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Group: Administrators
Posts: 13K,
Visits: 105K
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+x+x+xHi again, Participants are completing 2 of these blocks. If I try run the experiment twice, the second time the block is presented none of the options show up. Is there a way to reset the skips/present the same block twice? Also, is there a strikeout feature instead of an option disappearing completely off the screen once it has been selected? If there is no strikeout option, is there a way to keep the stimuli on the screen, but after they press on it once they cannot select it again? Like removing it as a valid response? The rationale is that we'd like to have each trial look the same. The script already does that. Also, I didn't say the option cannot be striked out. <list options>
/ items = ("option a", "option b", "option c", "option d", "option e","option f", "option g", "option h")
/ selectionrate = always
</list>
<values>
/ pair1a = ""
/ pair1b = ""
/ pair1apassage = 1
/ pair1bpassage = 1
</values>
<list pair1responses>
</list>
<expt>
/ onexptbegin = [
values.pair1a = list.options.nextvalue;
values.pair1apassage = list.options.currentindex;
values.pair1b = list.options.nextvalue;
values.pair1bpassage = list.options.currentindex;
]
/ blocks = [1=exampleblock]
</expt>
<block exampleblock>
/ onblockbegin = [
list.pair1responses.reset();
]
/ trials = [1-2=pair1trial]
</block>
<trial pair1trial>
/ ontrialend = [
list.pair1responses.appenditem(trial.pair1trial.response);
]
/ stimulusframes = [1=click, pair1a, pair1b]
/ inputdevice = mouse
/ validresponse = (pair1a, pair1b)
/ isvalidresponse = [
list.pair1responses.indexof(trial.pair1trial.response) == -1;
]
/ branch = [
if (trial.pair1trial.response == "pair1a") {
values.pair1a = concat(concat("<s>", values.pair1a), "</s>");
return surveypage.pair1a_follow_up;
} else if (trial.pair1trial.response == "pair1b") {
values.pair1b = concat(concat("<s>", values.pair1b), "</s>");
return surveypage.pair1b_follow_up;
};
]
</trial>
<text click>
/ items = ("Click on one of the below options:")
/ position = (50%, 10%)
</text>
<text pair1a>
/ items = ("<%values.pair1a%>")
/ position = (50%, 30%)
</text>
<text pair1b>
/ items = ("<%values.pair1b%>")
/ position = (50%, 40%)
</text>
<surveypage pair1a_follow_up>
/ subcaption = "<%item.passages.item(values.pair1apassage)%>"
/ showpagenumbers = false
/ showquestionnumbers = false
</surveypage>
<surveypage pair1b_follow_up>
/ subcaption = "<%item.passages.item(values.pair1bpassage)%>"
/ showpagenumbers = false
/ showquestionnumbers = false
</surveypage>
<item passages>
/ 1 = "Passage pertaining to Option A"
/ 2 = "Passage pertaining to Option B"
/ 3 = "Passage pertaining to Option C"
/ 4 = "Passage pertaining to Option D"
/ 5 = "Passage pertaining to Option E"
/ 6 = "Passage pertaining to Option F"
/ 7 = "Passage pertaining to Option G"
/ 8 = "Passage pertaining to Option H"
</item>
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Group: Forum Members
Posts: 6,
Visits: 23
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+x+xHi again, Participants are completing 2 of these blocks. If I try run the experiment twice, the second time the block is presented none of the options show up. Is there a way to reset the skips/present the same block twice? Also, is there a strikeout feature instead of an option disappearing completely off the screen once it has been selected? > the second time the block is presented none of the options show up. Is there a way to reset the skips/present the same block twice? You need to set the text elements' skip properties back to false again /onblockbegin. Hi Dave, I was able to use this successfully for one condition (where I present all 8 choices at once). However, when I try to apply it to the other condition (2 paired choices are presented at a time), the strike through is still there when I go to run this second condition another time. How do I allow people to redo the paired version again while keeping the same original pairings? I hope that makes sense. If not, please let me know and I can try to rephrase. Thank you.
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Group: Administrators
Posts: 13K,
Visits: 105K
|
+x+x+xHi again, Participants are completing 2 of these blocks. If I try run the experiment twice, the second time the block is presented none of the options show up. Is there a way to reset the skips/present the same block twice? Also, is there a strikeout feature instead of an option disappearing completely off the screen once it has been selected? > the second time the block is presented none of the options show up. Is there a way to reset the skips/present the same block twice? You need to set the text elements' skip properties back to false again /onblockbegin. Hi Dave, I was able to use this successfully for one condition (where I present all 8 choices at once). However, when I try to apply it to the other condition (2 paired choices are presented at a time), the strike through is still there when I go to run this second condition another time. How do I allow people to redo the paired version again while keeping the same original pairings? I hope that makes sense. If not, please let me know and I can try to rephrase. Thank you. You obviously need to revert the strikethrough at the start of the block. <list options>
/ items = ("option a", "option b", "option c", "option d", "option e","option f", "option g", "option h")
/ selectionrate = always
</list>
<values>
/ pair1a = ""
/ pair1b = ""
/ pair1apassage = 1
/ pair1bpassage = 1
</values>
<list pair1responses>
</list>
<expt>
/ onexptbegin = [
values.pair1a = list.options.nextvalue;
values.pair1apassage = list.options.currentindex;
values.pair1b = list.options.nextvalue;
values.pair1bpassage = list.options.currentindex;
]
/ blocks = [1-2=exampleblock]
</expt>
<block exampleblock>
/ onblockbegin = [
list.pair1responses.reset();
values.pair1a = replaceall(values.pair1a, "<s>", "");
values.pair1a = replaceall(values.pair1a, "</s>", "");
values.pair1b = replaceall(values.pair1b, "<s>", "");
values.pair1b = replaceall(values.pair1b, "</s>", "");
]
/ trials = [1-2=pair1trial]
</block>
<trial pair1trial>
/ ontrialend = [
list.pair1responses.appenditem(trial.pair1trial.response);
]
/ stimulusframes = [1=click, pair1a, pair1b]
/ inputdevice = mouse
/ validresponse = (pair1a, pair1b)
/ isvalidresponse = [
list.pair1responses.indexof(trial.pair1trial.response) == -1;
]
/ branch = [
if (trial.pair1trial.response == "pair1a") {
values.pair1a = concat(concat("<s>", values.pair1a), "</s>");
return surveypage.pair1a_follow_up;
} else if (trial.pair1trial.response == "pair1b") {
values.pair1b = concat(concat("<s>", values.pair1b), "</s>");
return surveypage.pair1b_follow_up;
};
]
</trial>
<text click>
/ items = ("Click on one of the below options:")
/ position = (50%, 10%)
</text>
<text pair1a>
/ items = ("<%values.pair1a%>")
/ position = (50%, 30%)
</text>
<text pair1b>
/ items = ("<%values.pair1b%>")
/ position = (50%, 40%)
</text>
<surveypage pair1a_follow_up>
/ subcaption = "<%item.passages.item(values.pair1apassage)%>"
/ showpagenumbers = false
/ showquestionnumbers = false
</surveypage>
<surveypage pair1b_follow_up>
/ subcaption = "<%item.passages.item(values.pair1bpassage)%>"
/ showpagenumbers = false
/ showquestionnumbers = false
</surveypage>
<item passages>
/ 1 = "Passage pertaining to Option A"
/ 2 = "Passage pertaining to Option B"
/ 3 = "Passage pertaining to Option C"
/ 4 = "Passage pertaining to Option D"
/ 5 = "Passage pertaining to Option E"
/ 6 = "Passage pertaining to Option F"
/ 7 = "Passage pertaining to Option G"
/ 8 = "Passage pertaining to Option H"
</item>
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