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draw a line

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nakayama	nakayama posted 5 Years Ago Topic Details Share Topic
Group: Forum Members Posts: 72, Visits: 408	Hi, Inquisit community Is it possible to draw a tilted line? I have noticed that the Shape supports circle, triangle and rectangle shapes. If not, is there a similar way to approximate to draw a tilted line (maybe a tilted rectangle)? Thank you for your reply;) Attachments sample3.iqx (226 views, 1.00 KB)
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nakayama	nakayama posted 5 Years Ago ANSWER Post Details Share Post
Group: Forum Members Posts: 72, Visits: 408	+x nakayama - 10/24/2019 Hi, Inquisit community Is it possible to draw a tilted line? I have noticed that the Shape supports circle, triangle and rectangle shapes. If not, is there a similar way to approximate to draw a tilted line (maybe a tilted rectangle)? Thank you for your reply;) I also notice triangle can provide a tilted line, is that possible to do by adjusting a triangle?
	Reply Like 10
Dave	Dave posted 5 Years Ago ANSWER Post Details Share Post
Group: Administrators Posts: 13K, Visits: 104K	+x nakayama - 10/24/2019 +x nakayama - 10/24/2019 Hi, Inquisit community Is it possible to draw a tilted line? I have noticed that the Shape supports circle, triangle and rectangle shapes. If not, is there a similar way to approximate to draw a tilted line (maybe a tilted rectangle)? Thank you for your reply;) I also notice triangle can provide a tilted line, is that possible to do by adjusting a triangle? No, rotating or tilting stimuli (be it <shape>, <picture>, or <text> is not currently possible. The closest you can get is drawing a triangle and have other objects cover up the parts you don't want, but this seems fiddly: <shape triangle> / shape = triangle / color = blue / size = (40%, 20%) / position = (40%, 50%) </shape> <shape cover1> / shape = triangle / color = white / size = (40%, 20%) / position = (40%, 51%) </shape> <shape cover2> / shape = rectangle / color = white / size = (20%, 20%) / position = (30%, 50%) </shape> <trial example> / stimulusframes = [1=triangle, cover1, cover2] / validresponse = (57) </trial>
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nakayama	nakayama posted 5 Years Ago ANSWER Post Details Share Post
Group: Forum Members Posts: 72, Visits: 408	thank you for your advice. That is a great enlightenment;)
	Reply Like 14