Am i correct with the assumption that a high D-Score always stands for the associationstrength of the compatible Block?
In My Script i have the following components (i used the Inquisit-Script and just changed the items for the two attributes and the two targets - see the attachment):
AttributeA: Postive
Attribute B: Negative
TargetA: Generation
TargetB: Agegroup
This means the higher my D-Score the higher is the preference of a subject for its Generation in contrast to its age group? -> preference for TargetA-Attribute A?
The *absolute* value abs(D) is taken to reflect the strength of association, the *sign* (+ vs. -) indicates the direction of the association. You'll find all of this covered in the published literature and you can find a quick, Inquisit-specific summary at https://www.millisecond.com/forums/Topic3444.aspx.
My second question concerns the modification of the Inquisit Syntax-File: I want to calculate the D-Score without the practice Blocks
The unmodified SPSS syntax as available from millisecond.com already gives you separate D's for practice only vs. test only vs. all blocks. So do the Inquisit IAT scripts ,i.e., there is no strict need for any SPSS syntax at all if all you're interested in are the various Ds. This is also covered in the above-mentioned summary.
If you have general questions re. writing, modifying, understanding SPSS syntax, I would recommend you consult the support resources provided by SPSS Inc. / IBM and/or some of the numerous books and online tutorials on the topic.
Finally note that Greenwald et al. (2003) strongly recommend including the "practice" blocks.
Regards,
~Dave