list syntax

Back

list syntax

Author	Message
nakayama	nakayama posted 9 Years Ago ANSWER Post Details Share Post
Group: Forum Members Posts: 72, Visits: 408	Thank you Dave！Very appreciated.
	Reply Like 56
Dave	Dave posted 9 Years Ago ANSWER Post Details Share Post
Group: Administrators Posts: 13K, Visits: 104K	Yes, that /stimulustimes setup combined with a 2100 ms /timeout would result in a display duration of approx. 100 ms for the stimulus "target".
	Reply Like 58
nakayama	nakayama posted 9 Years Ago ANSWER Post Details Share Post
Group: Forum Members Posts: 72, Visits: 408	Thank you Dave! I appreciate it very much! I read it. As for timing, is it correct to define the duration of stimulus as "100ms" like this? <trial standard> / stimulustimes = [1=fixation;2000=target] / recorddata = true / timeout = 2100 </trial> Best, nakayama
	Reply Like 63
Dave	Dave posted 9 Years Ago ANSWER Post Details Share Post
Group: Administrators Posts: 13K, Visits: 104K	Various issues in that script; pay closer attention to any warnings and error messages when you parse and run, then fix them. Main problem was you using /stimulusframes instead of /stimulustimes in <trial target>. Compare to the attached. You may also want to take a closer look at the "How to Control Trial Duration and Inter-Trial Intervals" topic in the documentation to make sure you understand Inquisit's timing model and the resulting timings are what you intend them to be. Attachments experimentrandom1.iqx (555 views, 2.00 KB)
	Reply Like 62
nakayama	nakayama posted 9 Years Ago ANSWER Post Details Share Post
Group: Forum Members Posts: 72, Visits: 408	Thank you Dave! I modified it. However, when I ran my script I showed this: Direct2D Warning: 0x8899000c A presentation error has occurred that may be recoverable. The caller needs to re-create the render target then attempt to render the frame again. Line 779, File win\Direct2DGraphics.cpp Would you please take a look at my draft? I was trying to start a the target stimulus with the duration randomly from (10,20,30,40,50,60,70,80,90,100) Thank you for your time! Attachments experimentrandom1.iqx (560 views, 2.00 KB)
	Reply Like 45
Dave	Dave posted 9 Years Ago ANSWER Post Details Share Post
Group: Administrators Posts: 13K, Visits: 104K	To select a value at random from a <list> and store it, do: <list somelist> / items = (1,2,3,4,5,6,7,8,9,10) </list> <values> / count = 0 ... </values> <expt> / onextpbegin = [values.count = list.somelist.nextvalue] / blocks = [1=1] ... </expt> Then work with / in- or de-crease values.count in your <block> as needed.
	Reply Like 55
nakayama	nakayama posted 9 Years Ago HOT Topic Details Share Topic
Group: Forum Members Posts: 72, Visits: 408	Hi, Mr. Dave. I am wondering whether inquisit 4 can do this: On the beginning of the block, list randomly select a number. How can we track down that number? Since at the end of that block, the number will decrease or increase by 1 from the one that was selected. I use this syntax but doesn't work. Thank you for your concern！ <list selection> / selectionmode = random / items = (1,2,3,4,5,6,7,8,9,10) </list> <values> /step=10 /count=list.selection </values> <block 1> / onblockbegin = [list.selection] / trials = [1= standard;2=target;3=question] / onblockend = [if(openended.question.correct)list.selection.currentvalue -=1 else list.selection.currentvalue +=1] / branch = [if (list.selection.currentvalue==10 && openended.question.correct) 0] / branch = [if(list.selection.currentvalue<10)block.1] </block> Best, nakayama
	Reply Like 57