Millisecond Forums

No problem. Let me know how it goes!

Thanks for this I will give it a hack so to speak

Apologies for doubling up with PM

Assuming you did something like

<expressions>
/ getlossdeck1 = sequence(0, 0, 0, 0, 0, 0, 0, 0, 0, 1250)
/ getlossdeck2 = sequence(0, 0, 0, 0, 0, 150, 200, 250, 300, 350)
/ getlossdeck3 = sequence(0, 0, 0, 0, 0, 0, 50, 50, 50, 50)
/ getlossdeck4 = sequence(0, 0, 0, 0, 0, 0, 0, 0, 0, 250)
</expressions>

there is no reason why the decks should be "in sync". If e.g. "deck 1" is selected
<trial igt>
...
/ ontrialend = [ if (trial.igt.response == "deck1") {... ; values.loss=expressions.getlossdeck1; ...}]
...
</trial>

A single sample is retrieved from expressions.getlossdeck1. The remaining expressions are (supposed to be) wholly unaffected -- no samples are retrieved.

The quickest, but somewhat hack-ish, way to change that is to retrieve a sample from *every* expression regardless of the deck chosen:

<trial igt>
...
/ ontrialend = [ if (trial.igt.response == "deck1") {... ; values.loss=expressions.getlossdeck1; expressions.getlossdeck2; expressions.getlossdeck3; expressions.getlossdeck4;...}]
/ ontrialend = [ if (trial.igt.response == "deck2") {... ; values.loss=expressions.getlossdeck2; expressions.getlossdeck1; expressions.getlossdeck3; expressions.getlossdeck4;...}]
...
</trial>

Dave

I know I'm dredging this from the mists of time but I am also trying to do a linear sequence with the iowa gambling task from the web scripts.

I have used the sequence command to select a fixed loss value and modified other elements of the script so that it only shows one value for loss gain over the card

Its 90% there but I cannot get the getlossdeck sequence to step together so that it doesn't step back when users select a different response.

i.e if they keep hitting deck A the cards are in correct sequence but if they change from deck to deck it does the decks in order but not so the sixth card in A leads to the 7th in B etc

Is there a simple way of explaining your example of counters so that I can get the existing code to step in time so to speak 

I have some code you can look at to see the modifications I've made if it would help

J

You're welcome. BTW, if you're into risk-taking card tasks, definitely check out the Columbia Card Task script available from the Inquisit Task Library.

Cheers,

~Dave

Dear Dave,

thanks for these examples and your answers. They were very helpfull. [:)]

Have a good weekend. With best wishes,

Olga

Hmm, I don't think there's much more too it. Let's do this by way of an example. Suppose you have defined a counter element:

<counter fruit>
/ items = ("apple", "banana", "cherry", "damson", "elderberry")
[...]
</counter>

Now, suppose you want to retrieve the third item from the counter, i.e. "cherry", with the getitem function. You can use that function either by way of the <expressions> element

<expressions>
/ getcherry = getitem(counter.fruit, 3)
[...]
</expressions>

or by way of Inquisit's event attributes ('/ onexptbegin', '/ onexptend', '/ onblockbegin', '/ onblockend', '/ ontrialbegin', '/ ontrialend') available at the <expt>, <block> and <trial> level

<trial getcherry>
/ ontrialbegin = [text.favoritefruit.item.1 = getitem(counter.fruit, 3)]
/ stimulusframes = [favoritefruit]
[...]
</trial>

<text favoritefruit>
[...]
</text>

and do all sorts of things with it, e.g. write it to a <text> element or to a <values> entry. Note that the item index number, i.e. the second argument of the getitem function  ( 3 for "cherry") may also be a variable. So you might as well define another <values> entry (or use anything that returns a valid numerical value) and use it as the functions argument:

<values>
/ cherryindex = 3
[...]
</values>

<expressions>

/ getcherry = getitem(counter.fruit, values.cherryindex)

[...]

</expressions>

Best wishes from a fellow Inquisit user,

~Dave

Dear Dave,

thank you so much for your help. That is indeed a very simple soultion for this probelm. [:D]

However, we are developing a new card risking task and there it would be helpful to be able to get the n-th element of a counter. Unfortunatelly there are not many examples for the usage of the function getitem in the documentation .

getitem(counter.deck, 1)

getitem(text.presenteditems, text.presenteditems.itemcount)

getitem(item.useritems, item.useritems.itemcount - 1)

Can you tell me how one would have to define "counter.deck", "text.presenteditems", or "item.useritems" so that this function is executed regularely?

Kind regards,

Olga

Okay, I had a quick look at your script and compared it to the original IGT script available from millisecond.com. Well, if all you want is a fixed sequence of losses for each deck, there's a much easier way to pull this off. In the original script, losses are randomly determined by the following expressions:

<expressions>
/ getlossdeck1 = noreplace(0, 0, 0, 0, 0, 0, 0, 0, 0, 1250)
/ getlossdeck2 = noreplace(0, 0, 0, 0, 0, 150, 200, 250, 300, 350)
/ getlossdeck3 = noreplace(0, 0, 0, 0, 0, 0, 50, 50, 50, 50)
/ getlossdeck4 = noreplace(0, 0, 0, 0, 0, 0, 0, 0, 0, 250)
</expressions>

Each time the subject selects e.g. deck1, a random value is returned from expressions.getlossdeck1 (without replacement). Now, if you want to switch that behavior to a predictable, fixed sequence in which certain amounts of losses should occur, you may simply define:

<expressions>
/ getlossdeck1 = sequence(0, 0, 0, 0, 0, 0, 0, 0, 0, 1250)
/ getlossdeck2 = sequence(0, 0, 0, 0, 0, 150, 200, 250, 300, 350)
/ getlossdeck3 = sequence(0, 0, 0, 0, 0, 0, 50, 50, 50, 50)
/ getlossdeck4 = sequence(0, 0, 0, 0, 0, 0, 0, 0, 0, 250)
</expressions>

I.e.only when the subject selects deck1 for the tenth time, a loss of 1250 will occur. No further changes are necessary as you can see from the attached script.

Let me know if that helps,

~Dave

What exactly isn't working?