Random picture pairing using mycounter


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NaomiLee
NaomiLee
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Thank you so much that works! Sorry I am new to Inquisit and think I'd just got a bit confused trying to sort the issue out from looking on these forums. 


Dave
Dave
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NaomiLee - 11/18/2019
My experiment involves ppts judging whether pairings shown are a match or not. Each ppt has a different 3 pairings that they need to learn. However, there are 9 possible pairings. I believe I have worked out how to create a random assignment of pairings for each ppt.  

<counter mycounter>
/ select = noreplace(1,2,3,4,5,6,7,8,9)
/ selectionrate = experiment
</counter>

<item pictures>
/1="ECircle.png"
/2="EDiamond.png"
/3="EHexagon.png"
/4="EOctagon.png"
/5="EOval.png"
/6="EPentagon.png"
/7="ERectangle.png"
/8="ESquare.png"
/9="ETriangle.png"
</item>

<picture Pic1>
/items = pictures
/select = mycounter
/position = (50%, 35%)
</picture>

<picture Pic2>
/items = pictures
/select = mycounter
/ position = (50%, 35%)
</picture>

<picture Pic3>
/items = pictures
/select = mycounter
/ position = (50%, 35%)
</picture>

This seems to work, but not sure if there is a way to ensure that the same picture isn't duplicated - think it works with noreplace but not certain. 

The issue I am having is that the instruction page needs to show the pictures in a different position. 

<trial trial_pra_selfpace_demo>
/stimulustimes = [0=txt_pra_selfpace_instr, txt_instr_key, pic_instr_L, pic_instr_M, pic_instr_R, txt_instr_L, txt_instr_M, txt_instr_R, fixation_L, fixation_R, fixation]
/ validresponse = (57)
/ correctresponse = (57)
</trial>

## instr_Picture
<picture pic_instr_L>
/ items = picture.Pic1
/ position = (30%, 35%)
</picture>
<picture pic_instr_M>
/items = picture.Pic2
/ position = (50%, 35%)
</picture>
<picture pic_instr_R>
/items = picture.Pic3
/ position = (70%, 35%)
</picture>

However this leads to the error that the pictures (picture.Pic1, picture.Pic2, picture.Pic3) could not be located. Is this because it is a random assignment rather than one set image? Are there any ways I could overcome this? Is there a way I could display Pic1, Pic2, Pic3 side by side on one instruction screen. 

Many thanks, Naomi



<picture pic_instr_L>
/ items = picture.Pic1
/ position = (30%, 35%)
</picture>
<picture pic_instr_M>
/items = picture.Pic2
/ position = (50%, 35%)
</picture>
<picture pic_instr_R>
/items = picture.Pic3
/ position = (70%, 35%)
</picture>

This is invalid syntax. The /items attribute must refer to an <item> element, not another <picture> element.

I also don't understand what you're doing with that <counter>. The way you've set that up, it'll select a single random value over the course of the entire experiment. That is: Your three <picture> elements Pic1, Pic2, and Pic 3 will all display the same item, not three different items. What you'll want to do is probably something along the following lines:

<values>
/ pic1_item = 1
/ pic2_item = 1
/ pic3_item = 1
</values>

<list mylist>
/ poolsize = 9
/ selectionrate = always
/ selectionmode = random
/ replace = false
</counter>

<expt>
/ onexptbegin = [values.pic1_item = list.mylist.nextindex;
values.pic2_item = list.mylist.nextindex;
values.pic3_item = list.mylist.nextindex;
]
....
</expt>

with

<picture Pic1>
/items = pictures
/select = values.pic1_item
/position = (50%, 35%)
</picture>

<picture Pic2>
/items = pictures
/select = values.pic2_item
/ position = (50%, 35%)
</picture>

<picture Pic3>
/items = pictures
/select = values.pic3_item
/ position = (50%, 35%)
</picture>

and same for the picture elements you use during the instructions / demo trial:

## instr_Picture
<picture pic_instr_L>
/items = pictures
/select = values.pic1_item
/ position = (30%, 35%)
</picture>
<picture pic_instr_M>
/items = pictures
/select = values.pic2_item
/ position = (50%, 35%)
</picture>
<picture pic_instr_R>
/items = pictures
/select = values.pic3_item
/ position = (70%, 35%)
</picture>


Edited 5 Years Ago by Dave
NaomiLee
NaomiLee
Associate Member (83 reputation)Associate Member (83 reputation)Associate Member (83 reputation)Associate Member (83 reputation)Associate Member (83 reputation)Associate Member (83 reputation)Associate Member (83 reputation)Associate Member (83 reputation)Associate Member (83 reputation)
Group: Forum Members
Posts: 2, Visits: 2
My experiment involves ppts judging whether pairings shown are a match or not. Each ppt has a different 3 pairings that they need to learn. However, there are 9 possible pairings. I believe I have worked out how to create a random assignment of pairings for each ppt.  

<counter mycounter>
/ select = noreplace(1,2,3,4,5,6,7,8,9)
/ selectionrate = experiment
</counter>

<item pictures>
/1="ECircle.png"
/2="EDiamond.png"
/3="EHexagon.png"
/4="EOctagon.png"
/5="EOval.png"
/6="EPentagon.png"
/7="ERectangle.png"
/8="ESquare.png"
/9="ETriangle.png"
</item>

<picture Pic1>
/items = pictures
/select = mycounter
/position = (50%, 35%)
</picture>

<picture Pic2>
/items = pictures
/select = mycounter
/ position = (50%, 35%)
</picture>

<picture Pic3>
/items = pictures
/select = mycounter
/ position = (50%, 35%)
</picture>

This seems to work, but not sure if there is a way to ensure that the same picture isn't duplicated - think it works with noreplace but not certain. 

The issue I am having is that the instruction page needs to show the pictures in a different position. 

<trial trial_pra_selfpace_demo>
/stimulustimes = [0=txt_pra_selfpace_instr, txt_instr_key, pic_instr_L, pic_instr_M, pic_instr_R, txt_instr_L, txt_instr_M, txt_instr_R, fixation_L, fixation_R, fixation]
/ validresponse = (57)
/ correctresponse = (57)
</trial>

## instr_Picture
<picture pic_instr_L>
/ items = picture.Pic1
/ position = (30%, 35%)
</picture>
<picture pic_instr_M>
/items = picture.Pic2
/ position = (50%, 35%)
</picture>
<picture pic_instr_R>
/items = picture.Pic3
/ position = (70%, 35%)
</picture>

However this leads to the error that the pictures (picture.Pic1, picture.Pic2, picture.Pic3) could not be located. Is this because it is a random assignment rather than one set image? Are there any ways I could overcome this? Is there a way I could display Pic1, Pic2, Pic3 side by side on one instruction screen. 

Many thanks, Naomi



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