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Randomization of blocks and "Sub-Blocks".


Randomization of blocks and "Sub-Blocks".
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DannyPilgrim
DannyPilgrim
DannyPilgrim
posted 4 Years Ago
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Hello everyone,

I hope you understand my question.
I have three separate blocks which contain three Sub-blocks each:

Block_a
- a1 = 96 Trials
- a2 = 96 Trials
- a3 = 96 Trials

Block_b
- b1 = 96 Trials
- b2 = 96 Trials
- b3 = 96 Trials

Block_c
- c1 = 96 Trials
- c2 = 96 Trials
- c3 = 96 Trials

I'd like to randomize the big blocks (Block_a, Block_b, Block_c) and those inside of them as well. The picture visualizes what I mean.

On which layer do I have to define this? On the <block> or <expt> layer?

Would it be something like that in the <block> layer:
<block Block_a>
/ preinstructions = (htmlpage.Übung2)
/ trials = noreplace=[1-96 =noreplace(...)]
/ trials = [1-96 =noreplace(...)]
/ trials = [1-96 =noreplace(...)]
</block>
(The trials themselves are randomized in each Sub-Block with =noreplace)

Or do I have to define all Sub-Blocks and arrange them within the <expt> layer?

I know how to randomize blocks in the <expt> but right now I cannot define it how I need it.

Best Regards,
Danny
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DannyPilgrim
DannyPilgrim
DannyPilgrim
posted 4 Years Ago ANSWER
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Dave
Dave
Dave
posted 4 Years Ago ANSWER
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DannyPilgrim - 4/28/2021

You have to do something like this:

<values>
/ a_blockcount = 0
/ b_blockcount = 0
/ c_blockcount = 0
</values>

<expt>
/ blocks = [1-3 = noreplace(block.a, block.b, block.c)]
</expt>

<block a>
/ branch = [
    //select a random sub-block
    list.a_sub.nextvalue;
]
</block>

// three "sub-blocks"
<list a_sub>
/ items = (block.a1, block.a2, block.a3)
</list>

<block a1>
/ onblockbegin = [
    values.a_blockcount += 1;
]
/ trials = [1=mytrial]
/ branch = [
    // if we stil have further sub-blocks to run, select the next one at random
    if (values.a_blockcount < 3) {
        list.a_sub.nextvalue;
    }
]
</block>

<block a2>
/ onblockbegin = [
    values.a_blockcount += 1;
]
/ trials = [1=mytrial]
/ branch = [
    // if we stil have further sub-blocks to run, select the next one at random
    if (values.a_blockcount < 3) {
        list.a_sub.nextvalue;
    }
]
</block>

<block a3>
/ onblockbegin = [
    values.a_blockcount += 1;
]
/ trials = [1=mytrial]
/ branch = [
    // if we stil have further sub-blocks to run, select the next one at random
    if (values.a_blockcount < 3) {
        list.a_sub.nextvalue;
    }
]
</block>

<block b>
/ branch = [
    //select a random sub-block
    list.b_sub.nextvalue;
]
</block>

// three "sub-blocks"
<list b_sub>
/ items = (block.b1, block.b2, block.b3)
</list>

<block b1>
/ onblockbegin = [
    values.b_blockcount += 1;
]
/ trials = [1=mytrial]
/ branch = [
    // if we stil have further sub-blocks to run, select the next one at random
    if (values.b_blockcount < 3) {
        list.b_sub.nextvalue;
    }
]
</block>

<block b2>
/ onblockbegin = [
    values.b_blockcount += 1;
]
/ trials = [1=mytrial]
/ branch = [
    // if we stil have further sub-blocks to run, select the next one at random
    if (values.b_blockcount < 3) {
        list.b_sub.nextvalue;
    }
]
</block>

<block b3>
/ onblockbegin = [
    values.b_blockcount += 1;
]
/ trials = [1=mytrial]
/ branch = [
    // if we stil have further sub-blocks to run, select the next one at random
    if (values.b_blockcount < 3) {
        list.b_sub.nextvalue;
    }
]
</block>

<block c>
/ branch = [
    //select a random sub-block
    list.c_sub.nextvalue;
]
</block>

// three "sub-blocks"
<list c_sub>
/ items = (block.c1, block.c2, block.c3)
</list>

<block c1>
/ onblockbegin = [
    values.c_blockcount += 1;
]
/ trials = [1=mytrial]
/ branch = [
    // if we stil have further sub-blocks to run, select the next one at random
    if (values.c_blockcount < 3) {
        list.c_sub.nextvalue;
    }
]
</block>

<block c2>
/ onblockbegin = [
    values.c_blockcount += 1;
]
/ trials = [1=mytrial]
/ branch = [
    // if we stil have further sub-blocks to run, select the next one at random
    if (values.c_blockcount < 3) {
        list.c_sub.nextvalue;
    }
]
</block>

<block c3>
/ onblockbegin = [
    values.c_blockcount += 1;
]
/ trials = [1=mytrial]
/ branch = [
    // if we stil have further sub-blocks to run, select the next one at random
    if (values.c_blockcount < 3) {
        list.c_sub.nextvalue;
    }
]
</block>

<trial mytrial>
/ stimulusframes = [1=mytext]
/ validresponse = (57)
</trial>

<text mytext>
/ items = ("This is block <%script.currentblock%>.")
</text>
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DannyPilgrim
DannyPilgrim
DannyPilgrim
posted 4 Years Ago ANSWER
Partner Member (543 reputation)Partner Member (543 reputation)Partner Member (543 reputation)Partner Member (543 reputation)Partner Member (543 reputation)Partner Member (543 reputation)Partner Member (543 reputation)Partner Member (543 reputation)Partner Member (543 reputation)
Group: Forum Members
Posts: 37, Visits: 146
 
Dave - 4/28/2021
 
DannyPilgrim - 4/28/2021

You have to do something like this:

<values>
/ a_blockcount = 0
/ b_blockcount = 0
/ c_blockcount = 0
</values>

<expt>
/ blocks = [1-3 = noreplace(block.a, block.b, block.c)]
</expt>

<block a>
/ branch = [
    //select a random sub-block
    list.a_sub.nextvalue;
]
</block>

// three "sub-blocks"
<list a_sub>
/ items = (block.a1, block.a2, block.a3)
</list>

<block a1>
/ onblockbegin = [
    values.a_blockcount += 1;
]
/ trials = [1=mytrial]
/ branch = [
    // if we stil have further sub-blocks to run, select the next one at random
    if (values.a_blockcount < 3) {
        list.a_sub.nextvalue;
    }
]
</block>

<block a2>
/ onblockbegin = [
    values.a_blockcount += 1;
]
/ trials = [1=mytrial]
/ branch = [
    // if we stil have further sub-blocks to run, select the next one at random
    if (values.a_blockcount < 3) {
        list.a_sub.nextvalue;
    }
]
</block>

<block a3>
/ onblockbegin = [
    values.a_blockcount += 1;
]
/ trials = [1=mytrial]
/ branch = [
    // if we stil have further sub-blocks to run, select the next one at random
    if (values.a_blockcount < 3) {
        list.a_sub.nextvalue;
    }
]
</block>

<block b>
/ branch = [
    //select a random sub-block
    list.b_sub.nextvalue;
]
</block>

// three "sub-blocks"
<list b_sub>
/ items = (block.b1, block.b2, block.b3)
</list>

<block b1>
/ onblockbegin = [
    values.b_blockcount += 1;
]
/ trials = [1=mytrial]
/ branch = [
    // if we stil have further sub-blocks to run, select the next one at random
    if (values.b_blockcount < 3) {
        list.b_sub.nextvalue;
    }
]
</block>

<block b2>
/ onblockbegin = [
    values.b_blockcount += 1;
]
/ trials = [1=mytrial]
/ branch = [
    // if we stil have further sub-blocks to run, select the next one at random
    if (values.b_blockcount < 3) {
        list.b_sub.nextvalue;
    }
]
</block>

<block b3>
/ onblockbegin = [
    values.b_blockcount += 1;
]
/ trials = [1=mytrial]
/ branch = [
    // if we stil have further sub-blocks to run, select the next one at random
    if (values.b_blockcount < 3) {
        list.b_sub.nextvalue;
    }
]
</block>

<block c>
/ branch = [
    //select a random sub-block
    list.c_sub.nextvalue;
]
</block>

// three "sub-blocks"
<list c_sub>
/ items = (block.c1, block.c2, block.c3)
</list>

<block c1>
/ onblockbegin = [
    values.c_blockcount += 1;
]
/ trials = [1=mytrial]
/ branch = [
    // if we stil have further sub-blocks to run, select the next one at random
    if (values.c_blockcount < 3) {
        list.c_sub.nextvalue;
    }
]
</block>

<block c2>
/ onblockbegin = [
    values.c_blockcount += 1;
]
/ trials = [1=mytrial]
/ branch = [
    // if we stil have further sub-blocks to run, select the next one at random
    if (values.c_blockcount < 3) {
        list.c_sub.nextvalue;
    }
]
</block>

<block c3>
/ onblockbegin = [
    values.c_blockcount += 1;
]
/ trials = [1=mytrial]
/ branch = [
    // if we stil have further sub-blocks to run, select the next one at random
    if (values.c_blockcount < 3) {
        list.c_sub.nextvalue;
    }
]
</block>

<trial mytrial>
/ stimulusframes = [1=mytext]
/ validresponse = (57)
</trial>

<text mytext>
/ items = ("This is block <%script.currentblock%>.")
</text>



Thank you very much, Dave!
That helps alot!
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