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<values> / globalType = null / subType = null / firstPairItemNumber = -1 / secondPairItemNumber = -1 </values>
<block exampleBlock> / trials = [1-38 = noReplace(sameTrial, diffTrial)] </block>
<trial sameTrial> / onTrialBegin = { values.globalType = "same"; //set globa trial type values.subType = list.sameTypes.nextValue; // select subtype // select item for 1st pair according to subtype if (startsWith(values.subType, "A")) { values.firstPairItemNumber = list.catAItemNumbers.nextValue; } else if (startsWith(values.subType, "B")) { values.firstPairItemNumber = list.catBItemNumbers.nextValue; } else if (startsWith(values.subType, "C")) { values.firstPairItemNumber = list.catCItemNumbers.nextValue; } else if (startsWith(values.subType, "D")) { values.firstPairItemNumber = list.catDItemNumbers.nextValue; }; // select item for 2nd pair according to subtype if (endsWith(values.subType, "A")) { values.secondPairItemNumber = list.catAItemNumbers.nextValue; } else if (endsWith(values.subType, "B")) { values.secondPairItemNumber = list.catBItemNumbers.nextValue; } else if (endsWith(values.subType, "C")) { values.secondPairItemNumber = list.catCItemNumbers.nextValue; } else if (endsWith(values.subType, "D")) { values.secondPairItemNumber = list.catDItemNumbers.nextValue; }; } / stimulusTimes = [0=clearScreen, firstPair; 1000=clearScreen, fixation; 2000=clearScreen, secondPair; 3000=clearScreen, x] / validResponse = ("F", "J") / correctResponse = ("F") </trial>
<list sameTypes> / items = ( "AA", "AA", "AA", "AA", "AA", "AA", "AA", "AA", "AA", "BB", "BB", "BB", "BB", "BB", "BB", "CC", "CC", "CC", "CC") </list>
<trial diffTrial> / onTrialBegin = { values.globalType = "diff"; //set globa trial type values.subType = list.diffTypes.nextValue; // select subtype // select item for 1st pair according to subtype if (startsWith(values.subType, "A")) { values.firstPairItemNumber = list.catAItemNumbers.nextValue; } else if (startsWith(values.subType, "B")) { values.firstPairItemNumber = list.catBItemNumbers.nextValue; } else if (startsWith(values.subType, "C")) { values.firstPairItemNumber = list.catCItemNumbers.nextValue; } else if (startsWith(values.subType, "D")) { values.firstPairItemNumber = list.catDItemNumbers.nextValue; }; // select item for 2nd pair according to subtype if (endsWith(values.subType, "A")) { values.secondPairItemNumber = list.catAItemNumbers.nextValue; } else if (endsWith(values.subType, "B")) { values.secondPairItemNumber = list.catBItemNumbers.nextValue; } else if (endsWith(values.subType, "C")) { values.secondPairItemNumber = list.catCItemNumbers.nextValue; } else if (endsWith(values.subType, "D")) { values.secondPairItemNumber = list.catDItemNumbers.nextValue; }; } / stimulusTimes = [0=clearScreen, firstPair; 1000=clearScreen, fixation; 2000=clearScreen, secondPair; 3000=clearScreen, x] / validResponse = ("F", "J") / correctResponse = ("J") </trial>
<list diffTypes> / items = ( "AB", "AB", "AB", "AC", "BA", "BA", "BC", "BD", "BD", "CA", "CA", "CB", "CB", "CB", "DA", "DB", "DC", "DC", "DC") </list>
<text fixation> / items = ("+") / erase = false </text>
<text x> / items = ("X") / erase = false </text>
<text firstPair> / items = allItems / select = values.firstPairItemNumber / erase = false </text>
<text secondPair> / items = allItems / select = values.secondPairItemNumber / erase = false </text>
<item allItems> // category A / 0 = "Cat A Pair 1" / 1 = "Cat A Pair 2" / 2 = "Cat A Pair 3" / 3 = "Cat A Pair 4" / 4 = "Cat A Pair 5" / 5 = "Cat A Pair 6" / 6 = "Cat A Pair 7" / 7 = "Cat A Pair 8" / 8 = "Cat A Pair 9" / 9 = "Cat A Pair 10" / 10 = "Cat A Pair 11" / 11 = "Cat A Pair 12" / 12 = "Cat A Pair 13" / 13 = "Cat A Pair 14" / 14 = "Cat A Pair 15" / 15 = "Cat A Pair 16" / 16 = "Cat A Pair 17" / 17 = "Cat A Pair 18" / 18 = "Cat A Pair 19" / 19 = "Cat A Pair 20" / 20 = "Cat A Pair 21" / 21 = "Cat A Pair 22" / 22 = "Cat A Pair 23" / 23 = "Cat A Pair 24" / 24 = "Cat A Pair 25" / 25 = "Cat A Pair 26" / 26 = "Cat A Pair 27" // category B / 27 = "Cat B Pair 1" / 28 = "Cat B Pair 2" / 29 = "Cat B Pair 3" / 30 = "Cat B Pair 4" / 31 = "Cat B Pair 5" / 32 = "Cat B Pair 6" / 33 = "Cat B Pair 7" / 34 = "Cat B Pair 8" / 35 = "Cat B Pair 9" / 36 = "Cat B Pair 10" / 37 = "Cat B Pair 11" / 38 = "Cat B Pair 12" / 39 = "Cat B Pair 13" / 40 = "Cat B Pair 14" / 41 = "Cat B Pair 15" / 42 = "Cat B Pair 16" / 43 = "Cat B Pair 17" / 44 = "Cat B Pair 18" / 45 = "Cat B Pair 19" / 46 = "Cat B Pair 20" / 47 = "Cat B Pair 21" / 48 = "Cat B Pair 22" / 49 = "Cat B Pair 23" / 50 = "Cat B Pair 24" // category C / 51 = "Cat C Pair 1" / 52 = "Cat C Pair 2" / 53 = "Cat C Pair 3" / 54 = "Cat C Pair 4" / 55 = "Cat C Pair 5" / 56 = "Cat C Pair 6" / 57 = "Cat C Pair 7" / 58 = "Cat C Pair 8" / 59 = "Cat C Pair 9" / 60 = "Cat C Pair 10" / 61 = "Cat C Pair 11" / 62 = "Cat C Pair 12" / 63 = "Cat C Pair 13" / 64 = "Cat C Pair 14" / 65 = "Cat C Pair 15" / 66 = "Cat C Pair 16" / 67 = "Cat C Pair 17" / 68 = "Cat C Pair 18" // category D / 69 = "Cat D Pair 1" / 70 = "Cat D Pair 2" / 71 = "Cat D Pair 3" / 72 = "Cat D Pair 4" / 73 = "Cat D Pair 5" / 74 = "Cat D Pair 6" / 75 = "Cat D Pair 7" </item>
<list catAItemNumbers> / items = (0-26) / selectionRate = always </list>
<list catBItemNumbers> / items = (27-50) / selectionRate = always </list>
<list catCItemNumbers> / items = (51-68) / selectionRate = always </list>
<list catDItemNumbers> / items = (69-75) / selectionRate = always </list>
<data> / columns = ( date, time, subject, group, session, blockNum, blockCode, trialNum, trialCode, response, responseText, latency, correct, values.globalType, values.subType, values.firstPairItemNumber, values.secondPairItemNumber, text.firstPair.currentItem, text.secondPair.currentItem ) </data>
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Yes, that's right. Sorry for making this confusing!
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Group: Administrators
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+x+x+xWe don't particularly care if each type occurs equally often. It's more about the fact that participants are responding F or J roughly equal number of times. Well, it makes a difference in terms of how many items you need per category. So, what are the numbers? I see. (I forgot to add that there's a fourth category, D, but we don't want consecutive pairs of D) Same: 9 x AA 6 x BB 4 x CC Different: 3 x AB 1 x AC 2 x BA 1 x BC 2 x BD 2 x CA 3 x CB 1 x DA 1 x DB 3 x DC By my count, that means you have 27 category A items 24 category B items 18 category C items 7 cateory D items Does that match? In general, it would be helpful if you could provide such information in an accessible way, so I don't have to count these things up manually. Thanks.
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Group: Forum Members
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+x+xWe don't particularly care if each type occurs equally often. It's more about the fact that participants are responding F or J roughly equal number of times. Well, it makes a difference in terms of how many items you need per category. So, what are the numbers? I see. (I forgot to add that there's a fourth category, D, but we don't want consecutive pairs of D) Same: 9 x AA 6 x BB 4 x CC Different: 3 x AB 1 x AC 2 x BA 1 x BC 2 x BD 2 x CA 3 x CB 1 x DA 1 x DB 3 x DC
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Group: Administrators
Posts: 13K,
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+xWe don't particularly care if each type occurs equally often. It's more about the fact that participants are responding F or J roughly equal number of times. Well, it makes a difference in terms of how many items you need per category. So, what are the numbers?
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We don't particularly care if each type occurs equally often. It's more about the fact that participants are responding F or J roughly equal number of times.
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+xEach stimulus is a word pair (eg. cap:bottle, mammal:fox, etc.) and is categorized into A, B, or C. Each trial shows the first word pair, then a "+", then the second word pair, then an "X". On the second word pair, participants respond by pressing F or J. This sequence is one trial. I'd like to randomize the list of word pairs, but make it so that 50% of trials have word pairs from the same category (ie. AA or BB or CC), and 50% of trials do not. Hopefully this makes more sense? You have 3 possible "same" trial types: AA, BB, CC As for the "different" trials, it's unclear if you care about order. I assume you do, so you have 6 types: AB, AC, BA, BC, CA, CB. Normally you would care that each type occurs equally often. That doesn't work with 38 trials total. It would work with 36. Same: 6 x AA 6 x BB 6 x CC Different: 3 x AB 3 x AC 3 x BA 3 x BC 3 x CA 3 x CB So, what do you want to do to get to 38 trials? Unclear to me.
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Each stimulus is a word pair (eg. cap:bottle, mammal:fox, etc.) and is categorized into A, B, or C. Each trial shows the first word pair, then a "+", then the second word pair, then an "X". On the second word pair, participants respond by pressing F or J. This sequence is one trial.
I'd like to randomize the list of word pairs, but make it so that 50% of trials have word pairs from the same category (ie. AA or BB or CC), and 50% of trials do not. Hopefully this makes more sense?
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Group: Administrators
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+xHi, I want 38 trials that are each made up of 2 stimuli. Is there a way to randomize the stimuli but make it so that 50% of trials have the same stimuli type? For example, each stimulus is categorized as type A, B, or C. 50% of trials should be stimuli of the same category (eg. AA), and 50% do not (eg. AB). Is it possible to incorporate this logic? Give a more detailed description and a concrete example.
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Group: Forum Members
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Hi,
I want 38 trials that are each made up of 2 stimuli. Is there a way to randomize the stimuli but make it so that 50% of trials have the same stimuli type? For example, each stimulus is categorized as type A, B, or C. 50% of trials should be stimuli of the same category (eg. AA), and 50% do not (eg. AB). Is it possible to incorporate this logic?
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