noreplace(trialA, trialB)
/...
</block>

Is this possible somehow?
Thanks in advance!

Dominik

You can achieve this by performing trial selection via a <list> and setting the <list>'s /poolsize via <parameters>:

<parameters>
/ ntrials = 10
</parameters>

<block myblock>
/ stop = [
    block.myblock.trialcount >= parameters.ntrials
]

/ trials = [1=list.triallist]
</block>

<list triallist>
/ items = (trial.a, trial.b)
/ poolsize = parameters.ntrials

</list>


<trial a>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]

</trial>

<trial b>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]

</trial>

The above will run 10 trials (5 x a; 5 x b).

Change the ntrials parameter to 20, and you'll get 10 x a and 10 x b:

<parameters>
/ ntrials = 20
</parameters>

<block myblock>
/ stop = [
    block.myblock.trialcount >= parameters.ntrials
]
/ trials = [1=list.triallist]
</block>

<list triallist>
/ items = (trial.a, trial.b)
/ poolsize = parameters.ntrials
</list>


<trial a>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]
</trial>

<trial b>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]
</trial>

Hope this helps.

mrg4
mrg4
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Group: Forum Members
Posts: 19, Visits: 218
Dave - Tuesday, November 7, 2017
mrg4 - Tuesday, November 7, 2017
Hi,
I am currently working on creating templates for some standard procedures which only vary in their stimulus material and a few parameters.
One of those parameters is the number of trials within a specific block.
Is there any chance of using values within a block's trial-attribute?
Here is a example of how I imagine the ideal sultion:

<block Test>
/trials = [1-values.NumTrials = noreplace(trialA, trialB)
/...
</block>

Is this possible somehow?
Thanks in advance!

Dominik

You can achieve this by performing trial selection via a <list> and setting the <list>'s /poolsize via <parameters>:

<parameters>
/ ntrials = 10
</parameters>

<block myblock>
/ stop = [
    block.myblock.trialcount >= parameters.ntrials
]

/ trials = [1=list.triallist]
</block>

<list triallist>
/ items = (trial.a, trial.b)
/ poolsize = parameters.ntrials

</list>


<trial a>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]

</trial>

<trial b>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]

</trial>

The above will run 10 trials (5 x a; 5 x b).

Change the ntrials parameter to 20, and you'll get 10 x a and 10 x b:

<parameters>
/ ntrials = 20
</parameters>

<block myblock>
/ stop = [
    block.myblock.trialcount >= parameters.ntrials
]
/ trials = [1=list.triallist]
</block>

<list triallist>
/ items = (trial.a, trial.b)
/ poolsize = parameters.ntrials
</list>


<trial a>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]
</trial>

<trial b>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]
</trial>

Hope this helps.

Thank you so much for your quick response! That's the solution I was looking for! :)
Best regards.

Andrew Papale
Andrew Papale
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Group: Forum Members
Posts: 62, Visits: 230
mrg4 - 11/9/2017
Dave - Tuesday, November 7, 2017
mrg4 - Tuesday, November 7, 2017
Hi,
I am currently working on creating templates for some standard procedures which only vary in their stimulus material and a few parameters.
One of those parameters is the number of trials within a specific block.
Is there any chance of using values within a block's trial-attribute?
Here is a example of how I imagine the ideal sultion:

<block Test>
/trials = [1-values.NumTrials = noreplace(trialA, trialB)
/...
</block>

Is this possible somehow?
Thanks in advance!

Dominik

You can achieve this by performing trial selection via a <list> and setting the <list>'s /poolsize via <parameters>:

<parameters>
/ ntrials = 10
</parameters>

<block myblock>
/ stop = [
    block.myblock.trialcount >= parameters.ntrials
]

/ trials = [1=list.triallist]
</block>

<list triallist>
/ items = (trial.a, trial.b)
/ poolsize = parameters.ntrials

</list>


<trial a>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]

</trial>

<trial b>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]

</trial>

The above will run 10 trials (5 x a; 5 x b).

Change the ntrials parameter to 20, and you'll get 10 x a and 10 x b:

<parameters>
/ ntrials = 20
</parameters>

<block myblock>
/ stop = [
    block.myblock.trialcount >= parameters.ntrials
]
/ trials = [1=list.triallist]
</block>

<list triallist>
/ items = (trial.a, trial.b)
/ poolsize = parameters.ntrials
</list>


<trial a>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]
</trial>

<trial b>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]
</trial>

Hope this helps.

Thank you so much for your quick response! That's the solution I was looking for! :)
Best regards.

I am trying to implement this to randomize total trial numbers, but it is not working correctly.  e.g. in the code I specified, I wanted it to run 5 trials, and Inquisit is instead running exactly 3 trials of my task.  The only difference appears to be that I branch from my trial in trial list to a feedback screen, and then from that feedback screen to list.triallist.nextvalue.  Any help would be appreciated!

<block experiment>
/ onblockbegin = [
    values.scrfunc = noreplace("IEV","DEV","CEV","CEVR","IEV","DEV","IEV","DEV");
    parameters.ntrials = 5;
    values.blockCount = values.blockCount + 1;
    values.trialCount = values.trialCount + parameters.ntrials;
    
]
/ stop = [
    block.experiment.trialcount >= parameters.ntrials
]
/ trials = [1=list.triallist]
</block>

<list triallist>
/items = (trial.experiment)
/ poolsize = parameters.ntrials
</list>

<trial experiment>
/ branch = [
    return trial.dispFeedback;
]
</trial>

<trial dispFeedback>
/ branch = [
    list.triallist.nextvalue
]
</trial>

<expt main1>
/ blocks = [
    1=instructions;
    2=experiment;
    3=experiment;
    4=endscreen;
]
</expt>






Dave
Dave
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Group: Administrators
Posts: 12K, Visits: 99K
AndrewPapale - 1/17/2023
mrg4 - 11/9/2017
Dave - Tuesday, November 7, 2017
mrg4 - Tuesday, November 7, 2017
Hi,
I am currently working on creating templates for some standard procedures which only vary in their stimulus material and a few parameters.
One of those parameters is the number of trials within a specific block.
Is there any chance of using values within a block's trial-attribute?
Here is a example of how I imagine the ideal sultion:

<block Test>
/trials = [1-values.NumTrials = noreplace(trialA, trialB)
/...
</block>

Is this possible somehow?
Thanks in advance!

Dominik

You can achieve this by performing trial selection via a <list> and setting the <list>'s /poolsize via <parameters>:

<parameters>
/ ntrials = 10
</parameters>

<block myblock>
/ stop = [
    block.myblock.trialcount >= parameters.ntrials
]

/ trials = [1=list.triallist]
</block>

<list triallist>
/ items = (trial.a, trial.b)
/ poolsize = parameters.ntrials

</list>


<trial a>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]

</trial>

<trial b>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]

</trial>

The above will run 10 trials (5 x a; 5 x b).

Change the ntrials parameter to 20, and you'll get 10 x a and 10 x b:

<parameters>
/ ntrials = 20
</parameters>

<block myblock>
/ stop = [
    block.myblock.trialcount >= parameters.ntrials
]
/ trials = [1=list.triallist]
</block>

<list triallist>
/ items = (trial.a, trial.b)
/ poolsize = parameters.ntrials
</list>


<trial a>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]
</trial>

<trial b>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]
</trial>

Hope this helps.

Thank you so much for your quick response! That's the solution I was looking for! :)
Best regards.

I am trying to implement this to randomize total trial numbers, but it is not working correctly.  e.g. in the code I specified, I wanted it to run 5 trials, and Inquisit is instead running exactly 3 trials of my task.  The only difference appears to be that I branch from my trial in trial list to a feedback screen, and then from that feedback screen to list.triallist.nextvalue.  Any help would be appreciated!

<block experiment>
/ onblockbegin = [
    values.scrfunc = noreplace("IEV","DEV","CEV","CEVR","IEV","DEV","IEV","DEV");
    parameters.ntrials = 5;
    values.blockCount = values.blockCount + 1;
    values.trialCount = values.trialCount + parameters.ntrials;
    
]
/ stop = [
    block.experiment.trialcount >= parameters.ntrials
]
/ trials = [1=list.triallist]
</block>

<list triallist>
/items = (trial.experiment)
/ poolsize = parameters.ntrials
</list>

<trial experiment>
/ branch = [
    return trial.dispFeedback;
]
</trial>

<trial dispFeedback>
/ branch = [
    list.triallist.nextvalue
]
</trial>

<expt main1>
/ blocks = [
    1=instructions;
    2=experiment;
    3=experiment;
    4=endscreen;
]
</expt>






Feedback trials obviously go towards the trial count, so what you get is the expected resutl:



Dave
Dave
Supreme Being (1M reputation)Supreme Being (1M reputation)Supreme Being (1M reputation)Supreme Being (1M reputation)Supreme Being (1M reputation)Supreme Being (1M reputation)Supreme Being (1M reputation)Supreme Being (1M reputation)Supreme Being (1M reputation)
Group: Administrators
Posts: 12K, Visits: 99K
Dave - 1/17/2023
AndrewPapale - 1/17/2023
mrg4 - 11/9/2017
Dave - Tuesday, November 7, 2017
mrg4 - Tuesday, November 7, 2017
Hi,
I am currently working on creating templates for some standard procedures which only vary in their stimulus material and a few parameters.
One of those parameters is the number of trials within a specific block.
Is there any chance of using values within a block's trial-attribute?
Here is a example of how I imagine the ideal sultion:

<block Test>
/trials = [1-values.NumTrials = noreplace(trialA, trialB)
/...
</block>

Is this possible somehow?
Thanks in advance!

Dominik

You can achieve this by performing trial selection via a <list> and setting the <list>'s /poolsize via <parameters>:

<parameters>
/ ntrials = 10
</parameters>

<block myblock>
/ stop = [
    block.myblock.trialcount >= parameters.ntrials
]

/ trials = [1=list.triallist]
</block>

<list triallist>
/ items = (trial.a, trial.b)
/ poolsize = parameters.ntrials

</list>


<trial a>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]

</trial>

<trial b>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]

</trial>

The above will run 10 trials (5 x a; 5 x b).

Change the ntrials parameter to 20, and you'll get 10 x a and 10 x b:

<parameters>
/ ntrials = 20
</parameters>

<block myblock>
/ stop = [
    block.myblock.trialcount >= parameters.ntrials
]
/ trials = [1=list.triallist]
</block>

<list triallist>
/ items = (trial.a, trial.b)
/ poolsize = parameters.ntrials
</list>


<trial a>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]
</trial>

<trial b>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]
</trial>

Hope this helps.

Thank you so much for your quick response! That's the solution I was looking for! :)
Best regards.

I am trying to implement this to randomize total trial numbers, but it is not working correctly.  e.g. in the code I specified, I wanted it to run 5 trials, and Inquisit is instead running exactly 3 trials of my task.  The only difference appears to be that I branch from my trial in trial list to a feedback screen, and then from that feedback screen to list.triallist.nextvalue.  Any help would be appreciated!

<block experiment>
/ onblockbegin = [
    values.scrfunc = noreplace("IEV","DEV","CEV","CEVR","IEV","DEV","IEV","DEV");
    parameters.ntrials = 5;
    values.blockCount = values.blockCount + 1;
    values.trialCount = values.trialCount + parameters.ntrials;
    
]
/ stop = [
    block.experiment.trialcount >= parameters.ntrials
]
/ trials = [1=list.triallist]
</block>

<list triallist>
/items = (trial.experiment)
/ poolsize = parameters.ntrials
</list>

<trial experiment>
/ branch = [
    return trial.dispFeedback;
]
</trial>

<trial dispFeedback>
/ branch = [
    list.triallist.nextvalue
]
</trial>

<expt main1>
/ blocks = [
    1=instructions;
    2=experiment;
    3=experiment;
    4=endscreen;
]
</expt>






Feedback trials obviously go towards the trial count, so what you get is the expected resutl:



To do this properly, i.e. 5 "experiment" trials, each followed by a feedback trial per block, you'll want to do something like this:

<values>
/ scrfunc = ""
/ blockcount = 0
/ trialcount = 0
</values>

<parameters>
/ ntrials = 0
</parameters>

<block experiment>
/ onblockbegin = [
    values.scrfunc = noreplace("IEV","DEV","CEV","CEVR","IEV","DEV","IEV","DEV");
    parameters.ntrials = 5;
    list.triallist.poolsize = parameters.ntrials;
    values.trialcount = 0;
    values.blockCount = values.blockCount + 1;
]
/ stop = [
    values.trialcount >= parameters.ntrials
]
/ trials = [1=list.triallist]
</block>

<list triallist>
/items = (trial.experiment)
/ poolsize = parameters.ntrials
</list>

<trial experiment>
/ trialduration = 100

/ branch = [
    return trial.dispFeedback;
]
</trial>

<trial dispFeedback>
/ ontrialbegin = [
    values.trialcount += 1;
]
/ trialduration = 100
/ branch = [
    list.triallist.nextvalue
]
</trial>

<expt main1>
/ blocks = [
    1=instructions;
    2=experiment;
    3=experiment;
    4=endscreen;
]
</expt>

<block instructions>
/ preinstructions = (intro)
</block>

<block endscreen>
/ preinstructions = (end)
</block>

<page intro>
^intro page
</page>

<page end>
^end page
</page>

<data>
/ columns = (date time subject group blocknum blockcode trialnum trialcode block.experiment.trialcount values.trialcount)
</data>

Andrew Papale
Andrew Papale
Partner Member (815 reputation)Partner Member (815 reputation)Partner Member (815 reputation)Partner Member (815 reputation)Partner Member (815 reputation)Partner Member (815 reputation)Partner Member (815 reputation)Partner Member (815 reputation)Partner Member (815 reputation)
Group: Forum Members
Posts: 62, Visits: 230
Dave - 1/17/2023
Dave - 1/17/2023
AndrewPapale - 1/17/2023
mrg4 - 11/9/2017
Dave - Tuesday, November 7, 2017
mrg4 - Tuesday, November 7, 2017
Hi,
I am currently working on creating templates for some standard procedures which only vary in their stimulus material and a few parameters.
One of those parameters is the number of trials within a specific block.
Is there any chance of using values within a block's trial-attribute?
Here is a example of how I imagine the ideal sultion:

<block Test>
/trials = [1-values.NumTrials = noreplace(trialA, trialB)
/...
</block>

Is this possible somehow?
Thanks in advance!

Dominik

You can achieve this by performing trial selection via a <list> and setting the <list>'s /poolsize via <parameters>:

<parameters>
/ ntrials = 10
</parameters>

<block myblock>
/ stop = [
    block.myblock.trialcount >= parameters.ntrials
]

/ trials = [1=list.triallist]
</block>

<list triallist>
/ items = (trial.a, trial.b)
/ poolsize = parameters.ntrials

</list>


<trial a>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]

</trial>

<trial b>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]

</trial>

The above will run 10 trials (5 x a; 5 x b).

Change the ntrials parameter to 20, and you'll get 10 x a and 10 x b:

<parameters>
/ ntrials = 20
</parameters>

<block myblock>
/ stop = [
    block.myblock.trialcount >= parameters.ntrials
]
/ trials = [1=list.triallist]
</block>

<list triallist>
/ items = (trial.a, trial.b)
/ poolsize = parameters.ntrials
</list>


<trial a>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]
</trial>

<trial b>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]
</trial>

Hope this helps.

Thank you so much for your quick response! That's the solution I was looking for! :)
Best regards.

I am trying to implement this to randomize total trial numbers, but it is not working correctly.  e.g. in the code I specified, I wanted it to run 5 trials, and Inquisit is instead running exactly 3 trials of my task.  The only difference appears to be that I branch from my trial in trial list to a feedback screen, and then from that feedback screen to list.triallist.nextvalue.  Any help would be appreciated!

<block experiment>
/ onblockbegin = [
    values.scrfunc = noreplace("IEV","DEV","CEV","CEVR","IEV","DEV","IEV","DEV");
    parameters.ntrials = 5;
    values.blockCount = values.blockCount + 1;
    values.trialCount = values.trialCount + parameters.ntrials;
    
]
/ stop = [
    block.experiment.trialcount >= parameters.ntrials
]
/ trials = [1=list.triallist]
</block>

<list triallist>
/items = (trial.experiment)
/ poolsize = parameters.ntrials
</list>

<trial experiment>
/ branch = [
    return trial.dispFeedback;
]
</trial>

<trial dispFeedback>
/ branch = [
    list.triallist.nextvalue
]
</trial>

<expt main1>
/ blocks = [
    1=instructions;
    2=experiment;
    3=experiment;
    4=endscreen;
]
</expt>






Feedback trials obviously go towards the trial count, so what you get is the expected resutl:



To do this properly, i.e. 5 "experiment" trials, each followed by a feedback trial per block, you'll want to do something like this:

<values>
/ scrfunc = ""
/ blockcount = 0
/ trialcount = 0
</values>

<parameters>
/ ntrials = 0
</parameters>

<block experiment>
/ onblockbegin = [
    values.scrfunc = noreplace("IEV","DEV","CEV","CEVR","IEV","DEV","IEV","DEV");
    parameters.ntrials = 5;
    list.triallist.poolsize = parameters.ntrials;
    values.trialcount = 0;
    values.blockCount = values.blockCount + 1;
]
/ stop = [
    values.trialcount >= parameters.ntrials
]
/ trials = [1=list.triallist]
</block>

<list triallist>
/items = (trial.experiment)
/ poolsize = parameters.ntrials
</list>

<trial experiment>
/ trialduration = 100

/ branch = [
    return trial.dispFeedback;
]
</trial>

<trial dispFeedback>
/ ontrialbegin = [
    values.trialcount += 1;
]
/ trialduration = 100
/ branch = [
    list.triallist.nextvalue
]
</trial>

<expt main1>
/ blocks = [
    1=instructions;
    2=experiment;
    3=experiment;
    4=endscreen;
]
</expt>

<block instructions>
/ preinstructions = (intro)
</block>

<block endscreen>
/ preinstructions = (end)
</block>

<page intro>
^intro page
</page>

<page end>
^end page
</page>

<data>
/ columns = (date time subject group blocknum blockcode trialnum trialcode block.experiment.trialcount values.trialcount)
</data>

Thank you, this works wonderfully. 
Andrew Papale
Andrew Papale
Partner Member (815 reputation)Partner Member (815 reputation)Partner Member (815 reputation)Partner Member (815 reputation)Partner Member (815 reputation)Partner Member (815 reputation)Partner Member (815 reputation)Partner Member (815 reputation)Partner Member (815 reputation)
Group: Forum Members
Posts: 62, Visits: 230
Andrew Papale - 1/17/2023
Dave - 1/17/2023
Dave - 1/17/2023
AndrewPapale - 1/17/2023
mrg4 - 11/9/2017
Dave - Tuesday, November 7, 2017
mrg4 - Tuesday, November 7, 2017
Hi,
I am currently working on creating templates for some standard procedures which only vary in their stimulus material and a few parameters.
One of those parameters is the number of trials within a specific block.
Is there any chance of using values within a block's trial-attribute?
Here is a example of how I imagine the ideal sultion:

<block Test>
/trials = [1-values.NumTrials = noreplace(trialA, trialB)
/...
</block>

Is this possible somehow?
Thanks in advance!

Dominik

You can achieve this by performing trial selection via a <list> and setting the <list>'s /poolsize via <parameters>:

<parameters>
/ ntrials = 10
</parameters>

<block myblock>
/ stop = [
    block.myblock.trialcount >= parameters.ntrials
]

/ trials = [1=list.triallist]
</block>

<list triallist>
/ items = (trial.a, trial.b)
/ poolsize = parameters.ntrials

</list>


<trial a>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]

</trial>

<trial b>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]

</trial>

The above will run 10 trials (5 x a; 5 x b).

Change the ntrials parameter to 20, and you'll get 10 x a and 10 x b:

<parameters>
/ ntrials = 20
</parameters>

<block myblock>
/ stop = [
    block.myblock.trialcount >= parameters.ntrials
]
/ trials = [1=list.triallist]
</block>

<list triallist>
/ items = (trial.a, trial.b)
/ poolsize = parameters.ntrials
</list>


<trial a>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]
</trial>

<trial b>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]
</trial>

Hope this helps.

Thank you so much for your quick response! That's the solution I was looking for! :)
Best regards.

I am trying to implement this to randomize total trial numbers, but it is not working correctly.  e.g. in the code I specified, I wanted it to run 5 trials, and Inquisit is instead running exactly 3 trials of my task.  The only difference appears to be that I branch from my trial in trial list to a feedback screen, and then from that feedback screen to list.triallist.nextvalue.  Any help would be appreciated!

<block experiment>
/ onblockbegin = [
    values.scrfunc = noreplace("IEV","DEV","CEV","CEVR","IEV","DEV","IEV","DEV");
    parameters.ntrials = 5;
    values.blockCount = values.blockCount + 1;
    values.trialCount = values.trialCount + parameters.ntrials;
    
]
/ stop = [
    block.experiment.trialcount >= parameters.ntrials
]
/ trials = [1=list.triallist]
</block>

<list triallist>
/items = (trial.experiment)
/ poolsize = parameters.ntrials
</list>

<trial experiment>
/ branch = [
    return trial.dispFeedback;
]
</trial>

<trial dispFeedback>
/ branch = [
    list.triallist.nextvalue
]
</trial>

<expt main1>
/ blocks = [
    1=instructions;
    2=experiment;
    3=experiment;
    4=endscreen;
]
</expt>






Feedback trials obviously go towards the trial count, so what you get is the expected resutl:



To do this properly, i.e. 5 "experiment" trials, each followed by a feedback trial per block, you'll want to do something like this:

<values>
/ scrfunc = ""
/ blockcount = 0
/ trialcount = 0
</values>

<parameters>
/ ntrials = 0
</parameters>

<block experiment>
/ onblockbegin = [
    values.scrfunc = noreplace("IEV","DEV","CEV","CEVR","IEV","DEV","IEV","DEV");
    parameters.ntrials = 5;
    list.triallist.poolsize = parameters.ntrials;
    values.trialcount = 0;
    values.blockCount = values.blockCount + 1;
]
/ stop = [
    values.trialcount >= parameters.ntrials
]
/ trials = [1=list.triallist]
</block>

<list triallist>
/items = (trial.experiment)
/ poolsize = parameters.ntrials
</list>

<trial experiment>
/ trialduration = 100

/ branch = [
    return trial.dispFeedback;
]
</trial>

<trial dispFeedback>
/ ontrialbegin = [
    values.trialcount += 1;
]
/ trialduration = 100
/ branch = [
    list.triallist.nextvalue
]
</trial>

<expt main1>
/ blocks = [
    1=instructions;
    2=experiment;
    3=experiment;
    4=endscreen;
]
</expt>

<block instructions>
/ preinstructions = (intro)
</block>

<block endscreen>
/ preinstructions = (end)
</block>

<page intro>
^intro page
</page>

<page end>
^end page
</page>

<data>
/ columns = (date time subject group blocknum blockcode trialnum trialcode block.experiment.trialcount values.trialcount)
</data>

Thank you, this works wonderfully. 

Can this same logic work to achieve variable block numbers?  I assumed it would but am having some trouble implementing.

Thanks,
- Andre

Dave
Dave
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Dave - Tuesday, November 7, 2017
mrg4 - Tuesday, November 7, 2017
Hi,
I am currently working on creating templates for some standard procedures which only vary in their stimulus material and a few parameters.
One of those parameters is the number of trials within a specific block.
Is there any chance of using values within a block's trial-attribute?
Here is a example of how I imagine the ideal sultion:

<block Test>
/trials = [1-values.NumTrials = noreplace(trialA, trialB)
/...
</block>

Is this possible somehow?
Thanks in advance!

Dominik

You can achieve this by performing trial selection via a <list> and setting the <list>'s /poolsize via <parameters>:

<parameters>
/ ntrials = 10
</parameters>

<block myblock>
/ stop = [
    block.myblock.trialcount >= parameters.ntrials
]

/ trials = [1=list.triallist]
</block>

<list triallist>
/ items = (trial.a, trial.b)
/ poolsize = parameters.ntrials

</list>


<trial a>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]

</trial>

<trial b>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]

</trial>

The above will run 10 trials (5 x a; 5 x b).

Change the ntrials parameter to 20, and you'll get 10 x a and 10 x b:

<parameters>
/ ntrials = 20
</parameters>

<block myblock>
/ stop = [
    block.myblock.trialcount >= parameters.ntrials
]
/ trials = [1=list.triallist]
</block>

<list triallist>
/ items = (trial.a, trial.b)
/ poolsize = parameters.ntrials
</list>


<trial a>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]
</trial>

<trial b>
/ validresponse = (0)
/ trialduration = 10
/ branch = [
    list.triallist.nextvalue;
]
</trial>

Hope this helps.

Thank you so much for your quick response! That's the solution I was looking for! :)
Best regards.

I am trying to implement this to randomize total trial numbers, but it is not working correctly.  e.g. in the code I specified, I wanted it to run 5 trials, and Inquisit is instead running exactly 3 trials of my task.  The only difference appears to be that I branch from my trial in trial list to a feedback screen, and then from that feedback screen to list.triallist.nextvalue.  Any help would be appreciated!

<block experiment>
/ onblockbegin = [
    values.scrfunc = noreplace("IEV","DEV","CEV","CEVR","IEV","DEV","IEV","DEV");
    parameters.ntrials = 5;
    values.blockCount = values.blockCount + 1;
    values.trialCount = values.trialCount + parameters.ntrials;
    
]
/ stop = [
    block.experiment.trialcount >= parameters.ntrials
]
/ trials = [1=list.triallist]
</block>

<list triallist>
/items = (trial.experiment)
/ poolsize = parameters.ntrials
</list>

<trial experiment>
/ branch = [
    return trial.dispFeedback;
]
</trial>

<trial dispFeedback>
/ branch = [
    list.triallist.nextvalue
]
</trial>

<expt main1>
/ blocks = [
    1=instructions;
    2=experiment;
    3=experiment;
    4=endscreen;
]
</expt>






Feedback trials obviously go towards the trial count, so what you get is the expected resutl:



To do this properly, i.e. 5 "experiment" trials, each followed by a feedback trial per block, you'll want to do something like this:

<values>
/ scrfunc = ""
/ blockcount = 0
/ trialcount = 0
</values>

<parameters>
/ ntrials = 0
</parameters>

<block experiment>
/ onblockbegin = [
    values.scrfunc = noreplace("IEV","DEV","CEV","CEVR","IEV","DEV","IEV","DEV");
    parameters.ntrials = 5;
    list.triallist.poolsize = parameters.ntrials;
    values.trialcount = 0;
    values.blockCount = values.blockCount + 1;
]
/ stop = [
    values.trialcount >= parameters.ntrials
]
/ trials = [1=list.triallist]
</block>

<list triallist>
/items = (trial.experiment)
/ poolsize = parameters.ntrials
</list>

<trial experiment>
/ trialduration = 100

/ branch = [
    return trial.dispFeedback;
]
</trial>

<trial dispFeedback>
/ ontrialbegin = [
    values.trialcount += 1;
]
/ trialduration = 100
/ branch = [
    list.triallist.nextvalue
]
</trial>

<expt main1>
/ blocks = [
    1=instructions;
    2=experiment;
    3=experiment;
    4=endscreen;
]
</expt>

<block instructions>
/ preinstructions = (intro)
</block>

<block endscreen>
/ preinstructions = (end)
</block>

<page intro>
^intro page
</page>

<page end>
^end page
</page>

<data>
/ columns = (date time subject group blocknum blockcode trialnum trialcode block.experiment.trialcount values.trialcount)
</data>

Thank you, this works wonderfully. 

Can this same logic work to achieve variable block numbers?  I assumed it would but am having some trouble implementing.

Thanks,
- Andre

Sure, you can do something similar for blocks.

GO

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