Randomizing no replace of blocks that are not sequential

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Randomizing no replace of blocks that are not sequential

Randomizing no replace of blocks that are not sequential

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kd01	kd01 posted 8 Years Ago Topic Details Share Topic
Group: Forum Members Posts: 6, Visits: 18	Hello, I have a task in which I hope to present three open ended trials (with different stimuli) in random order and between each openended trial present a survey on that trial and then a reminder of instructions. Is it possible to use the norepeatnoreplace command in the following way and still ensure there is no repeat of of any particular open ended trial but that they are each still shown randomly? <exp> /blocks = 1=start; 2=norepeatnoreplace(one, two, three); 3=survey.Survey1; 4=reminder1; 5=norepeatnoreplace(one, two, three); 6=survey.Survey2; 7=reminder2; 8=norepeatnoreplace(one, two, three); 9=survey.Survey3; 10=end </exp>
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Dave	Dave posted 8 Years Ago ANSWER Post Details Share Post
Group: Administrators Posts: 13K, Visits: 107K	+x kd01 - Wednesday, December 20, 2017 Hello, I have a task in which I hope to present three open ended trials (with different stimuli) in random order and between each openended trial present a survey on that trial and then a reminder of instructions. Is it possible to use the norepeatnoreplace command in the following way and still ensure there is no repeat of of any particular open ended trial but that they are each still shown randomly? <exp> /blocks = 1=start; 2=norepeatnoreplace(one, two, three); 3=survey.Survey1; 4=reminder1; 5=norepeatnoreplace(one, two, three); 6=survey.Survey2; 7=reminder2; 8=norepeatnoreplace(one, two, three); 9=survey.Survey3; 10=end </exp> No, that syntax is not correct / will not yield the desired result. What you should do is simply: /blocks = [1=start; 2,5,8=noreplace(one, two, three); 3=survey.Survey1; 4=reminder1; 6=survey.Survey2; 7=reminder2; 9=survey.Survey3; 10=end]
	Reply Like 32