Just wanted to check the SPSS Syntax for calculating the inclusive SD. I have two groups of pairs, which has resulted in four calculations for each numerator component (e.g., M1 M2 M3 M4 SD1 SD2 SD3 SD4 N1 N2 N3 N4). Group 1 (GRP1) are calculations with 1 and 2, and group 2 (GRP2) are calculations with 3 and 4.
When using the syntax to calculate the denominator for D-beip for each group, would I just replace only the calculations that change based on groups of pairs?
For example:
D_asis_numGRP2 = SQRT( ( ((N3-1) * SD3**2 + (N4-1) * SD4**2) + ((N3+N4) * ((M3-M4)**2) / 4) ) / (N3 + N4 - 1) )
Thank you :)
As far as I can see based on the info you provided: Yes.
Thanks Dave :)