same order of randomization


Author
Message
wieteke
wieteke
Expert (1.3K reputation)Expert (1.3K reputation)Expert (1.3K reputation)Expert (1.3K reputation)Expert (1.3K reputation)Expert (1.3K reputation)Expert (1.3K reputation)Expert (1.3K reputation)Expert (1.3K reputation)
Group: Forum Members
Posts: 11, Visits: 11
Dear all,

I use a randomization counter to pick random (no replace) a picture for trial A, and with the picture element I select with the current function the same picture for trial B and C (and this 80 times). This works perfectly fine. However, after this block 'task' I want another block 'task2' in which I would like the same order of pictures that participants received in block "task". Is this possible (I tried different things but could not find the solution)? Thanks a lot!


<block task>
/ trials = [1=A; 2=B; 3=C]
</block>

<counter blabla>
/ select = noreplace (1-80)
/ resetinterval = 0
</counter>


Dave
Dave
Supreme Being (1M reputation)Supreme Being (1M reputation)Supreme Being (1M reputation)Supreme Being (1M reputation)Supreme Being (1M reputation)Supreme Being (1M reputation)Supreme Being (1M reputation)Supreme Being (1M reputation)Supreme Being (1M reputation)
Group: Administrators
Posts: 12K, Visits: 98K
Yes, it's possible to do that. Two options:

#1: Randomize stuff *once* at the beginning of the experiment, store the result in a <list> or <counter>, then use sequential selection from that list / counter for the remainder of the experiment.

#2: Go for random order in the first portion, record the result (again in a list or counter) at runtime, then use sequential selection from said list counter in the 2nd part.

EDITED TO ADD: Example for #2 (#1 would work along similar lines):

<values>
/ itemnumber = 1
</values>

<expt>
/ blocks = [1=block1; 2=block2]
</expt>

<block block1>
/ trials = [1-4=block1_trial]
</block>

<block block2>
/ trials = [1-4=block2_trial]
</block>

<trial block1_trial>
/ ontrialbegin = [values.itemnumber=list.itemlist_block1.nextvalue; list.itemlist_block2.appenditem(values.itemnumber)]
/ stimulusframes = [1=mytext]
/ validresponse = (57)
</trial>

<trial block2_trial>
/ ontrialbegin = [values.itemnumber=list.itemlist_block2.nextvalue]
/ stimulusframes = [1=mytext]
/ validresponse = (57)
</trial>

<text mytext>
/ items = ("A", "B", "C", "D")
/ select = values.itemnumber
</text>

<list itemlist_block1>
/ items = (1,2,3,4)
/ selectionmode = random
</list>

<list itemlist_block2>
/ selectionmode = sequence
</list>

Edited 10 Years Ago by Dave
wieteke
wieteke
Expert (1.3K reputation)Expert (1.3K reputation)Expert (1.3K reputation)Expert (1.3K reputation)Expert (1.3K reputation)Expert (1.3K reputation)Expert (1.3K reputation)Expert (1.3K reputation)Expert (1.3K reputation)
Group: Forum Members
Posts: 11, Visits: 11
Thank you very much! That helps a lot!
GO

Merge Selected

Merge into selected topic...



Merge into merge target...



Merge into a specific topic ID...




Reading This Topic

Explore
Messages
Mentions
Search