RE: Random picture pairing using mycounter

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RE: Random picture pairing using mycounter

Random picture pairing using mycounter

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NaomiLee	NaomiLee posted 5 Years Ago Topic Details Share Topic
Group: Forum Members Posts: 2, Visits: 2	My experiment involves ppts judging whether pairings shown are a match or not. Each ppt has a different 3 pairings that they need to learn. However, there are 9 possible pairings. I believe I have worked out how to create a random assignment of pairings for each ppt. <counter mycounter> / select = noreplace(1,2,3,4,5,6,7,8,9) / selectionrate = experiment </counter> <item pictures> /1="ECircle.png" /2="EDiamond.png" /3="EHexagon.png" /4="EOctagon.png" /5="EOval.png" /6="EPentagon.png" /7="ERectangle.png" /8="ESquare.png" /9="ETriangle.png" </item> <picture Pic1> /items = pictures /select = mycounter /position = (50%, 35%) </picture> <picture Pic2> /items = pictures /select = mycounter / position = (50%, 35%) </picture> <picture Pic3> /items = pictures /select = mycounter / position = (50%, 35%) </picture> This seems to work, but not sure if there is a way to ensure that the same picture isn't duplicated - think it works with noreplace but not certain. The issue I am having is that the instruction page needs to show the pictures in a different position. <trial trial_pra_selfpace_demo> /stimulustimes = [0=txt_pra_selfpace_instr, txt_instr_key, pic_instr_L, pic_instr_M, pic_instr_R, txt_instr_L, txt_instr_M, txt_instr_R, fixation_L, fixation_R, fixation] / validresponse = (57) / correctresponse = (57) </trial> ## instr_Picture <picture pic_instr_L> / items = picture.Pic1 / position = (30%, 35%) </picture> <picture pic_instr_M> /items = picture.Pic2 / position = (50%, 35%) </picture> <picture pic_instr_R> /items = picture.Pic3 / position = (70%, 35%) </picture> However this leads to the error that the pictures (picture.Pic1, picture.Pic2, picture.Pic3) could not be located. Is this because it is a random assignment rather than one set image? Are there any ways I could overcome this? Is there a way I could display Pic1, Pic2, Pic3 side by side on one instruction screen. Many thanks, Naomi
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Dave	Dave posted 5 Years Ago ANSWER Post Details Share Post
Group: Administrators Posts: 13K, Visits: 104K	+x NaomiLee - 11/18/2019 My experiment involves ppts judging whether pairings shown are a match or not. Each ppt has a different 3 pairings that they need to learn. However, there are 9 possible pairings. I believe I have worked out how to create a random assignment of pairings for each ppt. <counter mycounter> / select = noreplace(1,2,3,4,5,6,7,8,9) / selectionrate = experiment </counter> <item pictures> /1="ECircle.png" /2="EDiamond.png" /3="EHexagon.png" /4="EOctagon.png" /5="EOval.png" /6="EPentagon.png" /7="ERectangle.png" /8="ESquare.png" /9="ETriangle.png" </item> <picture Pic1> /items = pictures /select = mycounter /position = (50%, 35%) </picture> <picture Pic2> /items = pictures /select = mycounter / position = (50%, 35%) </picture> <picture Pic3> /items = pictures /select = mycounter / position = (50%, 35%) </picture> This seems to work, but not sure if there is a way to ensure that the same picture isn't duplicated - think it works with noreplace but not certain. The issue I am having is that the instruction page needs to show the pictures in a different position. <trial trial_pra_selfpace_demo> /stimulustimes = [0=txt_pra_selfpace_instr, txt_instr_key, pic_instr_L, pic_instr_M, pic_instr_R, txt_instr_L, txt_instr_M, txt_instr_R, fixation_L, fixation_R, fixation] / validresponse = (57) / correctresponse = (57) </trial> ## instr_Picture <picture pic_instr_L> / items = picture.Pic1 / position = (30%, 35%) </picture> <picture pic_instr_M> /items = picture.Pic2 / position = (50%, 35%) </picture> <picture pic_instr_R> /items = picture.Pic3 / position = (70%, 35%) </picture> However this leads to the error that the pictures (picture.Pic1, picture.Pic2, picture.Pic3) could not be located. Is this because it is a random assignment rather than one set image? Are there any ways I could overcome this? Is there a way I could display Pic1, Pic2, Pic3 side by side on one instruction screen. Many thanks, Naomi <picture pic_instr_L> / items = picture.Pic1 / position = (30%, 35%) </picture> <picture pic_instr_M> /items = picture.Pic2 / position = (50%, 35%) </picture> <picture pic_instr_R> /items = picture.Pic3 / position = (70%, 35%) </picture> This is invalid syntax. The /items attribute must refer to an <item> element, not another <picture> element. I also don't understand what you're doing with that <counter>. The way you've set that up, it'll select a single random value over the course of the entire experiment. That is: Your three <picture> elements Pic1, Pic2, and Pic 3 will all display the same item, not three different items. What you'll want to do is probably something along the following lines: <values> / pic1_item = 1 / pic2_item = 1 / pic3_item = 1 </values> <list mylist> / poolsize = 9 / selectionrate = always / selectionmode = random / replace = false </counter> <expt> / onexptbegin = [values.pic1_item = list.mylist.nextindex; values.pic2_item = list.mylist.nextindex; values.pic3_item = list.mylist.nextindex; ] .... </expt> with <picture Pic1> /items = pictures /select = values.pic1_item /position = (50%, 35%) </picture> <picture Pic2> /items = pictures /select = values.pic2_item / position = (50%, 35%) </picture> <picture Pic3> /items = pictures /select = values.pic3_item / position = (50%, 35%) </picture> and same for the picture elements you use during the instructions / demo trial: ## instr_Picture <picture pic_instr_L> /items = pictures /select = values.pic1_item / position = (30%, 35%) </picture> <picture pic_instr_M> /items = pictures /select = values.pic2_item / position = (50%, 35%) </picture> <picture pic_instr_R> /items = pictures /select = values.pic3_item / position = (70%, 35%) </picture> Edited 5 Years Ago by Dave
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NaomiLee	NaomiLee posted 5 Years Ago ANSWER Post Details Share Post
Group: Forum Members Posts: 2, Visits: 2	Thank you so much that works! Sorry I am new to Inquisit and think I'd just got a bit confused trying to sort the issue out from looking on these forums.
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