RE: Incorrect Number of Trials

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Incorrect Number of Trials

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charsiubhau	charsiubhau posted 3 Years Ago Topic Details Share Topic
Group: Forum Members Posts: 32, Visits: 41	Hi there, I want to have 98 experimental trials for the each of the experimental trials for the nback (2 keys) followed by slider trial. However, I noticed in my output that they are not always 98. The sequence is as follows (not including slider trial): - 1back = 98 experimental trials - 2back = 99 experimental trials -3back = 100 trials Is it possible to have the 1back, 2back, and 3back all have 98 experimental trials? My code for trials is below, please let me know if you need my full script or any additional information. I'd appreciate any help! 1 = start; 2 - 98 = noreplace(nontarget, nontarget,target); 99 = slidertrial.nbackperception;
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charsiubhau	charsiubhau posted 3 Years Ago ANSWER Post Details Share Post
Group: Forum Members Posts: 32, Visits: 41	+x charsiubhau - 10/18/2022 Hi there, I want to have 98 experimental trials for the each of the experimental trials for the nback (2 keys) followed by slider trial. However, I noticed in my output that they are not always 98. The sequence is as follows (not including slider trial): - 1back = 98 experimental trials - 2back = 99 experimental trials -3back = 100 trials Is it possible to have the 1back, 2back, and 3back all have 98 experimental trials? My code for trials is below, please let me know if you need my full script or any additional information. I'd appreciate any help! 1 = start; 2 - 98 = noreplace(nontarget, nontarget,target); 99 = slidertrial.nbackperception; I just noticed that it increases the practice trials by one as well when I want them to remain at 10 practice trials for all levels. The sequence is as follows: - 1back = 10 practice trials - 2back = 11 practice trials - 3back = 12 practice trials
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charsiubhau	charsiubhau posted 3 Years Ago ANSWER Post Details Share Post
Group: Forum Members Posts: 32, Visits: 41	Here is my code! Attachments ENCODE Forwards.iqx (127 views, 76.00 KB)
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Dave	Dave posted 3 Years Ago ANSWER Post Details Share Post
Group: Administrators Posts: 13K, Visits: 105K	+x charsiubhau - 10/18/2022 Here is my code! I think you're mistakenly counting the start trials, of which there obviously must be a different number depending on the N-level. At N=1, the block must begin with one start trial. Only the second trial can be an experimental trial, since otherwise there is no stimulus presented one trial back (1-back). At N=2, the block must begin with two start trials. Only the third trial can be an experimental trial, since otherwise there is no stimulus presented two trials back (2-back). At N=3, the block must begin with three start trials. Only the fourth trial can be an experimental trial, since otherwise there is no stimulus presented three trials back (3-back).
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charsiubhau	charsiubhau posted 3 Years Ago ANSWER Post Details Share Post
Group: Forum Members Posts: 32, Visits: 41	+x Dave - 10/18/2022 +x charsiubhau - 10/18/2022 Here is my code! I think you're mistakenly counting the start trials, of which there obviously must be a different number depending on the N-level. At N=1, the block must begin with one start trial. Only the second trial can be an experimental trial, since otherwise there is no stimulus presented one trial back (1-back). At N=2, the block must begin with two start trials. Only the third trial can be an experimental trial, since otherwise there is no stimulus presented two trials back (2-back). At N=3, the block must begin with three start trials. Only the fourth trial can be an experimental trial, since otherwise there is no stimulus presented three trials back (3-back). Hi Dave, This makes a lot of sense, thank you so much!
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